Date 030807

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PDS Tut. & Lab.: II (CS 11001/19001): Section 9

Dept. of CS&Engg., IIT Kharagpur

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Tutorial & Laboratory  

Programming & Data Structure: CS11001/19001  



Section - 9/C 





DO NOT POWER ON THE MACHINE Department of Computer Science and Engineering I.I.T. Kharagpur Autumn Semester: 2007 - 2006 (03.08.2007) &

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PDS Tut. & Lab.: II (CS 11001/19001): Section 9

Dept. of CS&Engg., IIT Kharagpur

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Download Download the file date030807.ps from Programming & Data Structures ... of http://www.facweb.iitkgp.ernet.in/∼goutam View the file using the command kghostview & or ggv & &

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PDS Tut. & Lab.: II (CS 11001/19001): Section 9

Dept. of CS&Engg., IIT Kharagpur

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Submission of an Assignment

• There will be no hard copy printout for the sessional work. • You will submit the C program by ftp.

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PDS Tut. & Lab.: II (CS 11001/19001): Section 9

Dept. of CS&Engg., IIT Kharagpur

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Sessional Evaluation

• Correctness of program! • Regularity of work. • Programming style. • Program debugging and testing (by the student). &

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PDS Tut. & Lab.: II (CS 11001/19001): Section 9

Dept. of CS&Engg., IIT Kharagpur

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Note

If program plagiarism is detected, both the source of the copy and the destination of the copy will be awarded zero (0) in that experiment.

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PDS Tut. & Lab.: II (CS 11001/19001): Section 9

Dept. of CS&Engg., IIT Kharagpur

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Program Header

• Each program should have a header containing Section (9/C), Machine No., Roll No., Name, Assignment No. and a short description of the assignment. &

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PDS Tut. & Lab.: II (CS 11001/19001): Section 9

Dept. of CS&Engg., IIT Kharagpur

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File Name Convention • The file name will be CmmAA.c, where ‘C’ is for the section 9, ‘mm’ is the machine number and ‘AA’ is the assignment number e.g. C0604.c is the C program file from section 9, machine number ‘06’, for the 4th assignment.

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PDS Tut. & Lab.: II (CS 11001/19001): Section 9

Dept. of CS&Engg., IIT Kharagpur

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How to Prepare the Submission File • Every input data is also to be printed in the program. • Test your program to satisfy yourself before submission; then do the following: [Let the program file be C0604.c]

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PDS Tut. & Lab.: II (CS 11001/19001): Section 9

Dept. of CS&Engg., IIT Kharagpur

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Submission File (cont.) • Copy C0604.c to C0604.prn : $ cp C0604.c C0604.prn • Let there be five (5) sets of test input. Collect five sets of output in a file by executing ./a.out five times in the following way. $ ./a.out >> C0604.out

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PDS Tut. & Lab.: II (CS 11001/19001): Section 9

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Dept. of CS&Engg., IIT Kharagpur 10

Submission File (cont.) • Append the output file to the print file: $ cat C0604.out >> C0604.prn

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PDS Tut. & Lab.: II (CS 11001/19001): Section 9

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Submission File • You may see the content of C0604.prn by: $ cat C0604.prn | less • If you are satisfied, submit C0604.prn by ftp. • If you are not satisfied, remove both C0604.out and C0604.prn, $ rm C0604.out C0604.prn Fix the error and repeat the process. &

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PDS Tut. & Lab.: II (CS 11001/19001): Section 9

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Submission by ftp

$ ftp 10.3.19.55 Connected to 10.3.19.55 (10.3.19.55). 220 pclabII102 FTP server (Version wu-2.6.2-5) ready. Name (10.3.19.55:.....): pds09 Password: ******* 230 User pds07 logged in. Remote system type is UNIX. Using binary mode to transfer files. > cd assignment04 250 CWD command successful. ftp> put C0604.prn &

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PDS Tut. & Lab.: II (CS 11001/19001): Section 9

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Submission by ftp ftp> put C0604.prn local: C0604.prn remote: C0604.prn 227 Entering Passive Mode (...............) 150 Opening BINARY mode data connection for bat. 226 Transfer complete. 26 bytes sent in ......... secs (....... Kbytes/sec) ftp> bye ............ $ &

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PDS Tut. & Lab.: II (CS 11001/19001): Section 9

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C Program, Output & Print Files

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C program for the following function   2  x +9   

if x < 0,

f (x) =  x4 + 3x2 + 7 if 0 ≤ x < 20,     12x + 7

otherwise

Test the program with the following set of data. {−1.0, 0.0, 20.0, −0.99, +0.99, 19.99, 20.001} &

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C Program: Header : C0604.c /****************************************** * Section : C/9 * * M/c No. : 06, Roll No. : 20MB3007, * * Name : Arya Bhatta, * * Assignment No. : 04, * * Description : Program to calculate a * * given function. * ******************************************/ &

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PDS Tut. & Lab.: II (CS 11001/19001): Section 9

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int main() { float x, fx, temp ;

printf("Enter the value of x : ") ; scanf("%f", &x) ; if (x < 0.0) fx = x * x + 9.0 ; else if (x < 20.0) { temp = x * x ; fx = temp * (temp + 3.0) + 7.0 ; } else fx = 12.0 * x + 7.0 ; printf("\nf(%f) = %f\n", x, fx) ; }

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PDS Tut. & Lab.: II (CS 11001/19001): Section 9

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Creation of Output File $ ./a.out >> C0604.out -1.0 $ ./a.out >> C0604.out 0.0 $ ./a.out >> C0604.out 20.0 $ &

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PDS Tut. & Lab.: II (CS 11001/19001): Section 9

Dept. of CS&Engg., IIT Kharagpur

Output file: C0604.out

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$ cat C0604.out | less Enter the value of x : f(-1.000000) = 10.000000 Enter the value of x : f(0.000000) = 7.000000 Enter the value of x : f(20.000000) = 247.000000 Enter the value of x : f(-0.990000) = 9.980100 &

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Enter the value of x : f(0.990000) = 10.900896 Enter the value of x : f(19.990000) = 160886.031250 Enter the value of x : f(20.000699) = 247.011993

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Creation of Print File $ cp C0604.c C0604.prn $ cat C0604.out >> C0604.prn $ cat C0604.prn | less

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PDS Tut. & Lab.: II (CS 11001/19001): Section 9

Print File: C0604.prn

/****************************************** * Section : D/2 * ............................. int main() { float x, fx, temp ; ............................. printf("\nf(%f) = %f\n", x, fx) ; } Enter the value of x : f(-1.000000) = 10.000000 .............................

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Assignment Programs

• Create a subdirectory assignment07 under your home directory:

$ mkdir assignment07 • Change your current directory to assignment07:

$ cd assignment07 • Execute emacs and create files of assignment programs under the subdirectory assignment07:

$ emacs &

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