Free Pythagoras' Theorem Tutorial

Pyth ag ora s’ Theore m PYTHAGORAS’ THEOREM CONCEPT

PYTHAGORAS’ THEOREM EXERCISE

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• I named this teaching aid as Pythagoras’ Theorem Tutorial. • Using Microsoft PowerPoint, because it is very user friendly; many teachers know using Microsoft PowerPoint, so teacher can using and manage without any difficulties and this also allow teachers make any changes in the content or if they want to put more added value. • Please use mouse by click it for next preview during run this teaching aid

• This teaching aid has two parts; Pythagoras’ Theorem Concept and Pythagoras’ Theorem Exercise • Pythagoras’ Theorem Concept. I choose the relationship between every side in right-angled triangle to explain and show how to use the Pythagoras’ Theorem formula. This is very important because student will more understand the Pythagoras’ Theorem and remember it. • Pythagoras’ Theorem Exercise. This exercise have two set, the first set is more easy compare to another. The exercise also design complete with time mode, sounds and animations of right or wrong answer. This part is computer interactive and very interesting for teachers use in the classroom and for students uses it individually. HOME

Pythagor as’ T heor em Concept Involved right-angled triangle (90°)

hy po ten

us e

90°

Side which apposite with the right angle called as hypotenuse. This is the longest side.

The formula that will be use to find hypotenuse value is ;

a2 = b2 + c2 How does this formula derived from?

When a square build at every sides, the biggest square area is equal with addition of other both squares area.

90°

a c 90° b

c

a

c2 90° c

This red square area is c x c = c2

b

a c 90°

b2 This yellow square area is b x b = b2 b

b

The area of this square is equal with addition of both red square area and yellow square area (a2 = b2 + c2)

a c 90° b

a c 90° b

From the equation a2 = b2 + c2, hypotenuse value or a can be fined by using a =√ b 2 + c2

a c 90° b

b

For example, let say c = 3, b = 4, so the hypotenuse value or a can find by use the formula

a c 90° b From the equation

a2 = b2 + c2 a2 = 42 + 32 a2 = 16 + 9 a2 = 25 a = √25 a=5 HOME

YOU ARE GIVEN LIMITED TIME TO SOLVE EVERY QUESTION

Click the question number SET 1

SET 2

QUESTION 1

QUESTION 1

QUESTION 2

QUESTION 2

QUESTION 3

QUESTION 3

QUESTION 4

QUESTION 4

QUESTION 5

QUESTION 5

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Click the right answer QUESTION 1

Click the right-angled triangle

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Click the right answer QUESTION 2

Click the hypotenuses

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Click the right answer QUESTION 3

Choose the right relationship between the length of the sides of the following right-angled triangles x

z y a) y2 = x2 - z2 b) x2 = y2 + z2 c) z2 = y2 + x2 d) y2 = x2 + z2 Next Question

Click the right answer QUESTION 4

Choose the right relationship between the length of the sides of the following right-angled triangles c

a

b

a) b2 = a2 + c2 b) c2 = b2 + a2 c) a2 = b2 + c2 d) c2 = a2 - b2 Next Question

Click the right answer QUESTION 5

Find the length of QS if length PR is 6 Q

P

R

5 a) 4 S b) 7 c) 5 d) 8 Next Question

Click the right answer QUESTION 1

Let say c = 16, b = 8, so the hypotenuse value or a is.. b 90° a

c

a) 17.89 b) 24 c) 18.86 d) 19.89

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Click the right answer QUESTION 2

Sides of a right-angled triangle are 256 cm dan 625 cm. But the length of side noted as a is unknown yet. Find the length 256 cm 90°

a

625 cm

a) 562 cm b) 369 cm c) 570.17 cm d) 562.69 cm

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Click the right answer QUESTION 3

Find value of X

6

90°

x

4

a) 16 b) 10 c) 10.67 d) 5

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Click the right answer QUESTION 4

Hanafiah plan to renovate his house, and need to know the length of mn on his house’s roof. Help him to find the length. n

90° m

3m

7m

a) 11.26 m b) 8.62 m c) 10 m d) 7.62 m

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Click the right answer QUESTION 5

Sakinah walk along 25 meter from her house to Mardhiah’s house. After that, she walk again along 13 meter to a shop. If angle from Sakinah’s house and the shop is right angle, How long the distance of Sakinah’s house and the shop? Sakinah’s house

a) 27.18 m b) 38 m

90° Shop

c) 28.18 m d) 28.81 m

Mardhiah’s house

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