Core 1 Rules of Indices ο· ο· ο· ο·
π π₯ Γ π π¦ = π π₯+π¦ π π₯ Γ π π¦ = π π₯βπ¦ (π π₯ )π¦ = π π₯π¦ 1 πβπ₯ = ππ₯
ο·
ππ₯ = βπ
ο· ο·
π = ( βπ)π₯ = βπ π₯ π0 = 1
1
π₯ π¦
π₯
π¦
π¦
Types of Numbers
π π
ο·
β- Rational numbers can be written in the form
ο· ο· ο·
β€- Integers are any whole numbers β- Natural numbers are any positive integer β- Real numbers are any numbers that aren't imaginary
Surds ο· ο·
βπ Γ βπ = βπ Γ π βπ Γ βπ = π
ο·
βπ βπ
π
= βπ
To rationalise the denominator π βπ π π + βπ
Γ
Γ
βπ
πβπ π ππ β πβπ = π2 β π
=
βπ π β βπ π β βπ
Equations of a line ο· ο· ο·
π¦ = ππ₯ + π o π is the gradient o π is the y intercept π¦ β π¦1 = π(π₯ β π₯1 ) o π is the gradient o (π₯1 , π¦1 )is a point on the line ππ₯ + ππ¦ + π = 0 o π, π, and π are all integers
Completing the square π 2 π 2 π₯ 2 + ππ₯ + π = (π₯ + ) β ( ) + π 2 2 For equations such as 3π₯ 2 take the factor outside of the bracket
Sketching Graphs Consider SAXY ο· S- Shape ο· A- Asymptotes ο· X- X intercepts ο· Y- Y intercepts
Discriminant For ππ₯ 2 + ππ₯ + π π 2 β 4ππ If it is: ο· Greater than 0 o There are two real roots. ο·
Equal to 0 o There is one real root.
ο·
Less than 0 o There are no real roots.
Quadratic Inequalities ALWAYS DRAW THE GRAPH Solve the equation as if it is a quadratic equation, and plot it Find the x intercepts, and determine whether x should be greater than or less than those numbers Present on a numberline ο· A filled in circle means equal to ο· An empty circle means not equal to
Sketching Curves The graph of: π¦ = π₯2
π¦ = π₯3
π¦=
1 π₯
Curve Transformations f(x) β original curve
f(x+a)- move left along x axis by a 10
10
8
8
6
6
4
4
2
2
0
0 -4
-2
0
2
4
f(x)+a β move up the y axis by a
-6
-4
-2
0
2
f(ax)- shrink in the x axis by a
12
10
10
8
8
6
6 4
4
2
2
0
0 -4
-2
0
2
4
af(x)- stretch in the y axis by a 20 15 10 5 0 -4
-2
0
2
4
-2
-1
0
1
2
Co-ordinate geometry π= ο· ο·
ο· ο·
ο·
π¦2 β π¦1 π₯2 β π₯1
π is the gradient (π₯1 , π¦1 ) and (π₯2 , π¦2 ) are points on the line Parallel lines- the same gradient Perpendicular lines- one gradient is the negative reciprocal of the other π΄π΅ = β(π₯1 β π₯2 )2 + (π¦1 β π¦2 )2 π΄π΅ is the length of the line (π₯1 , π¦1 ) and (π₯2 , π¦2 ) are points on the line Pythagorasβ Theorem π₯1 + π₯2 π¦1 + π¦2 Midpoint ( , ) 2 2 (π₯1 , π¦1 ) and (π₯2 , π¦2 ) are points on the line
Sequences ο· ο· ο·
ππ = ππβ1 + π ππ = π + (π β 1)π ππ is a term in the sequence π is the first term π is the common difference ππ =
ο·
ππ is the sum of a sequence up to π
π (2π + (π β 1)π) 2
πΈππ π£πππ’π
β ο·
(ππππ’ππππ)
ππ‘πππ‘πππ π£πππ’π
β(ππππ’ππππ) means the sum of a sequence
Differentiation ππ¦ = ππ₯ πβ1 ππ₯
For π(π₯) the derivative is πβ²(π₯) 1. For a gradient at a point substitute the x value into the differentiated equation 2. To find the coordinate where a gradient equals a number, make the differentiated equation equal to the number 3. To find the gradient where a curve meets a line find the coordinate where they meet and use method 1 π2 π¦
The second derivative is ππ₯ 2 or πβ²β²(π₯)
Integration β«(π₯ π )ππ₯ =
π₯ π+1 +π π+1