Ejercisios De Polarizacion De Emisor En Transistores

  • April 2020
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EJERCISIOS DE POLARIZACION DE EMISOR EN TRANSISTORES SERVICIO NCIONAL DE APRENDIZAJE = SENA Cesar Andrés Guerrero Rojas Nilson Hernández Castro Mauricio López Montero 43 MELI

EJERCISIO No 1

EJERCICIO No 2

-VCC + VRB + VBE + VRE = 0V -VVC+ IB*RB + VBE + IE*RE =0V -VCC + IB*RB + VBE + (β +1) IB* RE=0V IB*RB + (β +1) IB* RE = VCC – VBE IB= VCC – VBE / RB + (β +1)*RE IB=16V – 0.7V / 240K+ (121)*1.5K =36.29μ A IE= (β + 1) IB = (121)36.29 μ A = 4.391 m A IC= β* IB = 120*36.29 μ A = 4.354 m A

Vrc = IC * RC = 4.354 m A * 3.6 K = 15.6 V VRE= IE * RE = 4.391 m A * 1.5K = 6.58 V VCE= VCC – IC (RC + RE) = 16 – 4.354 m A (3.6K + 1.5 K)= -6.205V VRB= 36.29 μ A * 240K = 8.70V VB= VBE + VE = 0.7 V + 6.58V = 7.28 V VC= VCE +VE = -6.205V + 6.58V= 0.375V VBC= VB- BC = 7.28V -0.375V = 6.905V EJERCICIO No 3

-VBB + VRB + VBE + VRE = 0V

VRB + VRE = VBB – VBE IB* RB + IE* RE = VBB – VBE IB (RB + (β +1)*RE) = VBB – VBE IB = VBB – VBE / RB + (β +1)*RE IB = 4.3V / 419K = 10.26 μ A IC = IB* β = 2.236 m A IE = 2.246 m A VRC = 4.4 V VRE = 2.2 V VRB = 2.05V VBE = VB – VE = VB = VBE + VE= 2.9 V VCE = VCC – VRC – VRE VCE = 5.4V VC = VCE +VC VC = 7.6V VBC= 0.7V – 7.6V= -6.9 V

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