Conversion of gas calorific value Hi to normal conditions H0 (0°C, 1 atm): 273.15 + t ( o C) 1.01325 H0 = Hi ⋅ ⋅ 273.15 p (bar)
Example:
Given by the supplier: 10000 kcal/m3 (20°C, 1 bar)
Ho = 10000. 273.15 +20 . 1.01325 273.15 1
= 10847.4001 kcal/Nm3
Conversion of normal gas calorific value H0 (0°C, 1 atm) to gas calorific value at other conditions Hi: Hi = H0 ⋅
Example:
273.15 p (bar) ⋅ o 273.15 + t ( C) 1.01325 10000 kcal/Nm3 at 25°C and 1.5 bar?
. Hi = 10000. 273.15 . 1.5 = 13562.54 kcal/m3 273.15 +25 1.01325