Irma Kurnia Sari 122017001 Transport Fenomena.docx

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Nama : Irma Kurnia Sari Nrp

: 122017001

1. At 60℃ the surface tension of water is 0,662 N⁄m and that of mercury is 0,47 N⁄m Determine the capillary height changes in these two fluids when they are in contact with air in glass tube of diameter 0,55 mm contact angles are 0° for water and 130° for mercurry. Translate: Pada 60℃ tegangan permukaan air adalah 0,662 N⁄m dan air raksa 0,47N⁄m . Tentukan perubahan tinggi kapiler dalam dua cairan ini ketika bersentuhan dengan udara dalam tabung gelas berdiameter 0,55 mm .sudut kontak adalah 0° unntuk air dan 130° untuk merkuri. Jawab : Dik : Air (Water) : 𝜎 = 0,0662 N⁄𝑚2 𝜃 = 0° 𝜌 = 9650 𝑁⁄𝑚3 ℊ = 9,81 𝑚⁄𝑠 2 𝑑 = 0,55 𝑚𝑚 = 0,00055 𝑚 𝑟=

1 2

𝑑=

1 2

(0,00055) = 0,000275 = 2.75𝑥10−4

Air Raksa (Mercurry): 𝜎 = 0,47 N⁄𝑚2 𝜃 = 130 ° 𝜌 = 132300 𝑁⁄𝑚3 ℊ = 9,81 𝑚⁄𝑠 2 𝑑 = 0,55 𝑚𝑚 = 0,00055 𝑚 𝑟=

1 2

𝑑=

1 2

(0,00055) = 0,000275 = 2.75𝑥10−4

Dit : ℎ 𝑤𝑎𝑡𝑒𝑟 ( 𝑎𝑖𝑟) … . . ? ℎ 𝑀𝑒𝑟𝑐𝑢𝑟𝑟𝑦 ( 𝑎𝑖𝑟 𝑟𝑎𝑘𝑠𝑎)…….?

Jawab:  ℎ=

Air (Water) 2 𝜎 𝑐𝑜𝑠 𝜃 𝜌ℊ𝑟 2 (0,0662 N⁄𝑚2 ) 𝑐𝑜𝑠 0 °

ℎ=

(9650 𝑁⁄𝑚3 ) (9,81 𝑚⁄𝑠 2 ) (2.75𝑥10−4 ) 0,1324 ℎ= 26,0332 ℎ = 5,0858 𝑥 10−3 𝑚  ℎ=

Mercurry ( Air Raksa ) 2 𝜎 𝑐𝑜𝑠 𝜃 𝜌ℊ𝑟 2 (0,47 N⁄𝑚2 ) 𝑐𝑜𝑠130 °

ℎ=

(132300 𝑁⁄𝑚3 ) (9,81 𝑚⁄𝑠 2 ) (2.75𝑥10−4 ) − 0,6042 ℎ= 356,91 ℎ = −1,6928 𝑥 10−3 𝑚

2. Water in a container is originally at 100 kpa. the water is subjected to a pressure of 120 Mpa. determine the percetage decrease in its volume?. Translate : Air dalam wadah aslinya 100 kpa. air dikenakan tekanan 120 Mpa.Tentukan persentase penurunan volumenya ? Jawab : Dik : 𝑃1 = 100 kpa → 100 𝑘𝑝𝑎 𝑥 𝑃2 = 120 𝑀𝑝𝑎 Dit : % penurunan volumenya ?

0,001 𝑀𝑝𝑎 1 𝑘𝑝𝑎

= 0.1 𝑀𝑝𝑎 𝑎𝑡𝑎𝑢 𝑃1 = 0,1 𝑀𝑝𝑎

jawab : Tekanan sebelum penurunan = 𝑃2 − 𝑃1 = 120 𝑀𝑝𝑎 − 0,1 𝑀𝑝𝑎 = 119,9 𝑀𝑝𝑎 𝑡𝑒𝑘𝑎𝑛𝑎𝑛 𝑎𝑤𝑎𝑙

% penurunan volumenya = 𝑡𝑒𝑘𝑎𝑛𝑎𝑛 𝑠𝑒𝑏𝑒𝑙𝑢𝑚 𝑝𝑒𝑛𝑢𝑟𝑢𝑛𝑎𝑛 𝑥 100 = =

119,9 𝑀𝑝𝑎 120 𝑀𝑝𝑎

𝑥 100%

11990 120

= 99,91 % 3. A liquid in a cylinder has avolume of 1200 𝑐𝑚3 at 1,25 Mpa and a volume of 1188 𝑐𝑚3 at 2,50 Mpa determine its bulk modulus of elasticity ? Translate : Suatu cairan dalam sebuah silinder memiliki volume 1200 𝑐𝑚3 pada 1,25 Mpa dan volume 1188 𝑐𝑚3 pada 2,50 Mpa tentukan modulus elastisitas bulk ? Jawab : Dik : 𝑃1 = 1,25 𝑀𝑝𝑎 𝑉1 = 1200 𝑐𝑚3 𝑃2 = 2,50 𝑀𝑝𝑎 𝑉2 = 1188 𝑐𝑚3 Dit ∶ 𝐵 ( modulus elastisistas bulk ) ? jawab : − ∆𝑃 𝐵= ∆𝑉⁄ 𝑉1 − 𝑉1 ( 𝑃2 − 𝑃1 ) 𝐵= 𝑉2 − 𝑉1 −1200 𝑐𝑚3 (2,50 𝑀𝑝𝑎 − 1 ,25 𝑀𝑝𝑎) 𝐵= (1188 − 1200) 𝑐𝑚3 −1200 (1,25 𝑀𝑝𝑎) 𝐵= − 12 −1500 𝐵= − 12 𝐵 = 125 𝑀𝑝𝑎 atau 𝐵 = 125 𝑁⁄𝑚𝑚2 4. Determine the diameter of the glass tube necesssary to keep capillary- height change of water at 30°C. less than 1 mm ? Translate :

Tentukan diameter tabung gelas yang diperlukan untuk perubahan ketinggian kapiler air pada 30°C kurang dari 1 mm ? Jawab : Dik : 𝜎 = 0,0712 𝑁⁄𝑚2 𝜃 = 0° 𝜌 = 996 𝑁⁄𝑚3 ℊ = 9,81 𝑚⁄𝑠 2 ℎ = 1𝑚𝑚 →

1 𝑚𝑚 1000 𝑚𝑚

𝑥 1𝑚 = 1𝑥10−3

Dit : 𝑑 ( 𝑑𝑖𝑎𝑚𝑒𝑡𝑒𝑟 ) … . . ? jawab : ℎ=

2 𝜎 𝑐𝑜𝑠 𝜃 𝜌ℊ𝑟

𝑟=

2 𝜎 𝑐𝑜𝑠 𝜃 𝜌ℊℎ 2 (0,0712 N⁄𝑚2 ) 𝑐𝑜𝑠0 °

𝑟=

𝑘𝑔⁄ 𝑚 (1𝑥 10−3 𝑚) 𝑚3 ) (9,81 ⁄𝑠 2 ) 0,1424 𝑟= 9,7707 (996

𝑟 = 0,01457 𝑚 jadi : 𝑑 = 2𝑥 𝑟 𝑑 = 2𝑥 0,01457 𝑚 𝑑 = 0,029 𝑚

𝑎𝑡𝑎𝑢

𝑑 = 29 𝑚𝑚

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