Telephone : PABX : 9661920-73/4980
DEPT. OF APPLIED PHYSICS, ELETRONICS & COMMUNICATION ENGINEERING UNIVERSITY OF DHAKA DHAKA-1000, BANGLADESH FAX: 880-2-8615583 E-MAIL:
[email protected]
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November 25, 2008 Dated, the………………………….
Ref. No............................
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Telephone : PABX : 9661920-73/4980
DEPT. OF APPLIED PHYSICS, ELETRONICS & COMMUNICATION ENGINEERING UNIVERSITY OF DHAKA DHAKA-1000, BANGLADESH FAX: 880-2-8615583 E-MAIL:
[email protected]
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November 25, 2008 Dated, the………………………….
Ref. No............................
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Telephone : PABX : 9661920-73/4980
DEPT. OF APPLIED PHYSICS, ELETRONICS & COMMUNICATION ENGINEERING UNIVERSITY OF DHAKA DHAKA-1000, BANGLADESH FAX: 880-2-8615583 E-MAIL:
[email protected]
! "
November 25, 2008 Dated, the………………………….
Ref. No............................
Vrms
π / 2+α
6 = 2π
1/ 2
3V sin (ωt + π / 6)d (ωt ) 2 m
2
π / 6 +α
3 3Vm2 = . π 2
1/ 2
π / 2 +α
(1 − cos(2ωt + π / 3))d (ωt )
π / 6 +α
9Vm2 sin( 2ωt + π / 3) ωt − = 2π 2 =
π / 2 +α
1/ 2
π / 6 +α
sin(π / 3 + 2α + π / 3) sin(π + 2α + π / 3) π /2 +α − −π / 6 −α + 2 2 2π
3Vm
3Vm π 1 = − {sin( 4π / 3 + 2α ) − sin(2π / 3 + 2α )} 2π 3 2 3Vm π 1 = − .2 cos(π + 2α ) sin(π / 3) 2π 3 2 3Vm π 3 cos 2α = + 2 2π 3
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3 9 3 cos 2α + 2 4π
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9 π 9 3 . + . cos 2α 2π 3 2π 2
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Telephone : PABX : 9661920-73/4980
DEPT. OF APPLIED PHYSICS, ELETRONICS & COMMUNICATION ENGINEERING UNIVERSITY OF DHAKA DHAKA-1000, BANGLADESH FAX: 880-2-8615583 E-MAIL:
[email protected]
! "
November 25, 2008 Dated, the………………………….
Ref. No............................
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Telephone : PABX : 9661920-73/4980
DEPT. OF APPLIED PHYSICS, ELETRONICS & COMMUNICATION ENGINEERING UNIVERSITY OF DHAKA DHAKA-1000, BANGLADESH FAX: 880-2-8615583 E-MAIL:
[email protected]
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November 25, 2008 Dated, the………………………….
Ref. No............................
Vdc 2 =
3 3Vm
π
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Vdc1 = −Vdc 2 cos α 2 = − cos α 1 = cos(π − α 1 )
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π / 6+α1
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