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PRESION[πππβππ2 ]
PRESION[ππ]
1
1016.0
97.7
938.1
4.0
5.70
1.10
107873
2
981.5
196.0
967.8
4.8
6.50
1.38
135331,8
3
991.5
968.8
981.5
5.2
6.80
1.50
147100
4
1032.0
800.9
1022.0
5.5
7.40
1.85
176520
5
1868.0
1564.0
1864.0
5.0
7.85
2.15
210843
NΒ°
CALCULO DE LOS DATOS Calculando la velocidad angular: π=
ππ + π·ππ€π [πππ] 2
π1 =
1016.0 + 97.7 πππ£ 2π[πππ] 1[πππ] = 556.85 [ Γ = 58.31[πππβπ ] ]Γ 2 πππ 1[πππ£] 60[π ]
π2 =
981.5 + 196.0 πππ£ 2π[πππ] 1[πππ] = 588.75 [ Γ = 61.65[πππβπ ] ]Γ 2 πππ 1[πππ£] 60[π ]
π3 =
991.5 + 968.8 πππ£ 2π[πππ] 1[πππ] = 980.15 [ Γ = 102.64[πππβπ ] ]Γ 2 πππ 1[πππ£] 60[π ]
π4 =
1032.0 + 800.9 πππ£ 2π[πππ] 1[πππ] = 916.45 [ Γ = 95.97[πππβπ ] ]Γ 2 πππ 1[πππ£] 60[π ]
π5 =
1868.0 + 1564.0 πππ£ 2π[πππ] 1[πππ] = 1716 [ Γ = 176.70[πππβπ ] ]Γ 2 πππ 1[πππ£] 60[π ]
Calculando la velocidad angular promedio: W=99.054 CALCULO DEL CAUDAL π1 =
5.70[π£π’πππ‘ππ ] 10[ππ ππππππ ] 0.001[π3 ] 1βπππβ 3 Γ Γ Γ = 0.00095 βπ βπ β 1βπππβ 1[π£π’πππ‘π] 1[ππ ππππππ ] 60βπ β
π2 =
6.50[π£π’πππ‘ππ ] 10[ππ ππππππ ] 0.001[π3 ] 1βπππβ 3 Γ Γ Γ = 0.00108 βπ βπ β 1βπππβ 1[π£π’πππ‘π] 1[ππ ππππππ ] 60βπ β
π3 =
6.80[π£π’πππ‘ππ ] 10[ππ ππππππ ] 0.001[π3 ] 1βπππβ 3 Γ Γ Γ = 0.00113 βπ βπ β 1βπππβ 1[π£π’πππ‘π] 1[ππ ππππππ ] 60βπ β
π4 =
7.40[π£π’πππ‘ππ ] 10[ππ ππππππ ] 0.001[π3 ] 1βπππβ 3 Γ Γ Γ = 0.00123 βπ βπ β 1βπππβ 1[π£π’πππ‘π] 1[ππ ππππππ ] 60βπ β
π5 =
7.85[π£π’πππ‘ππ ] 10[ππ ππππππ ] 0.001[π3 ] 1βπππβ 3 Γ Γ Γ = 0.00131 βπ βπ β 1βπππβ 1[π£π’πππ‘π] 1[ππ ππππππ ] 60βπ β
CALCULO DE LAS POTENCIAS 1. ππ = ππ Γ π [π] ππ = 107873 Γ 0.00095 = 102.48 [π] ππππ = ππ Γ 0.7 [π] ππππ = 102.48 Γ 0.7 = 71.74[π] ππΊππ = ππππ Γ 0.6 [π] ππΊππ = 71.74 Γ 0.6 = 43.04[π] ππΈπππ = π Γ πΌ [π] ππΈπππ = [π] 2. ππ = ππ Γ π [π] ππ = 135331,8 Γ 0.00108 = 146.16 [π] ππππ = ππ Γ 0.7 [π] ππππ = 146.16 Γ 0.7 = 102.31[π] ππΊππ = ππππ Γ 0.6 [π] ππΊππ = 102.31 Γ 0.6 = 61.39[π] ππΈπππ = π Γ πΌ [π] ππΈπππ = [π] 3. ππ = ππ Γ π [π] ππ = 147100 Γ 0.00113 = 166.22[π] ππππ = ππ Γ 0.7 [π] ππππ = 166.22 Γ 0.7 = 116.36[π] ππΊππ = ππππ Γ 0.6 [π] ππΊππ = 116.36 Γ 0.6 = 69.81[π] ππΈπππ = π Γ πΌ [π] ππΈπππ = [π] 4. ππ = ππ Γ π [π] ππ = 176520 Γ 0.00123 = 217.12[π]
ππππ = ππ Γ 0.7 [π] ππππ = 217.12 Γ 0.7 = 151.98 [π] ππΊππ = ππππ Γ 0.6 [π] ππΊππ = 151.98 Γ 0.6 = 91.19[π] ππΈπππ = π Γ πΌ [π] ππΈπππ = [π] 5. ππ = ππ Γ π [π] ππ = 210843 Γ 0.00131 = 276.20[π] ππππ = ππ Γ 0.7 [π] ππππ = 276.20 Γ 0.7 = 193.34[π] ππΊππ = ππππ Γ 0.6 [π] ππΊππ = 193.34 Γ 0.6 = 116.01 [π] ππΈπππ = π Γ πΌ [π] ππΈπππ = [π] Calculando el promedio de ππ : ππ = 181.64 CALCULO DEL TORQUE π π = 0.7 =
ππππ π Γ π 0.7 Γ ππ Γ π 0.7 Γ 181.64 = βπ= = = 1.28 ππ ππ Γ π π 99.054