Edo No Homogenea.docx

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𝑴é𝒕𝒐𝒅𝒐 π’‚π’ƒπ’“π’†π’—π’Šπ’‚π’…π’ π’Šπ’π’—π’π’π’–π’„π’“π’‚π’π’…π’ 𝒐𝒑𝒆𝒓𝒂𝒅𝒐𝒓𝒆𝒔 π’šβ€²β€² + πŸπ’šβ€² + πŸπ’š = 𝟏 + 𝒙 𝐷 2 + 2𝐷 + 2 = 0 𝐷=

βˆ’π‘ Β± βˆšπ‘ 2 βˆ’ 4π‘Žπ‘ 2π‘Ž

𝐷=

βˆ’2 Β± √(2)2 βˆ’ 4(1)(2) 2(1)

𝐷=

βˆ’2 Β± √4 2

𝐷1 =

βˆ’2 + βˆšβˆ’4 = βˆ’1 + 𝑖 2

𝐷2 =

βˆ’2 + βˆšβˆ’4 = βˆ’1 βˆ’ 𝑖 2

π‘…π‘Žπ‘–π‘π‘’π‘  π‘π‘œπ‘šπ‘π‘™π‘’π‘—π‘Žπ‘  π‘π‘œπ‘›π‘—π‘’π‘”π‘Žπ‘‘π‘Žπ‘ 

𝒀𝒉 = π‘ͺ𝟏 π’†βˆ’π’™ 𝐜𝐨𝐬 𝒙 + π‘ͺ𝟐 π’†βˆ’π’™ 𝒔𝒆𝒏 𝒙 𝑆𝑖 𝑓(π‘₯) = 𝑃(π‘₯) 𝑓(π‘₯) = 1 + π‘₯ π‘Œπ‘ = 𝑃(π‘₯) βˆ— 𝑄(𝐷) 𝑄(𝐷) = π‘Œπ‘ = (1 + π‘₯) βˆ—

𝐷2

1 𝐹(𝐷)

1 + 2𝐷 + 2

1 βˆ’1 βˆ’π· βˆ’π· 𝐷

1 βˆ’ 𝐷2 2 1 βˆ’ 𝐷2 2 +𝐷2 1 2 𝐷 2 1 βˆ’ 𝐷2 2

2 +2𝐷 1 1 βˆ’ 𝐷 2 2 1 + 𝐷3 2 1 + 𝐷3 2 1 + 𝐷3 2

1 1 1 π‘Œπ‘ = (1 + π‘₯) ( βˆ’ 𝐷 + 𝐷 2 ) 2 2 4 1 1 1 π‘Œπ‘ = (1 + π‘₯) βˆ’ 𝐷(1 + π‘₯) + 𝐷 2 (1 + π‘₯) 2 2 4

1 βˆ’ 𝐷4 4 1 βˆ’ 𝐷4 4

+𝐷2 1 + 𝐷2 4

π‘Œπ‘ =

1 π‘₯ 1 𝑑 1 𝑑 (1 + π‘₯) + βˆ— (1 + π‘₯) + βˆ’ βˆ— 2 2 2 𝑑π‘₯ 4 𝑑π‘₯

π‘Œπ‘ =

1 π‘₯ 1 1 𝑑 (1) + βˆ’ βˆ— (1) + βˆ— 2 2 2 4 𝑑π‘₯

π‘Œπ‘ =

1 π‘₯ 1 1 + βˆ’ βˆ— (1) + βˆ— (0) 2 2 2 4

1 π‘₯ 1 + βˆ’ 2 2 2 𝒙 𝒀𝒑 = 𝟐 π‘Œπ‘ =

π‘Œ = π‘Œβ„Ž + π‘Œπ‘ π‘Œ = 𝐢1 𝑒 βˆ’π‘₯ cos π‘₯ + 𝐢2 𝑒 βˆ’π‘₯ 𝑠𝑒𝑛 π‘₯ +

π‘₯ 2

𝒀 = π’†βˆ’π’™ (π‘ͺ𝟏 𝐜𝐨𝐬 𝒙 + π‘ͺ𝟐 𝒔𝒆𝒏 𝒙) +

𝒙 𝟐

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