Class Notes Industrial Lec11

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Telephone : PABX : 9661920-73/4980

DEPT. OF APPLIED PHYSICS, ELETRONICS & COMMUNICATION ENGINEERING UNIVERSITY OF DHAKA DHAKA-1000, BANGLADESH FAX: 880-2-8615583 E-MAIL: [email protected]

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November 25, 2008 Dated, the………………………….

Ref. No............................

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Telephone : PABX : 9661920-73/4980

DEPT. OF APPLIED PHYSICS, ELETRONICS & COMMUNICATION ENGINEERING UNIVERSITY OF DHAKA DHAKA-1000, BANGLADESH FAX: 880-2-8615583 E-MAIL: [email protected]

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November 25, 2008 Dated, the………………………….

Ref. No............................

2 3 *+.4 ""

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# ) *+.4 52 50*+14 '( ( ) : ) 3 ;" 2 )$ 3 ;" 2 (.*+,% ) 3 ;" 2 4.*+,% ( ( ) : ) $3 ) ()$ 3 ;" 2 (;" 2 (.*+,% 3 ;"#. 2 (*+,%# *+,% 3 < ,;" *+.42 (*+,% 3 < ,;" 2 4*+1% )$ 3 )$ () 3 < ,;" 2 (*+.% ) 3 ) () = 3Vmsin( t+ /2) ) ) ": π / 2 +α 6 Vdc = v ab d (ωt ) 2π π / 6+α = = = = = =

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3Vm sin(ωt + π / 6)d (ωt )

π / 6 +α

3 3Vm

[− cos(ωt + π / 6)]ππ // 26++αα

3 3Vm

[− cos(π / 2 + α + π / 6) + cos(π / 6 + α + π / 6)]

3 3Vm

[cos(π / 3 + α ) − cos(2π / 3 + α )]

π

π

π

3 3Vm

π

3 3Vm

π

.2 sin(π / 2 + α ) sin(π / 6) cos α

" =" " ) 3 3Vm Vdm =

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Telephone : PABX : 9661920-73/4980

DEPT. OF APPLIED PHYSICS, ELETRONICS & COMMUNICATION ENGINEERING UNIVERSITY OF DHAKA DHAKA-1000, BANGLADESH FAX: 880-2-8615583 E-MAIL: [email protected]

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November 25, 2008 Dated, the………………………….

Ref. No............................

Vrms

π / 2+α

6 = 2π

1/ 2

3V sin (ωt + π / 6)d (ωt ) 2 m

2

π / 6 +α

3 3Vm2 = . π 2

1/ 2

π / 2 +α

(1 − cos(2ωt + π / 3))d (ωt )

π / 6 +α

9Vm2 sin( 2ωt + π / 3) ωt − = 2π 2 =

π / 2 +α

1/ 2

π / 6 +α

sin(π / 3 + 2α + π / 3) sin(π + 2α + π / 3) π /2 +α − −π / 6 −α + 2 2 2π

3Vm

3Vm π 1 = − {sin( 4π / 3 + 2α ) − sin(2π / 3 + 2α )} 2π 3 2 3Vm π 1 = − .2 cos(π + 2α ) sin(π / 3) 2π 3 2 3Vm π 3 cos 2α = + 2 2π 3

>?

(--

#!

= Vm = Vm

3 9 3 cos 2α + 2 4π

(6,

1/ 2

1/ 2

1/ 2

1 3 3 cos 2α + 2 4π )

1/ 2

1/ 2

9 π 9 3 . + . cos 2α 2π 3 2π 2

= 3Vm

1/ 2

1/ 2

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Telephone : PABX : 9661920-73/4980

DEPT. OF APPLIED PHYSICS, ELETRONICS & COMMUNICATION ENGINEERING UNIVERSITY OF DHAKA DHAKA-1000, BANGLADESH FAX: 880-2-8615583 E-MAIL: [email protected]

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November 25, 2008 Dated, the………………………….

Ref. No............................

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Telephone : PABX : 9661920-73/4980

DEPT. OF APPLIED PHYSICS, ELETRONICS & COMMUNICATION ENGINEERING UNIVERSITY OF DHAKA DHAKA-1000, BANGLADESH FAX: 880-2-8615583 E-MAIL: [email protected]

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November 25, 2008 Dated, the………………………….

Ref. No............................

Vdc 2 =

3 3Vm

π

' % %$ '

cos α 2 :

)

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Vdc1 = −Vdc 2 cos α 2 = − cos α 1 = cos(π − α 1 )

α 2 = π − α1 ( ( ) 3 ;" )$ 3 ;" ) 3 ;"

)8-

'

= =

(--

#!

(60

:

2 (.*+,% 2 4.*+,% ( ( )

: ) $3 ) ()$ 3 ;" 2 (;" 2 (.*+,% 3 ;"#. 2 (*+,%# *+,% 3 < ,;" *+.42 (*+,% 3 < ,;" 2 4*+1% )$ 3 )$ () 3 < ,;" 2 (*+.% ) 3 ) () 3 < ,;" 2 40*+1% )8. ) ) ) *+14 -52 5 *4 - : ) 3 )8-4)8. 3 ) $()$ 3 < ,;"> 2 4*+1%( 2 (*+.%A 3 < ,;"#. 2 (*+1% .*+,% 3 ,;" 2 (*+1% $ ": ωt 1 i r (t ) = v r d (ωt ) ωLr π / 6+α1 =

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) 2

1 ωL r

ωt

-

.

)

)

3Vm cos(ωt − π / 6)d (ωt )

π / 6+α1

3Vm [sin(ωt − π / 6]ωπ t/ 6+α1 ωL r 3Vm [sin(ωt − π / 6) − sin α1 ] ωL r )

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