Ip Addressing And Sub Netting Answer Book
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Solved subnetting problems In IP addressing and subnetting workbook
Version 1.1
By Muhedin Abdullahi Mohamed [email protected] Currently a postgraduate student in Univeristi Teknologi Malaysia September 2009
The workbook is available at:
http://www.pdfcoke.com/doc/20246803/IP-Addressing-Sub-Netting-Workbook
When asked a subnetting problem, you can be presented with several pieces of information that describe the situation. Given that information, it will be up to you to figure out the remaining pieces of information to solve the problem. In this document I will present solutions to problems in IP addressing and subnetting work book v1.1 which was produced by Robb Jones. In the first part of the workbook, the types of information that you must be able to identify are as follows: Information required
Value
Address class Default subnet mask Custom subnet mask Total number of subnets Number of usable subnets Total number of host addresses Number of usable addresses Number of bits borrowed Let us now commence solving the problems skipping those that were already solved as examples in the workbook.
Part1 Problem41: In this problem, the following data is given : Number of needed usable subnets: 6 Number of needed usable hosts:
30
Network Address :
210.100.56.0
For this problem the solution is Information required
Value
Address class
C
Default subnet mask
255.255.255.0
Custom subnet mask
255.255.255.224
Total number of subnets
8
Number of usable subnets
6
Total number of host addresses
32
Number of usable addresses
30
Number of bits borrowed
3
Problem5: In this problem, the following data is given: Number of needed usable subnets: 6 1
Problems 1, 2 and 3 are solved in the work book as examples.
Number of needed usable hosts:
30
Network Address:
195.85.8.0
For this problem the solution is Information required
Value
Address class
C
Default subnet mask
255.255.255.0
Custom subnet mask
255.255.255.224
Total number of subnets
8
Number of usable subnets
6
Total number of host addresses
32
Number of usable addresses
30
Number of bits borrowed
3
Problem6: In this problem, the following data is given: Number of needed usable subnets: 126 Number of needed usable hosts: Network Address:
131070 118.0.0.0
For this problem the solution Information required
Value
Address class
A
Default subnet mask
255.0.0.0
Custom subnet mask
255.254.0.0
Total number of subnets
128
Number of usable subnets
126
Total number of host addresses
131072
Number of usable addresses
131070
Number of bits borrowed
7
Problem7: In this problem, the following data is given: Number of needed usable subnets: 2000 Number of needed usable hosts:
15
Network Address:
178.100.0.0
For this problem the solution Information required
Value
Address class
B
Default subnet mask
255.255.0.0
Custom subnet mask
255.255.255.224
Total number of subnets
2048
Number of usable subnets
2046
Total number of host addresses
32
Number of usable addresses
30
Number of bits borrowed
10
Problem8: In this problem, the following data is given: Number of needed usable subnets: 1 Number of needed usable hosts: Network Address:
45 200.175.14.0
For this problem the solution Information required
Value
Address class
C
Default subnet mask
255.255.255.0
Custom subnet mask
255.255.255.192
Total number of subnets
4
Number of usable subnets
2
Total number of host addresses
64
Number of usable addresses
62
Number of bits borrowed
2
Problem9: In this problem, the following data is given: Number of needed usable subnets: 60 Number of needed usable hosts: Network Address:
1000 128.77.0.0
For this problem the solution
Information required
Value
Address class
B
Default subnet mask
255.255.0.0
Custom subnet mask
255.255.252.0
Total number of subnets
64
Number of usable subnets
62
Total number of host addresses
1024
Number of usable addresses
1022
Number of bits borrowed
6
Problem10: In this problem, the following data is given: Number of needed usable hosts: 60 Network Address:
198.100.10.0
For this problem the solution Information required
Value
Address class
C
Default subnet mask
255.255.255.0
Custom subnet mask
255.255.255.192
Total number of subnets
4
Number of usable subnets
2
Total number of host addresses
64
Number of usable addresses
62
Number of bits borrowed
2
Problem11: In this problem, the following data is given: Number of needed usable subnets: 250 Network Address:
101.0.0.0
For this problem the solution Information required
Value
Address class
A
Default subnet mask
255.0.0.0
Custom subnet mask
255.255.0.0
Total number of subnets
256
Number of usable subnets
254
Total number of host addresses
65536
Number of usable addresses
65534
Number of bits borrowed
8
Problem12: In this problem, the following data is given: Number of needed usable subnets: 5 Network Address:
218.35.50.0
For this problem the solution Information required
Value
Address class
C
Default subnet mask
255.255.255.0
Custom subnet mask
255.255.255.224
Total number of subnets
8
Number of usable subnets
6
Total number of host addresses
32
Number of usable addresses
30
Number of bits borrowed
3
Problem13:
In this problem, the following data is given: Number of needed usable hosts: 2 5 Network Address:
218.35.50.0
For this problem the solution is: Information required
Value
Address class
C
Default subnet mask
255.255.255.0
Custom subnet mask
255.255.255.224
Total number of subnets
8
Number of usable subnets
6
Total number of host addresses
32
Number of usable addresses
30
Number of bits borrowed
3
Problem14: In this problem, the following data is given: Number of needed usable subnets: 10 Network Address:
172.59.0.0
For this problem the solution is:
Information required
Value
Address class
B
Default subnet mask
255.255.0.0
Custom subnet mask
255.255.240.0
Total number of subnets
16
Number of usable subnets
14
Total number of host addresses
4096
Number of usable addresses
4094
Number of bits borrowed
4
Problem15: In this problem, the following data is given: Number of needed usable hosts: 50 Network Address:
172.59.0.0
For this problem the solution is: Information required
Value
Address class
B
Default subnet mask
255.255.0.0
Custom subnet mask
255.255.255.192
Total number of subnets
1024
Number of usable subnets
1022
Total number of host addresses
64
Number of usable addresses
62
Number of bits borrowed
10
Problem16: In this problem, the following data is given: Number of needed usable hosts: 29 Network Address: For this problem the solution is:
23.0.0.0
Information required
Value
Address class
A
Default subnet mask
255.0.0.0
Custom subnet mask
255.255.255.224
Total number of subnets
524288
Number of usable subnets
524286
Total number of host addresses
32
Number of usable addresses
30
Number of bits borrowed
19
Part2: In addition to what has been discussed so far, this section will further determine other pieces of information as the valid host ranges in given subnet as well as subnet and broadcast addresses. Like the previous section, problems 1 and 2 will be skipped for they are solved in the workbook as examples:
Problem32: In this problem, the following data is given: Number of needed usable subnets: 1 Network Address:
195.223.50.0
For this problem the solution is: Information required
Value
Address class
C
Default subnet mask
255.255.255.0
Custom subnet mask
255.255.255.192
Total number of subnets
4
Number of usable subnets
2
Total number of host addresses
64
Number of usable addresses
62
Number of bits borrowed
2
2nd usable subnet range
195.223.50.128 to 195.223.50.191
2
For problems 1 and 2 check the work book
Subnet No for 1st usable subnet
195.223.50.64
Subnet broadcast address for 1st
195.223.50.127
usable sunet Assignable addresses for the 2nd
195.223.50.129 to 195.223.50.190
usable subnet
Problem4: In this problem, the following data is given: Number of needed usable subnets: 750 Network Address:
190.35.0.0
For this problem the solution is: Information required
Value
Address class
B
Default subnet mask
255.255.0.0
Custom subnet mask
255.255.255.192
Total number of subnets
1024
Number of usable subnets
1022
Total number of host addresses
64
Number of usable addresses
62
Number of bits borrowed
10
14th usable subnet range
190.35.3.128 to 190.35.3.191
Subnet No for 12th usable subnet
190.35.3.0
Subnet broadcast address for the 9th 190.35.2.127 usable subnet Assignable addresses for the 5th
190.35.1.65 to 190.35.1.126
usable subnet
Problem5: In this problem, the following data is given: Number of needed usable hosts: 6 Network Address:
126.0.0.0
For this problem the solution is: Information required
Value
Address class
A
Default subnet mask
255.0.0.0
Custom subnet mask
255.255.255.248
Total number of subnets
2097152
Number of usable subnets
2097150
Total number of host addresses
8
Number of usable addresses
6
Number of bits borrowed
21
1st usable subnet range
126.0.0.8 to 126.0.0.15
Subnet No for 4th usable subnet
126.0.0.32
Subnet broadcast address for the 6th 126.0.0.55 usable subnet Assignable addresses for the 9th usable subnet
Problem6:
126.0.0.73 to 126.0.0.78
In this problem, the following data is given: Number of needed usable subnets: 10 Network Address:
192.70.10.0
For this problem the solution is: Information required
Value
Address class
C
Default subnet mask
255.255.255.0
Custom subnet mask
255.255.255.240
Total number of subnets
16
Number of usable subnets
14
Total number of host addresses
16
Number of usable addresses
14
Number of bits borrowed
4
8th usable subnet range
192.70.10.128 to 192.70.10.143
Subnet No for 3rd usable subnet
192.70.10.48
Subnet broadcast address for the
192.70.10.191
11th usable subnet Assignable addresses for the 9th
192.70.10.145 to 192.70.10.158
usable subnet
Problem7: In this problem, the following data is given: Network Address:
10.0.0.0/163
For this problem the solution is: 3
The prefix number (/16 ) indicates how many bits used for the network ID.
Information required
Value
Address class
A
Default subnet mask
255.0.0.0
Custom subnet mask
255.255.0.0
Total number of subnets
256
Number of usable subnets
254
Total number of host addresses
65536
Number of usable addresses
65534
Number of bits borrowed
8
10th usable subnet range
10.10.0.0 to 10.10.255.255
Subnet No for 5th usable subnet
10.5.0.0
Subnet broadcast address for the 1st 10.1.255.255 usable subnet Assignable addresses for the 8th
10.8.0.1 to 10.8.255.254
usable subnet
Problem8: In this problem, the following data is given: Number of needed usable subnets: 4 Network Address:
172.50.0.0
For this problem the solution is:
Information required
Value
Address class
B
Default subnet mask
255.255.0.0
Custom subnet mask
255.255.224.0
Total number of subnets
8
Number of usable subnets
6
Total number of host addresses
8192
Number of usable addresses
8190
Number of bits borrowed
3
3rd usable subnet range
172.50.96.0 to
Subnet No for 4th usable subnet
172.50.128.0
172.50.127.255
Subnet broadcast address for the 5th 172.50.191.255 usable subnet Assignable addresses for the 2nd
172.50.64.1 to 172.50.95.254
usable subnet
Problem9: In this problem, the following data is given: Number of needed usable hosts:
28
Network Address:
172.50.0.0
For this problem the solution is: Information required
Value
Address class
B
Default subnet mask
255.255.0.0
Custom subnet mask
255.255.255.224
Total number of subnets
2048
Number of usable subnets
2046
Total number of host addresses
32
Number of usable addresses
30
Number of bits borrowed
11
1st
172.50.0.32
usable subnet range
Subnet No for 9th usable subnet
to
172.50.0.63
172.50.1.32
Subnet broadcast address for the 3rd 172.50.0.127 usable subnet Assignable addresses for the 5th
172.50.0.161 to 172.50.0.190
usable subnet
Problem10: In this problem, the following data is given: Number of needed usable subnets: Network Address:
45 220.100.100.0
For this problem the solution is: Information required
Value
Address class
C
Default subnet mask
255.255.255.0
Custom subnet mask
255.255.255.252
Total number of subnets
64
Number of usable subnets
62
Total number of host addresses
4
Number of usable addresses
2
Number of bits borrowed
6
4th usable subnet range
220.100.100.16
Subnet No for 3rd usable subnet
220.100.100.12
Subnet broadcast address for the
220.100.100.51
to
220.100.100.19
12th usable subnet Assignable addresses for the 11th
220.100.100.45 to 220.100.100.46
usable subnet
Problem11: In this problem, the following data is given: Number of needed usable hosts:
8000
Network Address:
135.70.0.0
For this problem the solution is:
Information required
Value
Address class
B
Default subnet mask
255.255.0.0
Custom subnet mask
255.255.252.0
Total number of subnets
8
Number of usable subnets
6
Total number of host addresses
8192
Number of usable addresses
8190
Number of bits borrowed
3
5th usable subnet range
135.70.160.0
Subnet No for 6th
135.70.192.0
usable subnet
Subnet broadcast address for the
to
135.70.191.255
to
135.70.159.254
135.70.95.255
2nd usable subnet Assignable addresses for the 4th usable subnet
135.70.128.1
Problem12: In this problem, the following data is given: Number of needed usable hosts: Network Address:
45 198.125.50.0
For this problem the solution is: Information required
Value
Address class
C
Default subnet mask
255.255.255.0
Custom subnet mask
255.255.252.192
Total number of subnets
4
Number of usable subnets
2
Total number of host addresses
64
Number of usable addresses
62
Number of bits borrowed
2
1st usable subnet range
198.125.50.64
Subnet No for 1st
198.125.50.64
usable subnet
Subnet broadcast address for the
to 198. 125.50.127
198.125.50.191
2nd usable subnet Assignable addresses for the 2nd
198.125.50.129
usable subnet
Problem13: In this problem, the following data is given: Network Address:
165.200.0.0/26
to 198.125.50.190
For this problem the solution is:
Information required
Value
Address class
B
Default subnet mask
255.255.0.0
Custom subnet mask
255.255.252.192
Total number of subnets
1024
Number of usable subnets
1022
Total number of host addresses
64
Number of usable addresses
62
Number of bits borrowed
10
9th
165.200.2.64
usable subnet range
Subnet No for 10th
to 165.200.2.127
165.200.2.128
usable subnet
165.200.255.127
Subnet broadcast address for the 1022nd usable subnet Assignable addresses for the 1021st
165.200.255.1
usable subnet
Problem14: In this problem, the following data is given: Number of needed usable hosts: Network Address:
16 200.10.10.0
For this problem the solution is:
Information required
Value
to 165.200.255.254
Address class
C
Default subnet mask
255.255.255.0
Custom subnet mask
255.255.252.224
Total number of subnets
8
Number of usable subnets
6
Total number of host addresses
32
Number of usable addresses
30
Number of bits borrowed
3
6th
200.10.10.192
usable subnet range
Subnet No for 4th
usable subnet
to 200.10.10.223
200.10.10.128
Subnet broadcast address for the 3rd 200.10.10.127 usable subnet Assignable addresses for the 5th
200.10.10.161
usable subnet
Problem15: In this problem, the following data is given: Network Address:
93.0.0.0/19
For this problem the solution is:
Information required
Value
Address class
A
Default subnet mask
255.0.0.0
Custom subnet mask
255.255..224.0
Total number of subnets
2048
to 200.10.10.190
Number of usable subnets
2046
Total number of host addresses
8192
Number of usable addresses
8190
Number of bits borrowed
11
14th
93.1.192.0
usable subnet range
Subnet No for 8th
usable subnet
to 93.1.223.255
93.1.0.0
Subnet broadcast address for the 6th 93.0.223.255 usable subnet Assignable addresses for the 11th
93.1.96.1
to 93.1.127.254
usable subnet
Conclusions: It is worth mentioning that this work is done as part of my assignments during the normal study of CCNA1 course. I therefore apologize you for any mistakes done. Your corrections and suggestions (if any) are welcomed at [email protected]/[email protected]
All thanks to Allah. Thank you too.
Version 1.1
By Muhedin Abdullahi Mohamed [email protected] Currently a postgraduate student in Univeristi Teknologi Malaysia September 2009
The workbook is available at:
http://www.pdfcoke.com/doc/20246803/IP-Addressing-Sub-Netting-Workbook
When asked a subnetting problem, you can be presented with several pieces of information that describe the situation. Given that information, it will be up to you to figure out the remaining pieces of information to solve the problem. In this document I will present solutions to problems in IP addressing and subnetting work book v1.1 which was produced by Robb Jones. In the first part of the workbook, the types of information that you must be able to identify are as follows: Information required
Value
Address class Default subnet mask Custom subnet mask Total number of subnets Number of usable subnets Total number of host addresses Number of usable addresses Number of bits borrowed Let us now commence solving the problems skipping those that were already solved as examples in the workbook.
Part1 Problem41: In this problem, the following data is given : Number of needed usable subnets: 6 Number of needed usable hosts:
30
Network Address :
210.100.56.0
For this problem the solution is Information required
Value
Address class
C
Default subnet mask
255.255.255.0
Custom subnet mask
255.255.255.224
Total number of subnets
8
Number of usable subnets
6
Total number of host addresses
32
Number of usable addresses
30
Number of bits borrowed
3
Problem5: In this problem, the following data is given: Number of needed usable subnets: 6 1
Problems 1, 2 and 3 are solved in the work book as examples.
Number of needed usable hosts:
30
Network Address:
195.85.8.0
For this problem the solution is Information required
Value
Address class
C
Default subnet mask
255.255.255.0
Custom subnet mask
255.255.255.224
Total number of subnets
8
Number of usable subnets
6
Total number of host addresses
32
Number of usable addresses
30
Number of bits borrowed
3
Problem6: In this problem, the following data is given: Number of needed usable subnets: 126 Number of needed usable hosts: Network Address:
131070 118.0.0.0
For this problem the solution Information required
Value
Address class
A
Default subnet mask
255.0.0.0
Custom subnet mask
255.254.0.0
Total number of subnets
128
Number of usable subnets
126
Total number of host addresses
131072
Number of usable addresses
131070
Number of bits borrowed
7
Problem7: In this problem, the following data is given: Number of needed usable subnets: 2000 Number of needed usable hosts:
15
Network Address:
178.100.0.0
For this problem the solution Information required
Value
Address class
B
Default subnet mask
255.255.0.0
Custom subnet mask
255.255.255.224
Total number of subnets
2048
Number of usable subnets
2046
Total number of host addresses
32
Number of usable addresses
30
Number of bits borrowed
10
Problem8: In this problem, the following data is given: Number of needed usable subnets: 1 Number of needed usable hosts: Network Address:
45 200.175.14.0
For this problem the solution Information required
Value
Address class
C
Default subnet mask
255.255.255.0
Custom subnet mask
255.255.255.192
Total number of subnets
4
Number of usable subnets
2
Total number of host addresses
64
Number of usable addresses
62
Number of bits borrowed
2
Problem9: In this problem, the following data is given: Number of needed usable subnets: 60 Number of needed usable hosts: Network Address:
1000 128.77.0.0
For this problem the solution
Information required
Value
Address class
B
Default subnet mask
255.255.0.0
Custom subnet mask
255.255.252.0
Total number of subnets
64
Number of usable subnets
62
Total number of host addresses
1024
Number of usable addresses
1022
Number of bits borrowed
6
Problem10: In this problem, the following data is given: Number of needed usable hosts: 60 Network Address:
198.100.10.0
For this problem the solution Information required
Value
Address class
C
Default subnet mask
255.255.255.0
Custom subnet mask
255.255.255.192
Total number of subnets
4
Number of usable subnets
2
Total number of host addresses
64
Number of usable addresses
62
Number of bits borrowed
2
Problem11: In this problem, the following data is given: Number of needed usable subnets: 250 Network Address:
101.0.0.0
For this problem the solution Information required
Value
Address class
A
Default subnet mask
255.0.0.0
Custom subnet mask
255.255.0.0
Total number of subnets
256
Number of usable subnets
254
Total number of host addresses
65536
Number of usable addresses
65534
Number of bits borrowed
8
Problem12: In this problem, the following data is given: Number of needed usable subnets: 5 Network Address:
218.35.50.0
For this problem the solution Information required
Value
Address class
C
Default subnet mask
255.255.255.0
Custom subnet mask
255.255.255.224
Total number of subnets
8
Number of usable subnets
6
Total number of host addresses
32
Number of usable addresses
30
Number of bits borrowed
3
Problem13:
In this problem, the following data is given: Number of needed usable hosts: 2 5 Network Address:
218.35.50.0
For this problem the solution is: Information required
Value
Address class
C
Default subnet mask
255.255.255.0
Custom subnet mask
255.255.255.224
Total number of subnets
8
Number of usable subnets
6
Total number of host addresses
32
Number of usable addresses
30
Number of bits borrowed
3
Problem14: In this problem, the following data is given: Number of needed usable subnets: 10 Network Address:
172.59.0.0
For this problem the solution is:
Information required
Value
Address class
B
Default subnet mask
255.255.0.0
Custom subnet mask
255.255.240.0
Total number of subnets
16
Number of usable subnets
14
Total number of host addresses
4096
Number of usable addresses
4094
Number of bits borrowed
4
Problem15: In this problem, the following data is given: Number of needed usable hosts: 50 Network Address:
172.59.0.0
For this problem the solution is: Information required
Value
Address class
B
Default subnet mask
255.255.0.0
Custom subnet mask
255.255.255.192
Total number of subnets
1024
Number of usable subnets
1022
Total number of host addresses
64
Number of usable addresses
62
Number of bits borrowed
10
Problem16: In this problem, the following data is given: Number of needed usable hosts: 29 Network Address: For this problem the solution is:
23.0.0.0
Information required
Value
Address class
A
Default subnet mask
255.0.0.0
Custom subnet mask
255.255.255.224
Total number of subnets
524288
Number of usable subnets
524286
Total number of host addresses
32
Number of usable addresses
30
Number of bits borrowed
19
Part2: In addition to what has been discussed so far, this section will further determine other pieces of information as the valid host ranges in given subnet as well as subnet and broadcast addresses. Like the previous section, problems 1 and 2 will be skipped for they are solved in the workbook as examples:
Problem32: In this problem, the following data is given: Number of needed usable subnets: 1 Network Address:
195.223.50.0
For this problem the solution is: Information required
Value
Address class
C
Default subnet mask
255.255.255.0
Custom subnet mask
255.255.255.192
Total number of subnets
4
Number of usable subnets
2
Total number of host addresses
64
Number of usable addresses
62
Number of bits borrowed
2
2nd usable subnet range
195.223.50.128 to 195.223.50.191
2
For problems 1 and 2 check the work book
Subnet No for 1st usable subnet
195.223.50.64
Subnet broadcast address for 1st
195.223.50.127
usable sunet Assignable addresses for the 2nd
195.223.50.129 to 195.223.50.190
usable subnet
Problem4: In this problem, the following data is given: Number of needed usable subnets: 750 Network Address:
190.35.0.0
For this problem the solution is: Information required
Value
Address class
B
Default subnet mask
255.255.0.0
Custom subnet mask
255.255.255.192
Total number of subnets
1024
Number of usable subnets
1022
Total number of host addresses
64
Number of usable addresses
62
Number of bits borrowed
10
14th usable subnet range
190.35.3.128 to 190.35.3.191
Subnet No for 12th usable subnet
190.35.3.0
Subnet broadcast address for the 9th 190.35.2.127 usable subnet Assignable addresses for the 5th
190.35.1.65 to 190.35.1.126
usable subnet
Problem5: In this problem, the following data is given: Number of needed usable hosts: 6 Network Address:
126.0.0.0
For this problem the solution is: Information required
Value
Address class
A
Default subnet mask
255.0.0.0
Custom subnet mask
255.255.255.248
Total number of subnets
2097152
Number of usable subnets
2097150
Total number of host addresses
8
Number of usable addresses
6
Number of bits borrowed
21
1st usable subnet range
126.0.0.8 to 126.0.0.15
Subnet No for 4th usable subnet
126.0.0.32
Subnet broadcast address for the 6th 126.0.0.55 usable subnet Assignable addresses for the 9th usable subnet
Problem6:
126.0.0.73 to 126.0.0.78
In this problem, the following data is given: Number of needed usable subnets: 10 Network Address:
192.70.10.0
For this problem the solution is: Information required
Value
Address class
C
Default subnet mask
255.255.255.0
Custom subnet mask
255.255.255.240
Total number of subnets
16
Number of usable subnets
14
Total number of host addresses
16
Number of usable addresses
14
Number of bits borrowed
4
8th usable subnet range
192.70.10.128 to 192.70.10.143
Subnet No for 3rd usable subnet
192.70.10.48
Subnet broadcast address for the
192.70.10.191
11th usable subnet Assignable addresses for the 9th
192.70.10.145 to 192.70.10.158
usable subnet
Problem7: In this problem, the following data is given: Network Address:
10.0.0.0/163
For this problem the solution is: 3
The prefix number (/16 ) indicates how many bits used for the network ID.
Information required
Value
Address class
A
Default subnet mask
255.0.0.0
Custom subnet mask
255.255.0.0
Total number of subnets
256
Number of usable subnets
254
Total number of host addresses
65536
Number of usable addresses
65534
Number of bits borrowed
8
10th usable subnet range
10.10.0.0 to 10.10.255.255
Subnet No for 5th usable subnet
10.5.0.0
Subnet broadcast address for the 1st 10.1.255.255 usable subnet Assignable addresses for the 8th
10.8.0.1 to 10.8.255.254
usable subnet
Problem8: In this problem, the following data is given: Number of needed usable subnets: 4 Network Address:
172.50.0.0
For this problem the solution is:
Information required
Value
Address class
B
Default subnet mask
255.255.0.0
Custom subnet mask
255.255.224.0
Total number of subnets
8
Number of usable subnets
6
Total number of host addresses
8192
Number of usable addresses
8190
Number of bits borrowed
3
3rd usable subnet range
172.50.96.0 to
Subnet No for 4th usable subnet
172.50.128.0
172.50.127.255
Subnet broadcast address for the 5th 172.50.191.255 usable subnet Assignable addresses for the 2nd
172.50.64.1 to 172.50.95.254
usable subnet
Problem9: In this problem, the following data is given: Number of needed usable hosts:
28
Network Address:
172.50.0.0
For this problem the solution is: Information required
Value
Address class
B
Default subnet mask
255.255.0.0
Custom subnet mask
255.255.255.224
Total number of subnets
2048
Number of usable subnets
2046
Total number of host addresses
32
Number of usable addresses
30
Number of bits borrowed
11
1st
172.50.0.32
usable subnet range
Subnet No for 9th usable subnet
to
172.50.0.63
172.50.1.32
Subnet broadcast address for the 3rd 172.50.0.127 usable subnet Assignable addresses for the 5th
172.50.0.161 to 172.50.0.190
usable subnet
Problem10: In this problem, the following data is given: Number of needed usable subnets: Network Address:
45 220.100.100.0
For this problem the solution is: Information required
Value
Address class
C
Default subnet mask
255.255.255.0
Custom subnet mask
255.255.255.252
Total number of subnets
64
Number of usable subnets
62
Total number of host addresses
4
Number of usable addresses
2
Number of bits borrowed
6
4th usable subnet range
220.100.100.16
Subnet No for 3rd usable subnet
220.100.100.12
Subnet broadcast address for the
220.100.100.51
to
220.100.100.19
12th usable subnet Assignable addresses for the 11th
220.100.100.45 to 220.100.100.46
usable subnet
Problem11: In this problem, the following data is given: Number of needed usable hosts:
8000
Network Address:
135.70.0.0
For this problem the solution is:
Information required
Value
Address class
B
Default subnet mask
255.255.0.0
Custom subnet mask
255.255.252.0
Total number of subnets
8
Number of usable subnets
6
Total number of host addresses
8192
Number of usable addresses
8190
Number of bits borrowed
3
5th usable subnet range
135.70.160.0
Subnet No for 6th
135.70.192.0
usable subnet
Subnet broadcast address for the
to
135.70.191.255
to
135.70.159.254
135.70.95.255
2nd usable subnet Assignable addresses for the 4th usable subnet
135.70.128.1
Problem12: In this problem, the following data is given: Number of needed usable hosts: Network Address:
45 198.125.50.0
For this problem the solution is: Information required
Value
Address class
C
Default subnet mask
255.255.255.0
Custom subnet mask
255.255.252.192
Total number of subnets
4
Number of usable subnets
2
Total number of host addresses
64
Number of usable addresses
62
Number of bits borrowed
2
1st usable subnet range
198.125.50.64
Subnet No for 1st
198.125.50.64
usable subnet
Subnet broadcast address for the
to 198. 125.50.127
198.125.50.191
2nd usable subnet Assignable addresses for the 2nd
198.125.50.129
usable subnet
Problem13: In this problem, the following data is given: Network Address:
165.200.0.0/26
to 198.125.50.190
For this problem the solution is:
Information required
Value
Address class
B
Default subnet mask
255.255.0.0
Custom subnet mask
255.255.252.192
Total number of subnets
1024
Number of usable subnets
1022
Total number of host addresses
64
Number of usable addresses
62
Number of bits borrowed
10
9th
165.200.2.64
usable subnet range
Subnet No for 10th
to 165.200.2.127
165.200.2.128
usable subnet
165.200.255.127
Subnet broadcast address for the 1022nd usable subnet Assignable addresses for the 1021st
165.200.255.1
usable subnet
Problem14: In this problem, the following data is given: Number of needed usable hosts: Network Address:
16 200.10.10.0
For this problem the solution is:
Information required
Value
to 165.200.255.254
Address class
C
Default subnet mask
255.255.255.0
Custom subnet mask
255.255.252.224
Total number of subnets
8
Number of usable subnets
6
Total number of host addresses
32
Number of usable addresses
30
Number of bits borrowed
3
6th
200.10.10.192
usable subnet range
Subnet No for 4th
usable subnet
to 200.10.10.223
200.10.10.128
Subnet broadcast address for the 3rd 200.10.10.127 usable subnet Assignable addresses for the 5th
200.10.10.161
usable subnet
Problem15: In this problem, the following data is given: Network Address:
93.0.0.0/19
For this problem the solution is:
Information required
Value
Address class
A
Default subnet mask
255.0.0.0
Custom subnet mask
255.255..224.0
Total number of subnets
2048
to 200.10.10.190
Number of usable subnets
2046
Total number of host addresses
8192
Number of usable addresses
8190
Number of bits borrowed
11
14th
93.1.192.0
usable subnet range
Subnet No for 8th
usable subnet
to 93.1.223.255
93.1.0.0
Subnet broadcast address for the 6th 93.0.223.255 usable subnet Assignable addresses for the 11th
93.1.96.1
to 93.1.127.254
usable subnet
Conclusions: It is worth mentioning that this work is done as part of my assignments during the normal study of CCNA1 course. I therefore apologize you for any mistakes done. Your corrections and suggestions (if any) are welcomed at [email protected]/[email protected]
All thanks to Allah. Thank you too.
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