Ice puck v1f= v1i(2m1)/(m1+m2) v1f = 5.46(0.9)/(1.4) v1f = 6.87 m/s east v2f = v1i(m1-m2)/(m1+m2) v2f = 5.46(-0.5)/(1.4) v2f = 3.822 m/s west 90-degree collision Momentum of car 1 p1 = m1 *v1 = 1500 *25 = 3.75 *104 kg-m/s towards north Momentum of car 2 p1 = m1 *v1 = 1500 *15 = 2.25 *104 kg-m/s towards east Resultant momentum p = √(p12+ p22 + 2 * p1 * p2 * cos α) since α (angle between p1and p2) = 90 p = √(p12 + p22) p = √{(3.752 + 2.252 )*108} = 4.37 *104 kg-m/s