Exercise 2
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1237.5 ft
V1
A
O
R1
α V2
ft 10230
β
B α
Φ
2 3 1
V4
C
R2
V3
F
V5
α
D E
X
ft 7590
μ
Y = 7590 – 2 * R
Y
W
Z = 2* R = 5729 ft
W = ( 1861 ^ 2+ 5729 ^ 2)^0.5 W= 6023.68 ft μ( = cos-1(1861/6023.68 α º = 72 =
Z
ft = 1861 ft 5729 – 7590 =
Φ
R = 5729.5/BU = 5729/2 = 2864.5 ft W
X = 7590 – 2 * R = 7590 – 5729 = 1861 ft
H
H = (6023.68 ^ 2 – 1861 ^ 2)^0.5 ft 5729 = Φ( = tan -1 ( 1861/ 5729 º 18 = (MD= KOP + Tangent Section + The Two Curves+(v5-v4 Length of the Curve = (α/BU)*100 = (72/2)*100 = 3600 ft Tangent Section = Y = 1861 ft v5-v4)=(10230-1237.5-5729) = 3263.5 ft) Hence, MD= 1237.5+1861+2*3600 + 3263.5 = 13562 ft
X
Intermediate Casing
ft 1237.5 ft 2640
J
)J = R* cos (90-α cos(18) = 2724.3 ft *2864.5 = KOP + J = 1237.5+2724.3 = 3961.8 ft P = cos-1(1402.5/2864.5) = 60.68º
R
P
Length of the new curve = (60.68/2)*100 ft 3034.23 = MD2=1237.5+3034.23 ft = 4271.74 ft X1 = (R^2-1402.5^2 )^0.5 = 2497.67 ft
x1
ft 1402.5
Summary
Max. Inclination reached =α = 72 º Total casing length from the top to the bottom = MD = 13562 ft Length of intermediate casing = MD2= 4271.74 ft Horizontal departure at the casing shoe = x1 = 2497.67 ft
V1
A
O
R1
α V2
ft 10230
β
B α
Φ
2 3 1
V4
C
R2
V3
F
V5
α
D E
X
ft 7590
μ
Y = 7590 – 2 * R
Y
W
Z = 2* R = 5729 ft
W = ( 1861 ^ 2+ 5729 ^ 2)^0.5 W= 6023.68 ft μ( = cos-1(1861/6023.68 α º = 72 =
Z
ft = 1861 ft 5729 – 7590 =
Φ
R = 5729.5/BU = 5729/2 = 2864.5 ft W
X = 7590 – 2 * R = 7590 – 5729 = 1861 ft
H
H = (6023.68 ^ 2 – 1861 ^ 2)^0.5 ft 5729 = Φ( = tan -1 ( 1861/ 5729 º 18 = (MD= KOP + Tangent Section + The Two Curves+(v5-v4 Length of the Curve = (α/BU)*100 = (72/2)*100 = 3600 ft Tangent Section = Y = 1861 ft v5-v4)=(10230-1237.5-5729) = 3263.5 ft) Hence, MD= 1237.5+1861+2*3600 + 3263.5 = 13562 ft
X
Intermediate Casing
ft 1237.5 ft 2640
J
)J = R* cos (90-α cos(18) = 2724.3 ft *2864.5 = KOP + J = 1237.5+2724.3 = 3961.8 ft P = cos-1(1402.5/2864.5) = 60.68º
R
P
Length of the new curve = (60.68/2)*100 ft 3034.23 = MD2=1237.5+3034.23 ft = 4271.74 ft X1 = (R^2-1402.5^2 )^0.5 = 2497.67 ft
x1
ft 1402.5
Summary
Max. Inclination reached =α = 72 º Total casing length from the top to the bottom = MD = 13562 ft Length of intermediate casing = MD2= 4271.74 ft Horizontal departure at the casing shoe = x1 = 2497.67 ft
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