Day 15 10.1– Adding and Subtracting Polynomials 10.2 – Multiplying Polynomials 10.1 Classifying Polynomials Polynomial: Usually written in ________________________________ Degree: Degree of a Polynomial: Leading Coefficient: Names for polynomials with different degrees are _________________, ___________________, _____________________, ___________________, and _____________________. Names for polynomials with different numbers of terms are _________________, __________________, and __________________.
Classify the following Polynomials: Polynomial Degree Type (by degree)
Leading Type (by terms) Coefficient
4 -3x + 2 2x 4x3 – 2x2 + 3x +2 3x2 + 1 x4 1 – 5x + 7x3 8x3 + 7 – x2 3x – 15x2 21 Adding & Subtracting To simplify, we must add or subtract ___________________________________ (have the same degree).
1. Find the sum of (5x3 – x + 2x2 + 7) + (x + x2 + 6) Vertically:
Horizontally:
Recall: The Distributive Property! 2. Find the difference of (3x2 – 5x + 3) – (2x2 – x – 4) Vertically:
Horizontally:
3. (2a2 – 4a + 3) + (6a2 + 4a – 3)
4. (5x2 + 2x – 1) + 8x2
5. (-3 + 2n2 + 5n5) – (4 – n3 + 2n2 + n5)
6. (6x – 3x2 + 1) – (9x – 4 – 3x2)
7. (6x – 5) – (8x + 15) + (3x – 4)
8. -10(u + 1) + 8(u – 1) – 3(u + 6)
10.2 Multiplying Polynomials Recall (again): The Distributive Property! 9. 3x(2x2 – 5x + 3) =
10. (2x – 3)(x + 7) =
Geometric Example:
w= h= Square Area (add up each square) =
Area of the entire rectangular region = F= O= I= L= 11. (3x – 4)(2x + 1) =
12. (x – 3)(2x + 2) =
13. (5a – b)(a + b) =
14. (2m – 1)(2m – 5) =
15. (2y – 4z)(2y + z) =
16. (x + 4)(3x + 2) =
Binomial-Trinomial & 3-Binomal Multiplication Caution!! 17. (x – 2)(5 + 3x – x2) = Vertically:
Horizontally:
18. (-x2 + 2x + 4)(x – 3) =
19. (x + 1)(5x3 –x2 + x + 4) =
20. (x – 1)(x3 + 2x2 + 2) =
21. (a2 - ab + b2)(a + b) =
22. (x + 9)(x – 2)(x – 7) =
23. (2x – 6)(x + 7)(x + 6) =
Day 16 10.3 – Special Products 10.4 – Solving in Factored Form Review: Simplify. 1. (2x2 – 3x – 1) – (5x2 + 2x – 3) =
2. 3x2(x3 – 6x2 + x – 5) =
3. (x – 6)(3x2 – 5) =
4. (x2 – 8x – 3)(x + 2) =
10.3 Special Products Recall: F. O. I. L. (see #3 above) Today: Special Binomial-Binomial Multiplication Patterns (a.k.a. You can’t fool me…I know what’s going to happen) Complete the examples and determine the patterns. Example: (4x + 3)(4x + 3) = Pattern: (a + b)2 = (a + b)(a + b) =
Example: (2x – 5)(2x – 5) =
Pattern: (a – b)2 = (a – b)(a – b) =
Example: (x – 3)(x + 3) =
Pattern: (a + b)(a – b) =
Geometric Example of (a + b)(a + b) = w= h= Square Area (add up each square) =
Area of the entire rectangular region = Yay, practice! 5. (x – 2)(x + 2) =
6. (4x + 7)(4x – 7) =
7. (2a – 1)2 =
8. (x + y)2 =
9. (3m + 5)2 =
10. (3 – 10z)2 =
10.4: Solving in Factored Form Recall: We can solve Quadratics by * * Today: Factored form! Zero Product Property: If ab = 0, then _________________ or _________________.
Solve (x – 2)(x + 3) = 0. When the equation equals zero, that means “solve!” Why?
11. (2x – 3)(x + 5) = 0
12. 5x(2x + 3) = 0
13. 2(x – 5)2 = 0
14. Cubic: 3x(4x + 2)(9x + 18) = 0
Recall: Finding the Vertex and Axis of Symmetry Today: x- coordinate of vertex is ____________________________________________. Find the roots, vertex, and axis of symmetry of y = (x – 2)(x – 6). Graph (label two additional points on your graph).
Find the roots, vertex, and axis of symmetry. Graph (label two additional points on your graph). 15. y = 4(x + 1)(x – 1) 16. y = - (x + 3)(x + 5)
Day 17 10.5 – Factoring the Greatest Common Factor and x2 + bx + c 10.7 – Factoring Special Products Review. 1. (13b + q)2
2. (10pq + 5r)(10pq – 5r)
3. 5x(4x – 1)(8x -7) = 0
4. Find the vertex of y = (x + 5)(x – 2)
10.5: Factoring the GCF Recall: Zero – Product & Distributive Properties Today: Factoring in order to solve using the Zero – Product Property Think about GCF factoring as ‘reverse distribution’ Before: y = 6(x + 2) = 6x + 12
Now: y = 6x + 12 = 6(x + 2) Solve: 6(x + 2) = 0 x+2=0 x = -2
Before: y = 5b(2b – 3) =
Now: y = 10b2 – 15b = Solve:
What is the GCF of all coefficients? What is the lowest exponent of all of the terms? Factor. 1. 16x2y3 – 12x3y2
2. 7r5s2 + 49r2s
3. 16wv4 + 12w3v2
4. 2d2e2 – 8d6e6
10.5: Factoring x2 + bx + c All of the trinomials we will factor today have an x2 coefficient of ___________! Next class we will factor trinomials with other values for a. Ex 1: Factor and solve x2 + x – 6 = 0 Step 1: Find a*c Find b
a*c = b=
Step 2: Find two numbers that have a product of the a*c value and a sum of the b value Step 3: Write the trinomial as the product of two binomials Step 4: Solve, if necessary.
Ex 2: Factor and solve x2 + 9x + 18 = 0 Step 1: Find a*c Find b
a*c = b=
Step 2: Find two numbers that have a product of the a*c value and a sum of the b value Step 3: Write the trinomial as the product of two binomials Step 4: Solve, if necessary.
Ex 3: Factor and solve x2 + 5x – 36 = 0
Factor. 5. x2 + 10x + 21
6. x2 + 8x + 15
7. x2 – 9x + 20
8. x2 – 8x – 9
9. x2 + 3x – 18
10. x2 + 6x – 5
How can you tell whether or not a trinomial can be factored?
Factor and solve. If not factorable, provide evidence. 11. x2 + 11x = -18 12. x2 – 5x = 24
13. x2 + 3x = 14
14. x2 – 5x = 32
10.7: Factoring Special Products Recall: Special Binomial-Binomial Multiplication Patterns Ex 4: Factor x2 – 36
Pattern:
Ex 5: Factor x2 + 6x + 9
Pattern:
Ex 6: Factor x2 – 12x + 36
Pattern:
Note: Factor. 15. 4x2 – 25
16. 16y2 – 24y + 9
17. 2x2 + 8x + 8
18. x2 + 9
19. 12 – 27x2
20. 9y2 + 60y + 100
21. 2x2 – 12x + 18
22. 4n2 – 16m2
23. If you kick a ball with an initial velocity of 32 ft/sec, will the ball reach a height of 16 feet? If it does, how long will it take to reach that height? Formula: Model: Factor and solve:
Day 18 11.6 – Factoring ax2 + bx + c 11.8 – Factoring with four terms Review: Factor and solve. If not factorable, provide evidence. 1. x2 – 10x + 24 = 0
2. x2 + 10x = - 9
3. 3x2 + 18x = 120
4. 12x2 + 27x = 0
5. 36x2 – 25 = 0
6. 4x2 – 40x = - 100
Recall: Steps to factor x2 + bx + c Step 1: Step 2: Step 3: Step 4: Today: We will factor trinomials of the form ax2 + bx + c where the coefficient of x2 is a number ________________________________________________________________. Today’s style of factoring is called the British method.
Ex 1: Factor and solve 6x2 – x – 2 = 0 Step 1: Find a*c a*c = Find b b= Step 2: Find two numbers that have a product of the a*c value and a sum of the b value Step 3: Write the trinomial as a polynomial with four terms, splitting the bx term into two terms using the values from Step 3 Step 4: Group the first two terms and the last two terms, inserting an addition sign in the middle. Step 5: Factor the GCF from the first group and factor the GCF from the second group. Step 6: Checkpoint! Factor the matching binomials. Group the outside terms. Step 7: Solve, if necessary. Ex 2: Factor and solve 8x2 – 2x – 3 = 0 Step 1: Find a*c a*c = Find b b= Step 2: Find two numbers that have a product of the a*c value and a sum of the b value Step 3: Write the trinomial as a polynomial with four terms, splitting the bx term into two terms using the values from Step 3 Step 4: Group the first two terms and the last two terms, inserting an addition sign in the middle. Step 5: Factor the GCF from the first group and factor the GCF from the second group. Step 7: Checkpoint! Factor the matching binomials. Group the outside terms. Step 8: Solve, if necessary.
Practice! Factor completely. Solve, if necessary. 1. 3x2 + 13x + 14
2. 5x2 + 27x – 18
3. 3x2 + 5x + 2
4. 2x2 + 21x – 11
5. 8x2 – 14x – 15
6. 6x2 + 9x – 27
7. 7x2 – 4x – 3
8. 6x2 – 5x – 21
9. 10x2 + 25x – 90
10. 8x2 + 10x – 11 = 12x + 10
Factoring by grouping:
13. x3 + 4x2 + 6x + 24
14. x3 + 2x2 – 36x – 72
Factor completely. Completely means: 15. 4x2 – 36
16. 75x4 – 3x2
17. 5x3 – 25x2 – 30x
18. 2x3 + 3x2 – 50x – 75
19. If the diving board at the Gunn pool is 2 feet above the water and you jump off the platform with an initial velocity of 4 feet per second, how long will it take you to enter the water? Model: Factor to solve:
Day 19 Chapter 10 Review 1. (- z3 + 3z) + (- z2 – 4z – 6)
2. (5x2 + 7x – 4) – (4x2 – 2x)
3. 5b2(3b3 – 2b2 + 1)
4. (3z + 4)(5z – 8)
5. (3 + 2s – s2)(s – 1)
6. (5p – 6q)2
7. (10x – 5y)(10x + 5y)
8. 3(x + 2)2 = 0
9. 2(3x – 1)(2x + 5) = 0
10. Find the x – intercepts, vertex, and axis of symmetry of the function. Graph (find two additional points for your graph). y = (x – 3)(x + 1)
Solve by factoring. 11. x2 – 2x = 24
12. 3x2 – 5 = - 14x
Factor completely. 13. x4 + 4x3 – 45x2
14. 8t3 – 3t2 + 16t – 6
Day 20 Quest today on Chapter 10 Review. 1. (3a + 2a4 – 5) – (a3 + 2a4 + 5a)
2. 4x2 – 5x = 6
3. 121 – x2
4. 64y2 + 48y + 9
5. x4 + 4x3 – 45x2 = 0
6. x3 + 2x2 – 4x - 8