اﻟﺒﺎب اﻟﺮاﺑﻊ ﺧﺮاﺋﻂ اﻟﺘﺤﻜﻢ ﻟﻠﺨﻮاص Control Charts for Attributes
د .ﻣﺤﻤﺪ ﻋﻴﺸـــﻮﻧﻲ أﺳﺘﺎذ ﻣﺴﺎﻋﺪ – ﻗﺴﻢ اﻟﺘﻘﻨﻴﺔ اﻟﻤﻴﻜﺎﻧﻴﻜﻴﺔ ٢٠٠٤ - Email :
[email protected] http://hctmetrology.tripod.com/quality
ﻣﻘﺪﻣﺔ ﻋﻦ ﺧﺮاﺋﻂ اﻟﺘﺤﻜﻢ ﻟﻠﺨﻮاص
ﺧﺮاﺋﻂ اﻟﺘﺤﻜﻢ ﻟﻠﺨﻮاص هﻲ أداة ﺕﻘﻨﻴﺔ ﻟﻠﻀﺒﻂ اﻻﺡﺼﺎﺋﻲ ﻟﺠﻮدة اﻟﻤﻨﺘﺠﺎت ،ﺕﻘﻮم ﻋﻠﻰ ﻗﻴﺎﺳﺎت ﻋﺎﻣﺔ ﻟﻤﺪى ﻣﻄﺎﺑﻘﺔ اﻟﻮﺡﺪات اﻟﻤﻨﺘﺠﺔ ﻣﻊ اﻟﻤﻮاﺹﻔﺎت اﻟﻘﻴﺎﺳﻴﺔ ﻣﻦ ﻋﺪﻣﻪ.
ﻧﻘﻮم ﺑﺘﺴﺠﻴﻞ ﺑﻴﺎﻧﺎت اﻟﺠﻮدة ﻋﻠﻰ ﺵﻜﻞ اﻋﺪاد ﻟﻠﻘﻄﻊ اﻟﻤﻄﺎﺑﻘﺔ conformingأو ﻏﻴﺮ اﻟﻤﻄﺎﺑﻘﺔ )ﻣﻨﺘﺞ ﻣﻌﻴﺐ( .non conforming
هﺬﻩ اﻟﺨﺮاﺋﻂ ﻋﻠﻰ ﻧﻮﻋﻴﻦ: ﺧﺮیﻄﺔ ﻧﺴﺒﺔ اﻟﻤﻌﻴﺐ p chart c chart ﺧﺮیﻄﺔ ﻋﺪد اﻟﻌﻴﻮب
.١ .٢
١
ﺧﺮیﻄﺔ ﻧﺴﺒﺔ اﻟﻤﻌﻴﺐ
p chart
ﺕﻘﻮم هﺬﻩ اﻟﺨﺮاﺋﻂ ﻋﻠﻰ دراﺳﺔ ﻗﻴﺎس اﻟﺼﻔﺎت و ﺧﺼﺎﺋﺺ اﻟﻤﻨﺘﺞ و ذﻟﻚ ﺑﺘﺤﺪیﺪ اﻟﻨﺴﺒﺔ اﻟﻤﺌﻮیﺔ اﻟﻐﻴﺮ ﻣﻄﺎﺑﻘﺔ ﻟﻠﻤﻮاﺹﻔﺎت )أو اﻟﻤﻌﻴﺒﺔ(. ﻣﺜﺎل : ﻋﺪد اﻟﻜﺮاﺳﻲ اﻟﺘﺎﻟﻔﺔ ﻓﻲ اﻟﻘﺎﻋﺔ = ٥ اﻟﻌﺪد اﻹﺝﻤﺎﻟﻲ ﻟﻠﻜﺮاﺳﻲ اﻟﻤﻔﺤﻮﺹﺔ )اﻟﻤﻮﺝﻮدة ﻓﻲ اﻟﻘﺎﻋﺔ( = ٥٠ ﻧﺴﺒﺔ اﻟﻜﺮاﺳﻲ اﻟﻤﻌﻴﺒﺔ = %١٠ = ١٠٠ * ٥٠ /٥ اﻟﻘﻄﻌﺔ اﻟﻤﻔﺤﻮﺹﺔ :ﻣﻄﺎﺑﻘﺔ أو ﻏﻴﺮ ﻣﻄﺎﺑﻘﺔ ٣
ﺧﺮیﻄﺔ ﻧﺴﺒﺔ اﻟﻤﻌﻴﺐ
.١ .٢ .٣ .٤ ٤
٢
p chart
ﺕﺆﺧﺬ ﻋﻴﻨﺎت ﻣﻦ ﺧﻂ اﻻﻧﺘﺎج ﻋﻠﻰ ﻓﺘﺮات ﻣﺨﺘﻠﻔﺔ و ﺕﻔﺘﺶ ﻋﻠﻰ ﺝﻮدة اﻟﻤﻨﺘﺞ ﺑﺤﺴﺎب ﻋﺪد اﻟﻮﺡﺪات اﻟﻤﻌﻴﺒﺔ )(#nonconforming items و ﻣﻦ ﺙﻢ و ﻗﺼﺪ اﻧﺸﺎء ﺧﺮیﻄﺔ ﻧﺴﺒﺔ اﻟﻤﻌﻴﺐ ﻧﻘﻮم ﺑﻤﺎ یﻠﻲ: ﻋﺪد اﻟﻮﺡﺪات اﻟﻤﻌﻴﺒﺔ ﻓﻲ آﻞ ﻋﻴﻨﺔ
ﺡﺴﺎب ﻧﺴﺒﺔ اﻟﻤﻌﻴﺐ ﻓﻲ آﻞ ﻋﻴﻨﺔ ﺡﺴﺎب ﺡﺪود اﻟﻀﺒﻂ ﻟﻠﻨﺴﺒﺔ رﺳﻢ ﺧﺮیﻄﺔ ﻧﺴﺒﺔ اﻟﻤﻌﻴﺐ ﻣﻊ ﺡﺪود اﻟﻀﺒﻂ دراﺳﺔ اﺳﺒﺎب أي اﻧﺤﺮاﻓﺎت ﻗﺪ ﻧﻼﺡﻈﻬﺎ.
اﻟﻌﺪد اﻻﺝﻤﺎﻟﻲ ﻟﻠﻮﺡﺪات ﻓﻲ آﻞ ﻋﻴﻨﺔ
=p
p Chart
ﺣﺴﺎب ﺣﺪود اﻟﻀﺒﻂ اﻟﺤﺪ اﻷﻋﻠﻰ ﻟﻠﻀﺒﻂ
Upper Control Limit
اﻟﺤﺪ اﻷدﻧﻰ ﻟﻠﻀﺒﻂ
Lower Control Limit
اﻻﻧﺤﺮاف اﻟﻤﻌﻴﺎري ﻟﻨﺴﺒﺔ اﻟﻤﻌﻴﺐ σp
Control Limits
) p (1 − p n
= p + z
) p (1 − p n
= p − z
p
p
UCL
LCL
ﻣﺘﻮﺳﻂ ﻧﺴﺒﺔ اﻟﻤﻌﻴﺐ ﻓﻲ اﻟﻌﻴﻨﺎت p s
ﻳﻤﺜﻞ zﻡﻌﺎﻡﻞ ﺽﺮب ﻧﺴﺘﻌﻤﻠﻪ آﺎﻟﺘﺎﻟﻲ:
∑ xi
;• z = 2 for 95.5% limits
∑ ni
i =1 s
= p
i =1
• z = 3 for 99.7% limits ٥
ﻡﺜﺎل ﻋﻤﻠﻲ ﻟﺨﺮﻳﻄﺔ ﻧﺴﺒﺔ اﻟﻤﻌﻴﺐ
ﺵﺮآﺔ ﺹﻨﺎﻋﻴﺔ ﺕﺼﻨﻊ ﻗﻄﻊ ﻣﻴﻜﺎﻧﻴﻜﻴﺔ ﻟﻤﺤﺮآﺎت اﻟﺪیﺰل .أﺧﺬت ١٠ﻋﻴﻨﺎت ﻣﻦ ﺧﻂ اﻻﻧﺘﺎج ،ﺕﺤﺘﻮي آﻞ واﺡﺪة ﻋﻠﻰ ١٠٠ ﻗﻄﻌﺔ و ﺕﻢ اﻟﺘﻔﺘﻴﺶ ﻋﻨﻬﺎ ﺡﺴﺐ ﻣﻮاﺹﻔﺎت ﻣﻌﻴﻨﺔ و رﺹﺪت أﻋﺪاد اﻟﻘﻄﻊ اﻟﻤﻌﻴﺒﺔ ﻋﻠﻰ اﻟﺠﺪول اﻟﺘﺎﻟﻲ:
هﻞ ﻧﻈﺎم اﻟﺘﺼﻨﻴﻊ ﻣﻨﻀﺒﻂ اﺡﺼﺎﺋﻴﺎ أم ﻻ ؟
٦
٣
p chart
10
9
8
7
6
5
4
3
2
1
اﻟﻌﻴﻨﺔ
4
3
6
2
1
4
8
3
2
5
ﻋﺪد اﻟﻘﻄﻊ اﻟﻤﻌﻴﺒﺔ
ﻡﺜﺎل ﻋﻤﻠﻲ
p chart
٢
m = 10 ﻋﺪد اﻟﻌﻴﻨﺎت ﻋﺪد اﻟﻘﻄﻊ ﻓﻲ آﻞ ﻋﻴﻨﺔ n = 100 10
9
8
7
6
5
4
3
2
1
اﻟﻌﻴﻨﺔ
4
3
6
2
1
4
8
3
2
5
ﻋﺪد اﻟﻤﻌﻴﺐ
0.05 0.02 0.03 0.08 0.04 0.01 0.02 0.06 0.03 0.04ﻧﺴﺒﺔ اﻟﻤﻌﻴﺐ m
ﻣﺘﻮﺳﻂ ﻧﺴﺒﺔ اﻟﻤﻌﻴﺐ ﻓﻲ آﻞ اﻟﻌﻴﻨﺎت
= 0 . 038
∑ pˆ i
i=1
m
= p
٧
ﻡﺜﺎل ﻋﻤﻠﻲ
٣
) p (1 − p n
= p + z
p
UCL
) p (1 − p n
= p − z
p
LCL
i=1 s
= p
z=3
p chart
ﺣﺴﺎب ﺣﺪود اﻟﻀﺒﻂ
s
i
∑ x
i
∑ n
i=1
)0.038(1 − 0.038 = 0.095 100
UCL = 0.038 + 3 CL = 0.038
)0.038(1 − 0.038 = −0.02 → 0 100 ٨
٤
LCL = 0.038 + 3
رﺱﻢ ﺥﺮﻳﻄﺔ ﻧﺴﺒﺔ اﻟﻤﻌﻴﺐ
p chart
٤
P Chart 0.10
3.0SL=0.09536
P=0.03800
- 3.0SL=0.000
اﻟﻨﺴﺒﺔ Proporti on
0.05
0.00 10
9
8
7
6
5
4
3
2
1
0
رﻗﻢ اﻟﻌﻴﻨﺔ
Sampl e Number
٩
ﺧﺮیﻄﺔ ﻋﺪد اﻟﻌﻴﻮب ﻓﻲ اﻟﻮﺡﺪة c chart
ﺧﺮیﻄﺔ ﻋﺪد اﻟﻌﻴﻮب هﻲ إﺡﺪى أهﻢ ﺧﺮاﺋﻂ اﻟﺘﺤﻜﻢ )ﺽﺒﻂ اﻟﺠﻮدة( ﻟﻠﺨﻮاص: •
١٠
٥
ﻋﺒﺎرة ﻋﻦ أﻋﺪاد ﺡﻘﻴﻘﻴﺔ )ﻻ یﻤﻜﻦ ﺡﺴﺎﺑﻬﺎ ﺑﺎﻟﻨﺴﺒﺔ اﻟﻤﺌﻮیﺔ( .
ﺕﺒﻴﻦ هﺬﻩ اﻟﺨﺮیﻄﺔ ﻋﺪد اﻟﻌﻴﻮب وﺡﺪة ﻣﻦ اﻟﻤﻨﺘﺞ :
))(nonconformities (defects
ﻓﻲ آﻞ
•
اﻟﻮﺡﺪة ﻗﺪ ﺕﻜﻮن ﻣﺜﻼ آﺮﺳﻲ ،ﺹﻔﻴﺤﺔ ﺹﻠﺐ أو ﺳﻴﺎرة ...
•
ﺡﺠﻢ اﻟﻮﺡﺪة یﻜﻮن ﺙﺎﺑﺖ.
•
ﻡﺜﺎل :ﺡﺴﺎب ﻋﺪد اﻟﻌﻴﻮب )ﺧﺪوش ،ﻣﺴﺎﻣﻴﺮ ﻏﻴﺮ ﻣﺜﺒﺘﺔ اﻟﺦ (..ﻓﻲ آﻞ آﺮﺳﻲ ﻣﻦ ﻋﻴﻨﺔ ﺕﺤﺘﻮي ﻋﻠﻰ ١٠٠آﺮﺳﻲ
.
c Chart
ﺣﺴﺎب ﺣﺪود اﻟﻀﺒﻂ
Control Limits
اﻟﺤﺪ اﻷﻋﻠﻰ ﻟﻠﻀﺒﻂ
c
UCL c = c + 3z
اﻟﺤﺪ اﻷدﻧﻰ ﻟﻠﻀﺒﻂ
ﻋﺪد اﻟﻌﻴﻮب ﻓﻲ آﻞ وﺡﺪة ci
c ﻳﻤﺜﻞ zﻡﻌﺎﻡﻞ ﺽﺮب ﻧﺴﺘﻌﻤﻠﻪ ﻟﺘﺤﺪﻳﺪ اﻟﺤﺪود اﻟﻤﺮاد ﺕﺤﻘﻴﻘﻬﺎ: ;• z = 2 : for 95.5% limits • z = 3 : for 99.7% limit
Upper Control Limit
Lower Control Limit
LCL c = c − 3z
ﻡﺘﻮﺱﻂ ﻋﺪد اﻟﻌﻴﻮب ﻓﻲ آﻞ اﻟﻮﺣﺪات k ∑ ci c = i =1
k
١١
ﻡﺜﺎل ﻋﻤﻠﻲ ﻟﺨﺮﻳﻄﺔ ﻋﺪد اﻟﻌﻴﻮب
١٢
٦
c chart
ﺵﺮآﺔ وودﻻﻧﺪ ﺕﺼﻨﻊ ورق ﻟﻄﺒﺎﻋﺔ اﻟﺠﺮاﺋﺪ .ﻓﻲ ﺁﺧﺮ ﻣﺮﺡﻠﺔ اﻻﻧﺘﺎج ﻗﺎم ﻣﻔﺘﺶ اﻟﺠﻮدة ﻟﺪى اﻟﺸﺮآﺔ ﺑﺎﻟﺘﻔﺘﻴﺶ ﻋﻦ ﺝﻮدة اﻟﻮرق ﺑﺈﺝﺮاء ﻗﻴﺎﺳﺎت ﻟﺨﺼﺎﺋﺺ اﻟﺠﻮدة ﻋﻠﻰ 5ﻟﻔﺎت ﻣﻦ اﻟﻮرق اﻟﻤﺼﻨﻊ و رﺹﺪ اﻟﻨﺘﺎﺋﺞ اﻟﻤﺠﺪوﻟﺔ أدﻧﺎﻩ. اﻟﻤﻄﻠﻮب :ﻋﻦ ﻃﺮیﻖ ﺧﺮیﻄﺔ اﻟﺘﺤﻜﻢ ﻟﻌﺪد اﻟﻌﻴﻮب ادرس اﺳﺘﻘﺮار اﻟﻌﻤﻠﻴﺔ اﻟﺘﺼﻨﻴﻌﻴﺔ ﻟﻠﺸﺮآﺔ )هﻞ ﻧﻈﺎم اﻟﺘﺼﻨﻴﻊ ﻣﻨﻀﺒﻂ )اﺡﺴﺐ ب(z = 2 : اﺡﺼﺎﺋﻴﺎ أم ﻻ ؟( 5
4
3
2
1
اﻟﻠﻔﺔ
24
22
17
21
16
ﻋﺪد اﻟﻌﻴﻮب
c Chart
ﺣﺴﺎب ﺣﺪود اﻟﻀﺒﻂ
Control Limits
ﻣﺘﻮﺳﻂ ﻋﺪد اﻟﻌﻴﻮب ﻓﻲ آﻞ اﻟﻮﺡﺪات c = (16+21+17+22+24) / 5 = 20
c = 20
z=2
اﻟﺤﺪ اﻷﻋﻠﻰ ﻟﻠﻀﺒﻂ
Upper Control Limit
UCLc = c + z c = 28.94 اﻟﺤﺪ اﻷدﻧﻰ ﻟﻠﻀﺒﻂ
c = 11.06
Lower Control Limit
LCLc = c – z
١٣
رﺱﻢ ﺥﺮﻳﻄﺔ ﻋﺪد اﻟﻌﻴﻮب
c chart
ﻋﺪد اﻟﻌﻴﻮب
رﻗﻢ اﻟﻌﻴﻨﺔ )اﻟﻠﻔﺔ(
١٤
٧
– ﺣﺎﻟﺔ دراﺱﻴﺔ ﻋﻦ ﺏﻨﻚ١ ﺕﺪرﻳﺐ Construction of p chart Example 1
Sample Number
Wrong Account Number
1 2 3 4 5 6 7 8 9 10 11 12
15 12 19 2 19 4 24 7 10 17 15 3
The operations manager of the booking services department of Hometown Bank is concerned about the number of wrong customer account numbers recorded by Hometown personnel. Each week a random sample of 2,500 deposits is taken, and the number of incorrect account numbers is recorded. The records for the past 12 weeks are shown in the following table.
Is the process out of control? (Use 3-sigma control limits.)
١٥
٢ ﺕﺪرﻳﺐ Construction of c chart Example 2 Surface defects have been counted on 25 rectangular steel plates, and the data are shown in the table. Construct a c control chart for nonconformities using this data to study if the process is under control
Plate No. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
No. of Nonconformities 1 0 4 3 1 2 5 0 2 1 1 0 8 0 2 1 3 5 4 6 3 1 0 2 4
٨
ﺟﺰاآﻢ اﷲ ﺥﻴﺮا ﻋﻠﻰ ﺣﺴﻦ اﻻﺱﺘﻤﺎع
هﻞ ﻡﻦ أﺱﺌﻠﺔ ؟ ٢٠٠٠
١٧
٩