Exp 4

  • Uploaded by: 3a2d
  • 0
  • 0
  • April 2020
  • PDF

This document was uploaded by user and they confirmed that they have the permission to share it. If you are author or own the copyright of this book, please report to us by using this DMCA report form. Report DMCA


Overview

Download & View Exp 4 as PDF for free.

More details

  • Words: 346
  • Pages: 5
Electric lab

: Objective To learn using the new method to solve the -1 .complex circuit .This method a-thevenin equivalent -2 . b-Norton equivalent circuit . Measure the maximum power transfer -3 To learn use the decade -4 . resistor box Using the pspice program until paint the circuit -5 .and works the simulate : Theory : thevenin equivalent-1 Vth =Vo.c (measure about method mesh ( Or nodal Rth = Req (whine put place the power .( Supply short circuit VL

Vth* =

: Norton equivalent circuit -2 IN=Is.c (measure about method .( Loop mesh Rth = Req

Electric lab

= IL : maximum power transfer-3 Rth=Req=RL Vth=Vo.c Pmax =Vth2/4Rth=Rn*In2/4 (Vo.c/2(*(Is.c/2(= ;( Result and digrams (data of table :Table 1 Equivalent voltage

Equivalent resistance

(V(

(Ω (

Equivalent (current(Isc (mA(

measure d

calculate d

measured

calculated

measure d

calculat ed

:Table 2 Load voltage

Load current

(V(

(A(

Measured

Calculated

Measured

Calculated

:Table 3 Equivalent (current(Isc (A ( measur ed

Equivalent resistance (Ω(

calculate d

measure d

calculat ed

Load voltage (V( measur ed

Load current (A(

calculat ed

measur ed

calculat ed

Electric lab

:Table 3 decade (resistance(Ω

(Load voltage (V

(Load current (mA

100 200 300 400 500 600 700 1k 1.5k 2k 2.1k 2.2K 2.3k 2.4k 2.5k

:Calculation : Using nodal 0+

=

Vth=18.71v : using loop 6.8k *I1( +(1k*I1(-(1k*I2(-20=0( +10 (7.8k*I1 -1k*I2 =10………..(1

(Load power (mW

Electric lab

(1k*I1(+(1k*I2(=0…………(2(-20 (Equation (1(+(2 I1=-10/6.8k =-1.47mA I2=1k*-1.47mA-20=-21.47mA Calculate the Rth Rth =Req=(6.8k*1k(/(6.8k+1k( =871 Ω Pmax=Vth2/4Rth Pmax=18.712/4*871 mW 100=

: Question Plot the power delivered to the load versus the load(1 resistance RL .whate is the value of Rload that draws the ? maximum power from the source 89 .3

Electric lab

exist large differences because the connecting (2 . to loss the voltage in the earth

: Conclusion the method of Norton is similar tom the method -1 .of thevenin thevenin theorem is an important tool in the-2 . solution of complex networks the equivalent circuit consist of an independent-3 . voltage source calculate the maximum power transfer whine Rth -4 . equal RL only

Related Documents

Exp 4
May 2020 17
Exp 4
April 2020 15
Exp 4 Chm556.docx
June 2020 19
Previoo Exp 4 Liq.docx
April 2020 6
Biod Exp 4
May 2020 8
Exp 4 Phy 524
June 2020 13

More Documents from ""

Experiement 4
April 2020 3
Exp 2
April 2020 9
Experiement 10
April 2020 8
Experiement 2
April 2020 11
Ex 8
April 2020 12
Circ 1ch15
April 2020 8