Ex 10
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Statics – Exercise No. 10 10.1 Knowing that the maximum friction force exerted by the bottle on the cork id=s 360 N. Determine (a) the force P which must be applied to the corkscrew to open the bottle, (b) the maximum force exerted by the base of the corkscrew on the top of the bottle. Answer: P = 90 N , R = 270 N .
10.3 Determine the horizontal force P which must be applied at A to maintain the equilibrium of the linkage. Answer: P = 660 N .
10.9 An overhead garage door of weight W consist of a uniform rectangular panel AC supported by a cable AE at the middle of the upper edge of the door and by two sets of frictionless rollers A and B which may slide in horizontal and vertical channels. Express the tension T in the cable AE in terms of W, a, b, and θ. a W cot θ . Answer: T = a+b
10.29 A force P of magnitude 300 N is applied to end E of cable CDE, which passes under pulley D and is attached to the mechanism at C. neglecting the weight of the mechanism and the radius of the pulley, determine the value of θ corresponding to equilibrium. The constant of the spring k = 3500 N/m, and the spring is unstretched when θ = 90°. Answer: θ = 8.36°.
10.40 Using the method of virtual work determine the reaction at E. Answer: E = 7.75 kN . 10.41 Using the method of virtual work determine separately the force and couple representing the reaction at H. Answer: MH = 550 Nm. 10.89 (a) Derive an equation defining the angle θ corresponding to the equilibrium position. (b) Determine the angle θ corresponding to equilibrium if P = 2W. θ W Answer: (a) sin = , (b) θ = 29°. 2 2P
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All the questions are taken from Ferdinand P. Beer and E. Russell Johnston Jr. “Vector Mechanics for Engineers, Statics” Second SI Metric Edition, McGraw-Hill Book Company.
10.3 Determine the horizontal force P which must be applied at A to maintain the equilibrium of the linkage. Answer: P = 660 N .
10.9 An overhead garage door of weight W consist of a uniform rectangular panel AC supported by a cable AE at the middle of the upper edge of the door and by two sets of frictionless rollers A and B which may slide in horizontal and vertical channels. Express the tension T in the cable AE in terms of W, a, b, and θ. a W cot θ . Answer: T = a+b
10.29 A force P of magnitude 300 N is applied to end E of cable CDE, which passes under pulley D and is attached to the mechanism at C. neglecting the weight of the mechanism and the radius of the pulley, determine the value of θ corresponding to equilibrium. The constant of the spring k = 3500 N/m, and the spring is unstretched when θ = 90°. Answer: θ = 8.36°.
10.40 Using the method of virtual work determine the reaction at E. Answer: E = 7.75 kN . 10.41 Using the method of virtual work determine separately the force and couple representing the reaction at H. Answer: MH = 550 Nm. 10.89 (a) Derive an equation defining the angle θ corresponding to the equilibrium position. (b) Determine the angle θ corresponding to equilibrium if P = 2W. θ W Answer: (a) sin = , (b) θ = 29°. 2 2P
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All the questions are taken from Ferdinand P. Beer and E. Russell Johnston Jr. “Vector Mechanics for Engineers, Statics” Second SI Metric Edition, McGraw-Hill Book Company.
