Formula P1 V1= P2 V2
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Un cilindro de 50L de gas nitrogeno a una presion inicial de 21.5Atm se conecta a un tanque rigido y vacio. La presion final del sistema cilindro tanque es de 1.55Atm ¿Cuáll es el volumen del tanque si el proceso fue isotermico?
P1 v1= p2 v2 21.5Atm 50L =1.55Atm (50L+v2)
Formula P1 v1= p2 v2
1075Atm L = 50L+v2 1075Atm L/1.55Atm = 50L+v2
693.5483 L = 50L+v2 50L+v2 = 693.5483L V2 = 693.5483L – 50L V2 = 643.5483L
Datos p1= 21.5 Atm V1= 50L P2=1.55Atm V2= 50L+v2
P1 v1= p2 v2 21.5Atm 50L =1.55Atm (50L+v2)
Formula P1 v1= p2 v2
1075Atm L = 50L+v2 1075Atm L/1.55Atm = 50L+v2
693.5483 L = 50L+v2 50L+v2 = 693.5483L V2 = 693.5483L – 50L V2 = 643.5483L
Datos p1= 21.5 Atm V1= 50L P2=1.55Atm V2= 50L+v2
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