Chemistry Maggie

CHEMISTRY PROJECT LI HIN HANG CHUI HIU TUNG

CHEMISTRY PRACTICAL PROJECT WORK DETERMINE THE NEURALIZING POWER OF COMMERICAL ANTACID SAMPLES

THEORY ANTI ACID IS A KIND OF MEDICINE THAT USED TO CURE STOMACH ACHE ■ IN THIS EXPERIMENT ,WE WILL PUT THE ANTI ACID IN KNOWN MOLARITY (O.1M)HCl AND IS BACK TITRATED AGAINST STANDARD NaOH SOLUTION. ■

WE CAN DETERMINE THE NEUTRALIZING POWER OF EACH BRAND OF SAMPLE BY RECORDING THE VOLUME OF NaOH USED IN BACK TITRATION ■ THE ONE WHICH USE LESS NaOH IN BACK TITRATION MEANS THAT IS THE STRONGER ■

CHEMICALS AND SAMPLES USED ■ ■ ■ ■ ■

~0.1M HCl 300ml ~0.1M NaOH 300ml CARBON POWDER MTHYL ORANGE 1 TABLET OF EACH SAMPLE

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WEISEN U TAITAN HYDROSOIL

APPARATUS AND EQUIPMENT USED ■ ■ ■

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500ml BEAKER X1 250ml BEARKER X3 250ml CONICAL FLASK X3 25ml PIPETTE X1 PIPETTE FILLER X1 50ml BURETTE X2 BURETTE CLAMP X 2

■ ■ ■ ■ ■ ■ ■

FUNNEL X1 FILTER PAPER X3 GLASS ROD X1 DROPPER X1 WASH BOTTLE X1 WHITE TILE X1 ELECTRIC BALANCE X1

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■

MORTAR AND PESTLE X1 SPOON X1

EXPRERIMENTAL PROCEDURES STANDARDIZATION OF HCl ■ BACK TITRATION OF EACH SAMPLE ■

STANDARDIZATION OF HCl ■

TO DETERMINE THE MOLARITY OF HCl

PROCEDURES CLEAN UP ALL APPARATUS ■ SUCK UP 25ml OF HCl (UNKNOWN MOLARITY)INTO THE PIPETTE BY USING PIPETTE FILLER ■ RELEASE THE SOLUTION INTO 250ml CONICAL FLASK ■ ADDING SOME INDICATOR(MTHYL ORANGE) TO THE CONCIAL FLASK ■

ADD UP THE BURETTE WITH 50mlOF (0.1M)NaOH ■ TITRATE THE SOLUTION UNTIL IT REACH THE END POINT.(INDICATE CHANGE OF RED TO YELLOW) ■

RESULT INITIAL READING

0ml

0ml

FINAL READING

24.9ml

24.9ml

NaOH USED 24.9ml

24.9ml

MEAN OF NAOH USED (24.9+24.9)/2 =24.9ml THE MOLARITY OF HCl MV=MV 25M=0.1032(24.9/1000) M=0.1028M AS THE RESULT,THE MOLARITY OF HCl IS 0.1028M,~0.1M

BACK TITRATION OF EACH SAMPLE ■

TO DETERMINE THE NUTRALIZING POWER OF EACH SAMPLE

PROCEDURES USE MOTER AND PISTEL TO BREAK DOWN THE TABLET INTO POWDER FORM ■ WEIGHT THE POWDER BY ELECTRIC BALANCE ■ DISSOLVE THE POWDER IN EXCESS HCl(25ml,30ml OR 50ml) IN CONCIAL FLASK(250ml) ■

STIRR THE SOLUTION WITH GLASS ROD ■ ADDING SOME CARBON POWDER TO ABSORB THE COLOUR OF THE SOLUTION ■ USE THE FILTER PAPER AND FUNNEL TO FILTER OUT THE UNDISSOLVE PARTICALS AND CARBON POWDER ■

ADDING FEW DROPS OF MTHYL ORANGE TO THE FILTERED SOLUTION AS AN INDICATOR ■ ADD UP THE BURETTE WITH 50ml NaOH(0.1M) ■ TITRATE THE SOLUTION UNTIL IT REACH THE END POINT(RED TO YELLOW) ■

ACTIVE INGREDIENT OF WEISEN U ■

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ALUMINIUM HYDROXIDE 192mg MAGNESIUM HYDROXIDE 159mg METHYLMETHIONI NE SULFONIUM CHLORIDE 25mg BIODIASTASE 25mg

METHY. .. BIO... AL(OH)3 MG(OH) 2

RESULT OF WEISEN U INITAL 1ml READING FINAL 25.8ml READING

0ml

0.7ml

24.9ml

26.4ml

NaOH USED

24.9ml

25.7ml

24.8ml

MEAN OF NaOH USED (24.8+24.9+25.7)/3 =25.1ml HCl ADDED IN DISSOLVING THE SAMPLE: 50ml HCl NEURALIZED BY THE SAMPLE: 50-25.1 =24.9ml

NO. OF MOLE OF HCl NEUTRALIZED BY WEISENU (24.9/1000)0.1028 =2.559X(10)-3mol

INGRADIENTS OF TAITAN ■ ■ ■

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Na(HCO3) 91.7mg Al(OH)3 36.7mg Al(OH)3+Mg(OH)2 36.7mg OTHERS 41.8mg

Na.... Al... Mg..+Al. . OTHERS

RESULT OF TAITAN INITIAL 0ml READING FINAL 9.6ml READING NaOH 9.6ml USED

1ml

0.7ml

10.2ml

10.1ml

9.2ml

9.4ml

MEAN OF NaOH USED (9.6+9.4+9.2)/3 =9.4ml VOLUME OF HCl USED:30ml VOLUME OF HCI NEUTRALIZED BY TAITAN: 30ml-9.4ml=20.6ml THE VOLUME OF HCl NEUTRALIZED BY TAITAN IS 20.6ml

NO. OF MOLE OF ACID NEUTRALIZED BY TAITAN: (20.6/1000)0.1028 =2.12X(10)-3mol

INGREDIENTS OF HYDROSOIL ■ ■ ■

Al(OH)3 200mg Mg(OH)2 200mg OTHERS ~150mg Al.. Mg... OTHERS

RESULT OF HYDROSOIL INITIAL 0.1ml READING FINAL 14.7ml READING

0.7ml

1.1ml

12.8ml

13.2ml

NaOH USED

12.1ml

12.1ml

14.6ml

MEAN OF NaOH (14.6+12.1+12.1)/3 =12.9ml VOLUME OF HCl USED:25ml HCl NEUTRALIZED BY HYDROSOIL: 25-12.9 =12.1ml

NO. OF MOLE OF ACID NEUTRALIZED BY HYDROSOIL: (12.1/1000)0.1028 =1.24X(10)-3mol

NO. OF MOLE OF HCl NEUTRALIZED BY EACH SAMPLE WEISEN U:(2.559/1000)mol ■ TAITAN:(2.12/1000)mol ■ HYDROSOIL:(1.24/1000)mol ■

NEUTRALIZING POWER: WESIEN U>TAITAN> HYDROSOIL WENSIEN U IS THE STRONGEST

WESIEN U

ERRORS OF THE EXPERIMENT THERE WILL HAVE SOME LOSS OF THE SAMPLES DURING GRINDING ■ THERE WILL HAVE SOME LOSS OF THE SAMPLES DURING FILTERING ■ SOME OF THE ACTIVE INGEDIENT MAY NOT DISSOLVE IN WEAK ACID(0.1M) ■

THE INDICATOR CAN NOT INDICATE THE SMALL RANGE OF pH CHANGE ■ HUMAN ERRORS ■ THER WILL BE OTHER SUBSTANCE IN THE TABLET WHICH AFFECT THE EXPERIMENTAL RESULT ■

PRECAUTIONS ACID IS CORROSIVE ■ ALKALINE IS CORROSIVE ■

CONCLUSION ■

AFTER THE EXPERIMENT,WE CAN DETERMINE THAT THE NEUTRALIZING POWER OF 1 TABLET OF EACH SAMPLE,THE STRONGEST ONE IS WESIEN U ,THE SECOND IS TAITAN, AND THE WEAKEST IS HYDROSOIL.

THE END THANK YOU VERY MUCH!!!!!

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