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Core 1 Rules of Indices ο‚· ο‚· ο‚· ο‚·

π‘Ž π‘₯ Γ— π‘Ž 𝑦 = π‘Ž π‘₯+𝑦 π‘Ž π‘₯ Γ— π‘Ž 𝑦 = π‘Ž π‘₯βˆ’π‘¦ (π‘Ž π‘₯ )𝑦 = π‘Ž π‘₯𝑦 1 π‘Žβˆ’π‘₯ = π‘Žπ‘₯

ο‚·

π‘Žπ‘₯ = βˆšπ‘Ž

ο‚· ο‚·

π‘Ž = ( βˆšπ‘Ž)π‘₯ = βˆšπ‘Ž π‘₯ π‘Ž0 = 1

1

π‘₯ 𝑦

π‘₯

𝑦

𝑦

Types of Numbers

π‘Ž 𝑏

ο‚·

β„š- Rational numbers can be written in the form

ο‚· ο‚· ο‚·

β„€- Integers are any whole numbers β„•- Natural numbers are any positive integer ℝ- Real numbers are any numbers that aren't imaginary

Surds ο‚· ο‚·

βˆšπ‘Ž Γ— βˆšπ‘ = βˆšπ‘Ž Γ— 𝑏 βˆšπ‘Ž Γ— βˆšπ‘Ž = π‘Ž

ο‚·

βˆšπ‘Ž βˆšπ‘

π‘Ž

= βˆšπ‘

To rationalise the denominator π‘Ž βˆšπ‘ π‘Ž 𝑏 + βˆšπ‘

Γ—

Γ—

βˆšπ‘

π‘Žβˆšπ‘ 𝑏 π‘Žπ‘ βˆ’ π‘Žβˆšπ‘ = 𝑏2 βˆ’ 𝑐

=

βˆšπ‘ 𝑏 βˆ’ βˆšπ‘ 𝑏 βˆ’ βˆšπ‘

Equations of a line ο‚· ο‚· ο‚·

𝑦 = π‘šπ‘₯ + 𝑐 o π‘š is the gradient o 𝑐 is the y intercept 𝑦 βˆ’ 𝑦1 = π‘š(π‘₯ βˆ’ π‘₯1 ) o π‘š is the gradient o (π‘₯1 , 𝑦1 )is a point on the line π‘Žπ‘₯ + 𝑏𝑦 + 𝑐 = 0 o π‘Ž, 𝑏, and 𝑐 are all integers

Completing the square 𝑏 2 𝑏 2 π‘₯ 2 + 𝑏π‘₯ + 𝑐 = (π‘₯ + ) βˆ’ ( ) + 𝑐 2 2 For equations such as 3π‘₯ 2 take the factor outside of the bracket

Sketching Graphs Consider SAXY ο‚· S- Shape ο‚· A- Asymptotes ο‚· X- X intercepts ο‚· Y- Y intercepts

Discriminant For π‘Žπ‘₯ 2 + 𝑏π‘₯ + 𝑐 𝑏 2 βˆ’ 4π‘Žπ‘ If it is: ο‚· Greater than 0 o There are two real roots. ο‚·

Equal to 0 o There is one real root.

ο‚·

Less than 0 o There are no real roots.

Quadratic Inequalities ALWAYS DRAW THE GRAPH Solve the equation as if it is a quadratic equation, and plot it Find the x intercepts, and determine whether x should be greater than or less than those numbers Present on a numberline ο‚· A filled in circle means equal to ο‚· An empty circle means not equal to

Sketching Curves The graph of: 𝑦 = π‘₯2

𝑦 = π‘₯3

𝑦=

1 π‘₯

Curve Transformations f(x) – original curve

f(x+a)- move left along x axis by a 10

10

8

8

6

6

4

4

2

2

0

0 -4

-2

0

2

4

f(x)+a – move up the y axis by a

-6

-4

-2

0

2

f(ax)- shrink in the x axis by a

12

10

10

8

8

6

6 4

4

2

2

0

0 -4

-2

0

2

4

af(x)- stretch in the y axis by a 20 15 10 5 0 -4

-2

0

2

4

-2

-1

0

1

2

Co-ordinate geometry π‘š= ο‚· ο‚·

ο‚· ο‚·

ο‚·

𝑦2 βˆ’ 𝑦1 π‘₯2 βˆ’ π‘₯1

π‘š is the gradient (π‘₯1 , 𝑦1 ) and (π‘₯2 , 𝑦2 ) are points on the line Parallel lines- the same gradient Perpendicular lines- one gradient is the negative reciprocal of the other 𝐴𝐡 = √(π‘₯1 βˆ’ π‘₯2 )2 + (𝑦1 βˆ’ 𝑦2 )2 𝐴𝐡 is the length of the line (π‘₯1 , 𝑦1 ) and (π‘₯2 , 𝑦2 ) are points on the line Pythagoras’ Theorem π‘₯1 + π‘₯2 𝑦1 + 𝑦2 Midpoint ( , ) 2 2 (π‘₯1 , 𝑦1 ) and (π‘₯2 , 𝑦2 ) are points on the line

Sequences ο‚· ο‚· ο‚·

π‘ˆπ‘› = π‘ˆπ‘›βˆ’1 + 𝑑 π‘ˆπ‘› = π‘Ž + (𝑛 βˆ’ 1)𝑑 π‘ˆπ‘› is a term in the sequence π‘Ž is the first term 𝑑 is the common difference 𝑆𝑛 =

ο‚·

𝑆𝑛 is the sum of a sequence up to 𝑛

𝑛 (2π‘Ž + (𝑛 βˆ’ 1)𝑑) 2

𝐸𝑛𝑑 π‘£π‘Žπ‘™π‘’π‘’

βˆ‘ ο‚·

(π‘†π‘’π‘žπ‘’π‘’π‘›π‘π‘’)

π‘†π‘‘π‘Žπ‘Ÿπ‘‘π‘–π‘›π‘” π‘£π‘Žπ‘™π‘’π‘’

βˆ‘(π‘†π‘’π‘žπ‘’π‘’π‘›π‘π‘’) means the sum of a sequence

Differentiation 𝑑𝑦 = 𝑛π‘₯ π‘›βˆ’1 𝑑π‘₯

For 𝑓(π‘₯) the derivative is 𝑓′(π‘₯) 1. For a gradient at a point substitute the x value into the differentiated equation 2. To find the coordinate where a gradient equals a number, make the differentiated equation equal to the number 3. To find the gradient where a curve meets a line find the coordinate where they meet and use method 1 𝑑2 𝑦

The second derivative is 𝑑π‘₯ 2 or 𝑓′′(π‘₯)

Integration ∫(π‘₯ 𝑛 )𝑑π‘₯ =

π‘₯ 𝑛+1 +𝑐 𝑛+1

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