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CALCULOS

ο‚·

PROCESO DE DISTANCIAS

Registro NΒΊ1 LADO A-B B-C C-D D-E E-A

DISTANCIAS INICIALES DE LA POLIGONAL TRAMO 1 TRAMO 2 TRAMO 3 TRAMO 4 TRAMO 5 4,495 5,365 3,354 4,219 4,400 5,933 5,206 4,864 3,986 4,130 2,903 4,887 3,686 4,819 3,879 4,185 5,248 4,968 5,733 0 4,445 5,068 4,798 0 0 PerΓ­metro(m)

TOTAL(m) 21,833 24,119 20,174 20,134 14,311 100,571

πΏπ‘‘π‘œπ‘‘π‘Žπ‘™ 𝐴𝐡 = 𝑇𝑅𝐴𝑀𝑂1 + 𝑇𝑅𝐴𝑀𝑂2 + 𝑇𝑅𝐴𝑀𝑂3 + 𝑇𝑅𝐴𝑀𝑂4 + 𝑇𝑅𝐴𝑀𝑂5 πΏπ‘‘π‘œπ‘‘π‘Žπ‘™ 𝐴𝐡 = (4,495 + 5,365 + 3,354 + 4,219 + 4,400)π‘š πΏπ‘‘π‘œπ‘‘π‘Žπ‘™ 𝐴𝐡 = 21,833 π‘š

πΏπ‘‘π‘œπ‘‘π‘Žπ‘™ 𝐡𝐢 = 𝑇𝑅𝐴𝑀𝑂1 + 𝑇𝑅𝐴𝑀𝑂2 + 𝑇𝑅𝐴𝑀𝑂3 + 𝑇𝑅𝐴𝑀𝑂4 + 𝑇𝑅𝐴𝑀𝑂5 πΏπ‘‘π‘œπ‘‘π‘Žπ‘™ 𝐡𝐢 = (5,933 + 5,206 + 4,864 + 3,986 + 4,130)π‘š πΏπ‘‘π‘œπ‘‘π‘Žπ‘™ 𝐡𝐢 = 24,119 π‘š

πΏπ‘‘π‘œπ‘‘π‘Žπ‘™ 𝐢𝐷 = 𝑇𝑅𝐴𝑀𝑂1 + 𝑇𝑅𝐴𝑀𝑂2 + 𝑇𝑅𝐴𝑀𝑂3 + 𝑇𝑅𝐴𝑀𝑂4 + 𝑇𝑅𝐴𝑀𝑂5 πΏπ‘‘π‘œπ‘‘π‘Žπ‘™ 𝐢𝐷 = (2,903 + 4,887 + 3,686 + 4,819 + 3,879)π‘š πΏπ‘‘π‘œπ‘‘π‘Žπ‘™ 𝐢𝐷 = 20,174 π‘š

πΏπ‘‘π‘œπ‘‘π‘Žπ‘™ 𝐷𝐸 = 𝑇𝑅𝐴𝑀𝑂1 + 𝑇𝑅𝐴𝑀𝑂2 + 𝑇𝑅𝐴𝑀𝑂3 + 𝑇𝑅𝐴𝑀𝑂4 + 𝑇𝑅𝐴𝑀𝑂5 πΏπ‘‘π‘œπ‘‘π‘Žπ‘™ 𝐷𝐸 = (4,185 + 5,248 + 4,968 + 5,733)π‘š πΏπ‘‘π‘œπ‘‘π‘Žπ‘™ 𝐷𝐸 = 20,134 π‘š

πΏπ‘‘π‘œπ‘‘π‘Žπ‘™ 𝐸𝐴 = 𝑇𝑅𝐴𝑀𝑂1 + 𝑇𝑅𝐴𝑀𝑂2 + 𝑇𝑅𝐴𝑀𝑂3 + 𝑇𝑅𝐴𝑀𝑂4 + 𝑇𝑅𝐴𝑀𝑂5 πΏπ‘‘π‘œπ‘‘π‘Žπ‘™ 𝐸𝐴 = (4,445 + 5,068 + 4,79)π‘š

πΏπ‘‘π‘œπ‘‘π‘Žπ‘™ 𝐸𝐴 = 14,311 π‘š

𝑃𝐸𝑅𝐼𝑀𝐸𝑇𝑅𝑂 = πΏπ‘‘π‘œπ‘‘. 𝐴𝐡 + πΏπ‘‘π‘œπ‘‘. 𝐡𝐢 + πΏπ‘‘π‘œπ‘‘. 𝐢𝐷 + πΏπ‘‘π‘œπ‘‘. 𝐷𝐸 + πΏπ‘‘π‘œπ‘‘. 𝐸𝐴 𝑃𝐸𝑅𝐼𝑀𝐸𝑇𝑅𝑂 = (21,833 + 24,119 + 20,174 + 20,134 + 14,311)π‘š 𝑃𝐸𝑅𝐼𝑀𝐸𝑇𝑅𝑂 = 100,571 π‘š

Registro NΒΊ2 (Correcciones) DISTANCIAS INICIALES DE LA POLIGONAL LADO TRAMO1c TRAMO2c TRAMO3c TRAMO4c TRAMO5c TOTALcorreg(m) A-B 4,494671 5,364633 3,353739 4,218686 4,399676 21,83141 B-C 5,932614 5,205639 4,863654 3,985699 4,129691 24,1173 C-D 2,902769 4,886653 3,685717 4,818656 3,878706 20,1725 D-E 4,18468804 5,24763722 4,9676489 5,73262018 0 20,1325943 E-A 4,44467405 5,06764458 4,79765661 0 0 14,3099752 PerΓ­metro(m) 100,563773

a) CorrecciΓ³n por standarizaciΓ³n (Cs)

𝐸𝑐 = πΏπ‘π‘œπ‘šπ‘–π‘›π‘Žπ‘™ βˆ’ πΏπ‘…π‘’π‘Žπ‘™

𝐢𝑠 =

πΏπ‘‡π‘Ÿπ‘Žπ‘šπ‘œ βˆ— 𝐸𝑐 πΏπ‘‡π‘Ÿπ‘Žπ‘šπ‘œ

𝐿𝑣 = πΏπ‘‡π‘Ÿπ‘Žπ‘šπ‘œ Β± 𝐢𝑠

Nota.- Como no tenemos el dato de la longitud real (LRe) no podemos calcular la longitud verdadera

b) CorrecciΓ³n por temperatura (Ct) 𝐢𝑑 = ±𝐿𝐾(𝑇 βˆ’ π‘‡π‘œ) Nota.- el signo estarΓ‘ dado por el resultado de la expresiΓ³n de parΓ©ntesis de la formula

LADO A-B 1

TRAMO 1 𝐢𝑑 = Β±4,495π‘š βˆ— 0,000012 ℃ (13 βˆ’ 20)℃ 𝐢𝑑 = βˆ’0,00037758π‘š 1

TRAMO 2 𝐢𝑑 = Β±5,365π‘š βˆ— 0,000012 ℃ (13 βˆ’ 20)℃ 𝐢𝑑 = βˆ’0,00045066π‘š

1

TRAMO 3 𝐢𝑑 = Β±3,354π‘š βˆ— 0,000012 ℃ (13 βˆ’ 20)℃ 𝐢𝑑 = βˆ’0,000281736π‘š

1

TRAMO 4 𝐢𝑑 = Β±4,219π‘š βˆ— 0,000012 ℃ (13 βˆ’ 20)℃ 𝐢𝑑 = βˆ’0,000354396π‘š

1

TRAMO 5 𝐢𝑑 = Β±4,400π‘š βˆ— 0,000012 ℃ (13 βˆ’ 20)℃ 𝐢𝑑 = βˆ’0,0003696π‘š

LADO B-C 1

TRAMO 1 𝐢𝑑 = Β±5,933π‘š βˆ— 0,000012 ℃ (13 βˆ’ 20)℃ 𝐢𝑑 = βˆ’0,000498372π‘š

1

TRAMO 2 𝐢𝑑 = Β±5,206π‘š βˆ— 0,000012 ℃ (13 βˆ’ 20)℃ 𝐢𝑑 = βˆ’0,000437304π‘š

1

TRAMO 3𝐢𝑑 = Β±4,864π‘š βˆ— 0,000012 ℃ (13 βˆ’ 20)℃ 𝐢𝑑 = βˆ’0,000408576π‘š

1

TRAMO 4 𝐢𝑑 = Β±3,986π‘š βˆ— 0,000012 ℃ (13 βˆ’ 20)℃ 𝐢𝑑 = βˆ’0,000334824π‘š 1

TRAMO 5 𝐢𝑑 = Β±4,130π‘š βˆ— 0,000012 ℃ (13 βˆ’ 20)℃ 𝐢𝑑 = βˆ’0,00034692π‘š LADO C-D 1

TRAMO 1 𝐢𝑑 = Β±2,903π‘š βˆ— 0,000012 ℃ (13 βˆ’ 20)℃ 𝐢𝑑 = βˆ’0,000243852π‘š 1

TRAMO 2 𝐢𝑑 = Β±4,887π‘š βˆ— 0,000012 ℃ (13 βˆ’ 20)℃ 𝐢𝑑 = βˆ’0,000410508π‘š 1

TRAMO 3 𝐢𝑑 = Β±3,686π‘š βˆ— 0,000012 ℃ (13 βˆ’ 20)℃ 𝐢𝑑 = βˆ’0,000309624π‘š

1

TRAMO 4 𝐢𝑑 = Β±4,819π‘š βˆ— 0,000012 ℃ (13 βˆ’ 20)℃ 𝐢𝑑 = βˆ’0,000404796π‘š 1

TRAMO 5 𝐢𝑑 = Β±3,879π‘š βˆ— 0,000012 ℃ (13 βˆ’ 20)℃ 𝐢𝑑 = βˆ’0,000325836π‘š

LADO D-E 1

TRAMO 1 𝐢𝑑 = Β±4,185π‘š βˆ— 0,000012 ℃ (13 βˆ’ 20)℃ 𝐢𝑑 = βˆ’0,00035154π‘š

1

TRAMO 2 𝐢𝑑 = Β±5,248π‘š βˆ— 0,000012 ℃ (13 βˆ’ 20)℃ 𝐢𝑑 = βˆ’0,000440832π‘š 1

TRAMO 3 𝐢𝑑 = Β±4,986π‘š βˆ— 0,000012 ℃ (13 βˆ’ 20)℃ 𝐢𝑑 = βˆ’0,000417312π‘š 1

TRAMO 4 𝐢𝑑 = Β±5,733π‘š βˆ— 0,000012 ℃ (13 βˆ’ 20)℃ 𝐢𝑑 = βˆ’0,000481572π‘š LADO E-A 1

TRAMO 1 𝐢𝑑 = Β±4,445π‘š βˆ— 0,000012 ℃ (13 βˆ’ 20)℃ 𝐢𝑑 = βˆ’0,00037338π‘š 1

TRAMO 2 𝐢𝑑 = Β±5,068π‘š βˆ— 0,000012 ℃ (13 βˆ’ 20)℃ 𝐢𝑑 = βˆ’0,000425712π‘š 1

TRAMO 3 𝐢𝑑 = Β±4,798π‘š βˆ— 0,000012 (13 βˆ’ 20)℃ ℃

𝐢𝑑 = βˆ’0,000403032π‘š

c) CorrecciΓ³n por catenaria (Cc) 𝐢𝑐 = Β±

π‘Š 2 𝐿3 24𝑃2

Nota.- el signo serΓ‘ negativo (-) si ha sido fabricada apoyada en toda su longitud y la medida se efectΓΊa con error de catenaria. El signo serΓ‘ positivo (+) si ha sido fabricada con catenaria y la medida se efectΓΊa apoyada en toda su longitud

LADO A-B π‘”π‘Ÿ

TRAMO 1

𝐢𝑐 = Β±

(18 π‘š )2 βˆ—(4,495π‘š)3 24βˆ—(5000π‘”π‘Ÿ)2

𝐢𝑐 =4,90437E-05π‘š

π‘”π‘Ÿ

TRAMO 2 𝐢𝑐

=Β±

(18 π‘š )2 βˆ—(5,365π‘š)3 24βˆ—(5000π‘”π‘Ÿ)2

𝐢𝑐 = 8,33879E-05π‘š

TRAMO 3 𝐢𝑐

=Β±

π‘”π‘Ÿ 2 ) βˆ—(3,354π‘š)3 π‘š 24βˆ—(5000π‘”π‘Ÿ)2

(18

𝐢𝑐 = 2,03743E-05π‘š π‘”π‘Ÿ

TRAMO 4 𝐢𝑐

=Β±

(18 π‘š )2 βˆ—(4,219π‘š)3

24βˆ—(5000π‘”π‘Ÿ)2 𝐢𝑐 = 4,05529E-05π‘š

π‘”π‘Ÿ

TRAMO 5 𝐢𝑐

=Β±

(18 π‘š )2 βˆ—(4,400π‘š)3 24βˆ—(5000π‘”π‘Ÿ)2

𝐢𝑐 = 4,59994E-05π‘š

LADO B-C π‘”π‘Ÿ

TRAMO 1 𝐢𝑐

=Β±

(18 π‘š )2 βˆ—(5,933π‘š)3 24βˆ—(5000π‘”π‘Ÿ)2

𝐢𝑐 = 0,000112776π‘š

TRAMO 2 𝐢𝑐

=Β±

π‘”π‘Ÿ 2 ) βˆ—(5,206π‘š)3 π‘š 24βˆ—(5000π‘”π‘Ÿ)2

(18

𝐢𝑐 = 7,61915E-05π‘š

π‘”π‘Ÿ

TRAMO 3 𝐢𝑐

=Β±

(18 π‘š )2 βˆ—(4,864π‘š)3 24βˆ—(5000π‘”π‘Ÿ)2

𝐢𝑐 = 6,21405E-05π‘š

π‘”π‘Ÿ

TRAMO 4 𝐢𝑐

=Β±

(18 π‘š )2 βˆ—(3,986π‘š)3 24βˆ—(5000π‘”π‘Ÿ)2

𝐢𝑐 = 3,41984E-05π‘š

π‘”π‘Ÿ

TRAMO 5 𝐢𝑐

=Β±

(18 π‘š )2 βˆ—(4,130π‘š)3 24βˆ—(5000π‘”π‘Ÿ)2

𝐢𝑐 =3,80403E-05π‘š

LADO C-D TRAMO 1 𝐢𝑐

=Β±

π‘”π‘Ÿ 2 ) βˆ—(2,903π‘š)3 π‘š 24βˆ—(5000π‘”π‘Ÿ)2

(18

𝐢𝑐 = 1,3211E-05π‘š

π‘”π‘Ÿ

TRAMO 2 𝐢𝑐

=Β±

(18 π‘š )2 βˆ—(4,887π‘š)3 24βˆ—(5000π‘”π‘Ÿ)2

𝐢𝑐 = 6,30261E-05π‘š

TRAMO 3 𝐢𝑐

=Β±

π‘”π‘Ÿ 2 ) βˆ—(3,686π‘š)3 π‘š 24βˆ—(5000π‘”π‘Ÿ)2

(18

𝐢𝑐 = 2,70433E-05π‘š

TRAMO 4 𝐢𝑐

=Β±

π‘”π‘Ÿ 2 ) βˆ—(4,819π‘š)3 π‘š 24βˆ—(5000π‘”π‘Ÿ)2

(18

𝐢𝑐 = 6,04317E-05π‘š

π‘”π‘Ÿ

TRAMO 4 𝐢𝑐

=Β±

(18 π‘š )2 βˆ—(3,879π‘š)3 24βˆ—(5000π‘”π‘Ÿ)2

𝐢𝑐 = 3,15176E-05π‘š

LADO D-E π‘”π‘Ÿ

TRAMO 1 𝐢𝑐

=Β±

(18 π‘š )2 βˆ—(4,185π‘š)3 24βˆ—(5000π‘”π‘Ÿ)2

𝐢𝑐 = 3,95804E-05π‘š

π‘”π‘Ÿ

TRAMO 2 𝐢𝑐

=Β±

(18 π‘š )2 βˆ—(5,248π‘š)3 24βˆ—(5000π‘”π‘Ÿ)2

𝐢𝑐 = 7,80504E-05π‘š

π‘”π‘Ÿ

TRAMO 3 𝐢𝑐

=Β±

(18 π‘š )2 βˆ—(4,968π‘š)3 24βˆ—(5000π‘”π‘Ÿ)2

𝐢𝑐 = 6,62123E-05π‘š

TRAMO 4 𝐢𝑐

=Β±

π‘”π‘Ÿ 2 ) βˆ—(5,733π‘š)3 π‘š 24βˆ—(5000π‘”π‘Ÿ)2

(18

𝐢𝑐 = 0,000101751π‘š

LADO E-A π‘”π‘Ÿ

TRAMO 1 𝐢𝑐

=Β±

(18 π‘š )2 βˆ—(4,445π‘š)3 24βˆ—(5000π‘”π‘Ÿ)2

𝐢𝑐 = 4,74252E-05π‘š

π‘”π‘Ÿ

TRAMO 2 𝐢𝑐

=Β±

(18 π‘š )2 βˆ—(5,068π‘š)3 24βˆ—(5000π‘”π‘Ÿ)2

𝐢𝑐 = 7,02916E-05π‘š

π‘”π‘Ÿ

TRAMO 3 𝐢𝑐

=Β±

(18 π‘š )2 βˆ—(4,798π‘š)3 24βˆ—(5000π‘”π‘Ÿ)2

𝐢𝑐 = 5,96451E-05π‘š

d) CorrecciΓ³n por horizontalidad (Ch) πΆβ„Ž = Β±

β„Ž2 2𝐿

Nota.- Como no tenemos el dato de variaciΓ³n de altura (h) no podremos calcular la correcciΓ³n por horizontalidad

e) CorrecciΓ³n por tensiΓ³n (Cp) 𝐢𝑝 = Β±

(𝑃 βˆ’ π‘ƒπ‘œ)𝐿 𝐴𝐸

Nota.- Como no tenemos los datos: tensiΓ³n aplicada (P), secciΓ³n transversal de la cinta (A), mΓ³dulo de elasticidad de la cinta (E)

CorrecciΓ³n total 𝐿𝑐 = 𝐿 Β± 𝐢𝑠 Β± 𝐢𝑑 Β± 𝐢𝑐 Β± πΆβ„Ž Β± 𝐢𝑝 𝐿𝑐 = 𝐿 Β± 0 Β± 𝐢𝑑 Β± 𝐢𝑐 Β± 0 Β± 0 𝐿𝑐 = 𝐿 Β± 𝐢𝑑 Β± 𝐢𝑐 LADO A-B 𝐿𝑐 = 𝐿 Β± 𝐢𝑑 Β± 𝐢𝑐 TRAMO 1 𝐿𝑐 = (4,495 βˆ’0,00037758+4,90437E-05)π‘š 𝐿𝑐 =4,494671π‘š TRAMO 2 𝐿𝑐 = (5,365 βˆ’0,00045066+ 8,33879E-05)π‘š 𝐿𝑐 =5,364633π‘š TRAMO 3 𝐿𝑐 = (3,354 βˆ’0,000281736+2,03743E-05)π‘š 𝐿𝑐 =3,353739π‘š TRAMO 4 𝐿𝑐 = (4,219 βˆ’0,000354396+4,05529E-05)π‘š 𝐿𝑐 =4,218686π‘š TRAMO 5 𝐿𝑐 = (4,4 βˆ’0,0003696+4,59994E-05)π‘š 𝐿𝑐 =4,399676π‘š 𝐿𝑐 = 𝐿𝑐1 + 𝐿𝑐2 + 𝐿𝑐3 + 𝐿𝑐4 + 𝐿𝑐5 𝐿𝑐 = (4,494671 + 5,364633 + 3,353739 + 4,218686 + 4,399676)π‘š 𝐿𝑐 = 21,83141π‘š

LADO B-C 𝐿𝑐 = 𝐿 Β± 𝐢𝑑 Β± 𝐢𝑐 TRAMO 1 𝐿𝑐 = (5,933 βˆ’ 0,000498372 + 0,000112776)π‘š 𝐿𝑐 = 5,932614π‘š TRAMO 2 𝐿𝑐 = (5,206 βˆ’0,000437304+ 7,61915E-05)π‘š 𝐿𝑐 = 5,205639π‘š TRAMO 3 𝐿𝑐 = (4,864 βˆ’ 0,000408576 + 6,21405E βˆ’ 05)π‘š 𝐿𝑐 = 4,863654π‘š TRAMO 4 𝐿𝑐 = (3,986 βˆ’ 0,000354396 + 3,41984E βˆ’ 05)π‘š 𝐿𝑐 = 3,985699π‘š TRAMO 5 𝐿𝑐 = (4,130 βˆ’ 0,00034692 + 3,80403E βˆ’ 05)π‘š 𝐿𝑐 = 4,129691π‘š 𝐿𝑐 = 𝐿𝑐1 + 𝐿𝑐2 + 𝐿𝑐3 + 𝐿𝑐4 + 𝐿𝑐5 𝐿𝑐 = (5,932614 + 5,205639 + 4,863654 + 3,985699 + 4,129691)π‘š 𝐿𝑐 = 24,1173π‘š

LADO C-D 𝐿𝑐 = 𝐿 Β± 𝐢𝑑 Β± 𝐢𝑐 TRAMO 1 𝐿𝑐 = (2,903 βˆ’ 0,000243852 + 1,3211E βˆ’ 05)π‘š 𝐿𝑐 = 2,902769π‘š TRAMO 2 𝐿𝑐 = (4,887 βˆ’ 0,000410508 + 6,30261E βˆ’ 05)π‘š 𝐿𝑐 = 4,886653π‘š TRAMO 3 𝐿𝑐 = (3,686 βˆ’ 0,000309624 + 2,70433E βˆ’ 05)π‘š 𝐿𝑐 = 3,685717π‘š TRAMO 4 𝐿𝑐 = (4,819 βˆ’ 0,000404796 + 6,04317E βˆ’ 05)π‘š 𝐿𝑐 = 4,818656π‘š TRAMO 5 𝐿𝑐 = (3,879 βˆ’ 0,000325836 + 3,15176E βˆ’ 05)π‘š 𝐿𝑐 = 3,878706π‘š

𝐿𝑐 = 𝐿𝑐1 + 𝐿𝑐2 + 𝐿𝑐3 + 𝐿𝑐4 + 𝐿𝑐5 𝐿𝑐 = (2,902769 + 4,886653 + 3,685717 + 4,818656 + 3,878706)π‘š 𝐿𝑐 = 20,1725π‘š

LADO D-E 𝐿𝑐 = 𝐿 Β± 𝐢𝑑 Β± 𝐢𝑐 TRAMO 1 𝐿𝑐 = (4,185 βˆ’ 0,00035154 + 0,00035154)π‘š 𝐿𝑐 = 4,18468804π‘š TRAMO 2 𝐿𝑐 = (5,248 βˆ’ 0,000440832 + 7,80504E βˆ’ 05)π‘š 𝐿𝑐 = 5,2476372π‘š TRAMO 3 𝐿𝑐 = (4,968 βˆ’ 0,000417312 + 6,62123E βˆ’ 05)π‘š 𝐿𝑐 = 4,9676489π‘š TRAMO 4 𝐿𝑐 = (5,733 βˆ’ 0,000481572 + 0,000101751)π‘š 𝐿𝑐 = 5,73262018π‘š 𝐿𝑐 = 𝐿𝑐1 + 𝐿𝑐2 + 𝐿𝑐3 + 𝐿𝑐4 𝐿𝑐 = (4,18468804 + 5,2476372 + 4,9676489 + 5,73262018)π‘š 𝐿𝑐 = 20,1325943π‘š LADO E-A 𝐿𝑐 = 𝐿 Β± 𝐢𝑑 Β± 𝐢𝑐 TRAMO 1 𝐿𝑐 = (4,445 βˆ’ 0,00037338 + 4,74252E βˆ’ 05)π‘š 𝐿𝑐 = 4,44467405π‘š TRAMO 2 𝐿𝑐 = (5,068 βˆ’ 0,000425712 + 7,02916E05)π‘š 𝐿𝑐 = 5,06764458π‘š TRAMO 3 𝐿𝑐 = (4,798 βˆ’ 0,000403032 + 5,96451E βˆ’ 05)π‘š 𝐿𝑐 = 4,79765661π‘š 𝐿𝑐 = 𝐿𝑐1 + 𝐿𝑐2 + 𝐿𝑐3 𝐿𝑐 = (4,44467405 + 5,06764458 + 4,79765661)π‘š 𝐿𝑐 = 14,3099752π‘š

PERIMETRO 𝑃 = 𝐿𝐢𝐴𝐡 + 𝐿𝐢𝐢𝐡 + 𝐿𝐢𝐢𝐷 + 𝐿𝐢𝐷𝐸 + 𝐿𝐢𝐸𝐴 𝑃 = (21,83141 + 24,1173 + 20,1725 + 20,1325943 + 14,3099752)m 𝑃 = 100,563773m

ο‚·

PROCESO DE ANGULOS INTERIORES Puntos

Distancia total

EstaciΓ³n A B C D E

Visado B C D E A

CALCULO DE ANGULO INTERIOR Azimut directo Azimut inverso 195 165 100 260 38 322 305 55 253 107

21,833 24,119 20,174 20,134 14,311 E

A

AzE-A=253ΒΊ

AzA-B=195ΒΊ

D AzD-E=305ΒΊ

B

AzB-C=100ΒΊ

AzC-D=38ΒΊ C

DESDE AQUÍ PARA ABAJO FALTAN REALIZAR LOS CALCULOS CALCULO DE LOS ANGULOS INTERIORES A ABαint B

270α΅’-201α΅’

282α΅’-270 α΅’

270α΅’-201α΅’

ABΞ±int (270-201) α΅’=69α΅’ (282-270) α΅’= 12α΅’ ABΞ±int = (180-69-12) α΅’ ABΞ±int= 99α΅’

BCΞ±int

C B 270α΅’-210α΅’

12α΅’

BCΞ±int 270α΅’-210α΅’= 60α΅’ BCΞ±int = (180-60-12) α΅’ BCΞ±int = 108α΅’

CDΞ±int

C

D

276α΅’-270α΅’

60α΅’

60α΅’

276α΅’-270α΅’= 6α΅’ CDΞ±int = (180-6-60) α΅’

CDΞ±int =114α΅’ ADΞ±int

(n-2)*180=Ξ±int 180(4-2)=360α΅’ SUMATORIA DeΞ±int= ABΞ±int + BCΞ±int + CDΞ±int +ADΞ±int AdΞ±int= SUMATORIA DeΞ±int- AbΞ±int- BCΞ±int- CdΞ±int AdΞ±int= 360α΅’-99α΅’- 108α΅’-114α΅’ AdΞ±int= 39α΅’

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