Formulario.docx
This document was uploaded by user and they confirmed that they have the permission to share it. If you are author or own the copyright of this book, please report to us by using this DMCA report form. Report DMCA
Overview
Download & View Formulario.docx as PDF for free.
More details
- Words: 263
- Pages: 1
Boyle
Densidad π1 π1 = π2 π2 π = ππ‘π, πΌπ ππ‘ππππ
Charles
π= Numero de moles
π1 π2 = π1 π2 π = ππ‘π, πΌπ πππππππ Gay-Lussac
π π ππ = π π π
π ππ ππ‘ = ππΏ + ππΎ π1 %πππ = (100) ππ‘ π=
Dalton π1 π2 = π1 π2 π = ππ‘π, πΌπ πππππππ
Combinada
ππ‘ = π1 + π2 + β― ππ π1 π1 = = π₯1 ππ‘ ππ‘ π1 = ππ‘ π₯1 Amagat
π1 π1 π2 π2 = π1 π2
General de los gases
ππ‘ = π1 + π2 + β― ππ π1 π1 = ππ‘ ππ‘ π1 π1 (100) = (100) β %π£ππ = %πππ ππ‘ ππ‘ %π£ππ β %πππ π π€1 %πππ π = (100) π€2 Graham
ππ = ππ π ππ π π= π ππ π π= π ππ π= ππ ππ π= π π Constante R
π1 βπ2 βππ2 = = π2 βπ1 βππ1 3π π ππ 3 πΈπ = π π 2
π=β
Van Der Waals ππ‘π π π = 0.08205 πππ π πππ»π ππ3 π = 62358 πππ π ππ 3 2 ππ‘ π = 10.73 ππ ππ πππ π πππ π = 8.314π₯107 πππ π π½ π = 8.314 πππ πΎ πππ R = 1.987 πππ πΎ π΅ππ R = 1.987 ππ πππ π
π2 π ) (π β ππ) = ππ π π 27π 2 ππ2 ππ‘π π 2 π= [=] 64ππ πππ 2 π ππ π π= [=] 8ππ πππ (π +
Berthelot 9πππ 6ππ2 ππ = ππ π [1 + (1 β 2 )] 128ππ π π ππ ππ = π§ππ π β π§ = ππ π π§πππππ = 1 π§ππππ β 1
Densidad π1 π1 = π2 π2 π = ππ‘π, πΌπ ππ‘ππππ
Charles
π= Numero de moles
π1 π2 = π1 π2 π = ππ‘π, πΌπ πππππππ Gay-Lussac
π π ππ = π π π
π ππ ππ‘ = ππΏ + ππΎ π1 %πππ = (100) ππ‘ π=
Dalton π1 π2 = π1 π2 π = ππ‘π, πΌπ πππππππ
Combinada
ππ‘ = π1 + π2 + β― ππ π1 π1 = = π₯1 ππ‘ ππ‘ π1 = ππ‘ π₯1 Amagat
π1 π1 π2 π2 = π1 π2
General de los gases
ππ‘ = π1 + π2 + β― ππ π1 π1 = ππ‘ ππ‘ π1 π1 (100) = (100) β %π£ππ = %πππ ππ‘ ππ‘ %π£ππ β %πππ π π€1 %πππ π = (100) π€2 Graham
ππ = ππ π ππ π π= π ππ π π= π ππ π= ππ ππ π= π π Constante R
π1 βπ2 βππ2 = = π2 βπ1 βππ1 3π π ππ 3 πΈπ = π π 2
π=β
Van Der Waals ππ‘π π π = 0.08205 πππ π πππ»π ππ3 π = 62358 πππ π ππ 3 2 ππ‘ π = 10.73 ππ ππ πππ π πππ π = 8.314π₯107 πππ π π½ π = 8.314 πππ πΎ πππ R = 1.987 πππ πΎ π΅ππ R = 1.987 ππ πππ π
π2 π ) (π β ππ) = ππ π π 27π 2 ππ2 ππ‘π π 2 π= [=] 64ππ πππ 2 π ππ π π= [=] 8ππ πππ (π +
Berthelot 9πππ 6ππ2 ππ = ππ π [1 + (1 β 2 )] 128ππ π π ππ ππ = π§ππ π β π§ = ππ π π§πππππ = 1 π§ππππ β 1
More Documents from "Yamile Yael Hilario"
Formulario.docx
November 2019 8
Q2p2.docx
June 2020 6
Violecia.docx
November 2019 13
Trabaja En Linea Con Ol-workspace
June 2020 19
