Finding stationary points Step 1 Starting with π¦ = π (π₯) differentiate it twice to get
ππ¦ ππ₯
and
π2 π¦ ππ₯ 2
.
Step 2 ππ¦
Solve
ππ₯
=0.
Step 3 π2 π¦
For each x value found in Step 2, find the value of y, and the sign of ππ₯ 2 (find whether the second derivative is greater than zero, less than zero or equal to zero). Step 4 If If If
π2 π¦ ππ₯ 2 π2 π¦ ππ₯ 2 π2 π¦ ππ₯ 2
> 0, you have a minimum point. < 0, you have a maximum point. = 0, then it could be a minimum, maximum or a point of inflection. Go to Step 5.
Otherwise, go to Step 6. Step 5 π3 π¦
Find the third derivative: ππ₯ 3 . If If
π2 π¦ ππ₯ 2 π2 π¦ ππ₯ 2
= 0 and
π3 π¦ ππ₯ 3
β 0, then you have a point of inflection.
π3 π¦
= 0 andππ₯ 3 = 0, then check the gradient either side of the x value.
Step 6 If required, sketch the curve. Remember: a. the first derivative tells us where the stationary point is; b. the second (and possibly third) derivative tells us what type the stationary point is.
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