Calculos Fluidos.docx

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Datos: ๐บ๐‘’๐‘™ = 11

๐œƒ30 = 42

๐บ = 24

๐œƒ60 = 61

๐œƒ300 = 164

๐œƒ100 = 89 ๐œƒ100 = 156

๐œƒ600 = 193

TVD = 12031 ft cgs= 10786 ft OD= 9,625 โ€œ ID= 8,835 โ€œ ID= 8,625 trรฉpano tuberรญa OD= 4, 5 โ€œ BHA= 397 ft

ID= 3,826 โ€œ OD= 7โ€

ID= 2, 25 โ€œ

Tramo I ๐œƒ600 ๐’๐‘ท = 3.32 log ( ) ๐œƒ300 193 ๐’๐‘ท = 3.32 log ( ) 164 ๐’๐‘ท = ๐ŸŽ, ๐Ÿ๐Ÿ‘๐Ÿ“ ๐’Œ๐‘ท =

5,71 ๐œƒ600 1022๐‘›๐‘

๐’Œ๐‘ท =

5,71 โˆ— 193 10220,235

๐’Œ๐‘ท = ๐Ÿ๐Ÿ๐Ÿ”, ๐Ÿ๐Ÿ“๐Ÿ– Auxiliares ๐œƒ600 = ๐œƒ300 + ๐‘‰๐‘ ๐‘‰๐‘ = ๐œƒ600 + ๐œƒ300

๐‘‰๐‘ = 193 โˆ’ 164 ๐‘ฝ๐’‘ = ๐Ÿ๐Ÿ— ๐‘ƒ๐ถ = ๐œƒ300 + ๐‘‰๐‘ ๐‘ƒ๐ถ = 164 โˆ’ 29 ๐‘ท๐‘ช = ๐Ÿ๐Ÿ‘๐Ÿ“ Hallar Q bomba ๐‘‰๐‘ =

24,48 ๐‘„ ๐ท2

๐‘„=

๐‘„=

๐‘‰๐‘ƒ ๐ท2 24,48

29 โˆ— (4,52 ) 24,48

๐‘ธ = ๐Ÿ๐Ÿ‘, ๐Ÿ—๐Ÿ–๐Ÿ— ๐‘ฎ๐‘ท๐‘ด ๐‘๐‘’๐‘ = 100 โˆ— 216,258 (

1,6 โˆ— 29 0,235โˆ’1 3 โˆ— 0,235 + 1 0,235 ) ( ) 4,5 4 โˆ— 0,235

๐‘ต๐’†๐’‘ = ๐Ÿ’๐Ÿ๐Ÿ•๐Ÿ’, ๐Ÿ๐ŸŽ๐Ÿ– ๐‘๐‘Ÿ๐‘’๐‘ =

15,467 โˆ— 29 โˆ— 4,5 โˆ— 9,49 4174,108 ๐‘ต๐’“๐’†๐’‘ = ๐Ÿ’. ๐Ÿ“๐Ÿ–๐Ÿ—

LAMINAL ๐‘“๐‘ =

24 4,589

๐’‡๐’‘ = ๐Ÿ“, ๐Ÿ๐Ÿ‘๐Ÿ” ๐‘ƒ๐‘ =

5,230 โˆ— 292 โˆ— 9.49 โˆ— 11641 92916 โˆ— 4,5 ๐‘ท๐’‘ = ๐Ÿ๐Ÿ๐Ÿ”๐Ÿ, ๐Ÿ๐Ÿ๐Ÿ ๐’‘๐’”๐’Š

Tramo II ๐‘›๐‘ = 0,235 ๐พ๐‘ = 216,258 Hallar Q ๐‘„=

29 โˆ— 2,252 24,48

๐‘ธ = ๐Ÿ“, ๐Ÿ—๐Ÿ—๐Ÿ• ๐‘ฎ๐‘ท๐‘ด ๐‘๐‘’๐‘

1,6 โˆ— 29 0,235โˆ’1 3 โˆ— 0,235 + 1 0,235 = 100 โˆ— 216,258 ( ) ( ) 2,25 4 โˆ— 0,235 ๐‘ต๐’†๐’‘ = ๐Ÿ๐Ÿ’๐Ÿ“๐Ÿ” ๐‘๐‘Ÿ๐‘’๐‘ =

15,467 โˆ— 29 โˆ— 2,25 โˆ— 9,49 2456

๐‘ต๐’“๐’†๐’‘ = ๐Ÿ‘, ๐Ÿ—๐Ÿ”๐ŸŽ ๐‘ญ๐’๐’–๐’‹๐’ ๐’๐’‚๐’Ž๐’Š๐’๐’‚๐’“ ๐‘“๐‘’ =

24 3,9

๐’‡๐’‘ = ๐Ÿ”, ๐Ÿ๐Ÿ“๐Ÿ’ ๐‘ƒ2 =

6,154 โˆ— 292 โˆ— 9.49 โˆ— 11641 92916 โˆ— 2,25 ๐‘ท๐’‘ = ๐Ÿ”๐Ÿ. ๐Ÿ’๐Ÿ“๐Ÿ‘ ๐’‘๐’”๐’Š

Tramo III ๐œƒ100 ๐‘›๐‘Ž = 0,657๐ฟ๐‘œ๐‘” ( ) ๐œƒ3 89 ๐‘›๐‘Ž = 0,657๐ฟ๐‘œ๐‘” ( ) 42 ๐‘›๐‘Ž = 0,214 ๐พ๐‘Ž = ๐พ๐‘Ž =

5,11๐œƒ3 5,11๐‘›๐‘Ž

5,11 โˆ— 42 5,110,214

๐พ๐‘Ž = 151,380 ๐‘ฃ๐‘Ž =

24,48๐‘„ (๐ท22 โˆ’ ๐ท12 )

Operaciones auxiliares Asumiendo caudales como la sumatoria de los anteriores tramos Q = 29,986 = 30 GPM ๐‘ฃ๐‘Ž =

24,48 โˆ— 30 (8,6252 โˆ’ 72 )

๐’—๐’‚ = ๐Ÿ๐Ÿ–, ๐Ÿ—๐Ÿ๐Ÿ’ ๐’‡๐’•/๐’Ž๐’Š๐’ 2,4๐‘‰๐‘Ž (๐‘›๐‘Žโˆ’1) 2๐‘›๐‘Ž + 1 ๐‘›๐‘Ž ๐œ‡๐‘’๐‘Ž = 100๐พ๐‘Ž ( ) ( ) ๐ท2 โˆ’ ๐ท1 3๐‘›๐‘Ž

๐œ‡๐‘’๐‘Ž

2,4 โˆ— 28,924 (0,214โˆ’1) 2 โˆ— 0,214 + 1 0,214 = 100 โˆ— 151,380 โˆ— ( ) ( ) 8,625 โˆ’ 7 3 โˆ— 0,214 ๐๐’†๐’‚ = ๐Ÿ—๐Ÿ‘๐Ÿ—, ๐ŸŽ๐Ÿ–๐Ÿ ๐‘๐‘…๐‘’ =

๐‘๐‘…๐‘’ =

15,467 โˆ— ๐‘‰๐‘Ž โˆ— (๐ท2 โˆ’ ๐ท1 ) โˆ— ๐œŒ ๐œ‡๐‘’๐‘Ž

15,467 โˆ— 28,924 โˆ— (8,625 โˆ’ 7) โˆ— 9,49 989,082

๐‘๐‘…๐‘’ = 6,975

Flujo laminar ๐‘“๐‘Ž =

24 ๐‘๐‘…๐‘’

๐‘“๐‘Ž =

24 6,975

๐‘“๐‘Ž = 3,44 Para la caรญa de presiรณn ๐‘ƒ๐‘Ž = ๐‘ƒ๐‘Ž =

๐‘“๐‘Ž โˆ— ๐‘‰๐‘Ž2 โˆ— ๐œŒ โˆ— ๐ฟ๐‘š 92916(๐ท2 โˆ’ ๐ท1 )

3,44 โˆ— 28,9242 โˆ— 9,49 โˆ— 390 92916(8,625 โˆ’ 7)

๐‘ท๐’‚ = ๐Ÿ•๐ŸŽ, ๐Ÿ“๐Ÿ’๐Ÿ’ ๐’‘๐’”๐’Š Tamo IV ๐œƒ100 ๐‘›๐‘Ž = 0,657๐ฟ๐‘œ๐‘” ( ) ๐œƒ3 89 ๐‘›๐‘Ž = 0,657๐ฟ๐‘œ๐‘” ( ) 42 ๐‘›๐‘Ž = 0,214 ๐พ๐‘Ž = ๐พ๐‘Ž =

5,11๐œƒ3 5,11๐‘›๐‘Ž

5,11 โˆ— 42 5,110,214

๐พ๐‘Ž = 151,380 ๐‘ฃ๐‘Ž =

24,48๐‘„ (๐ท22 โˆ’ ๐ท12 )

Operaciones auxiliares Asumiendo caudales como la sumatoria de los anteriores tramos Q = 29,986 = 30 GPM ๐‘ฃ๐‘Ž =

24,48 โˆ— 30 (8,6252 โˆ’ 4,52 )

๐’—๐’‚ = ๐Ÿ๐Ÿ‘, ๐Ÿ“๐Ÿ”๐Ÿ“ ๐’‡๐’•/๐’Ž๐’Š๐’

2,4๐‘‰๐‘Ž (๐‘›๐‘Žโˆ’1) 2๐‘›๐‘Ž + 1 ๐‘›๐‘Ž ๐œ‡๐‘’๐‘Ž = 100๐พ๐‘Ž ( ) ( ) ๐ท2 โˆ’ ๐ท1 3๐‘›๐‘Ž

๐œ‡๐‘’๐‘Ž

2,4 โˆ— 13,565 (0,214โˆ’1) 2 โˆ— 0,214 + 1 0,214 = 100 โˆ— 151,380 โˆ— ( ) ( ) 8,625 โˆ’ 4,5 3 โˆ— 0,214 ๐๐’†๐’‚ = ๐Ÿ‘๐Ÿ“๐Ÿ’๐Ÿ, ๐Ÿ‘๐ŸŽ๐Ÿ‘ ๐‘๐‘…๐‘’ =

๐‘๐‘…๐‘’ =

15,467 โˆ— ๐‘‰๐‘Ž โˆ— (๐ท2 โˆ’ ๐ท1 ) โˆ— ๐œŒ ๐œ‡๐‘’๐‘Ž

15,467 โˆ— 13,565 โˆ— (8,625 โˆ’ 4,5) โˆ— 9,49 3541,303

๐‘๐‘…๐‘’ = 2,319

Flujo laminar ๐‘“๐‘Ž =

24 ๐‘๐‘…๐‘’

๐‘“๐‘Ž =

24 2,319

๐‘“๐‘Ž = 10,349 Para la caรญa de presiรณn ๐‘ƒ๐‘Ž =

๐‘“๐‘Ž โˆ— ๐‘‰๐‘Ž2 โˆ— ๐œŒ โˆ— ๐ฟ๐‘š 92916(๐ท2 โˆ’ ๐ท1 )

10,349 โˆ— 13,5652 โˆ— 9,49 ๐‘ƒ๐‘Ž = โˆ— 855 92916(8,625 โˆ’ 4,5)

๐‘ท๐’‚ = ๐Ÿ’๐ŸŽ, ๐Ÿ‘๐Ÿ๐Ÿ’ ๐’‘๐’”๐’Š

Tamo V ๐œƒ100 ๐‘›๐‘Ž = 0,657๐ฟ๐‘œ๐‘” ( ) ๐œƒ3 89 ๐‘›๐‘Ž = 0,657๐ฟ๐‘œ๐‘” ( ) 42 ๐‘›๐‘Ž = 0,214 ๐พ๐‘Ž = ๐พ๐‘Ž =

5,11๐œƒ3 5,11๐‘›๐‘Ž

5,11 โˆ— 42 5,110,214

๐พ๐‘Ž = 151,380 ๐‘ฃ๐‘Ž =

24,48๐‘„ (๐ท22 โˆ’ ๐ท12 )

Operaciones auxiliares Asumiendo caudales como la sumatoria de los anteriores tramos Q = 29,986 = 30 GPM ๐‘ฃ๐‘Ž =

24,48 โˆ— 30 (8,8352 โˆ’ 4,52 )

๐’—๐’‚ = ๐Ÿ๐Ÿ, ๐Ÿ•๐ŸŽ๐Ÿ’ ๐’‡๐’•/๐’Ž๐’Š๐’ 2,4๐‘‰๐‘Ž (๐‘›๐‘Žโˆ’1) 2๐‘›๐‘Ž + 1 ๐‘›๐‘Ž ๐œ‡๐‘’๐‘Ž = 100๐พ๐‘Ž ( ) ( ) ๐ท2 โˆ’ ๐ท1 3๐‘›๐‘Ž

๐œ‡๐‘’๐‘Ž

2,4 โˆ— 12,704 (0,214โˆ’1) 2 โˆ— 0,214 + 1 0,214 = 100 โˆ— 151,380 โˆ— ( ) ( ) 8,835 โˆ’ 4,5 3 โˆ— 0,214 ๐๐’†๐’‚ = ๐Ÿ‘๐Ÿ–๐Ÿ•๐Ÿ•, ๐ŸŽ๐Ÿ๐ŸŽ ๐‘๐‘…๐‘’ =

๐‘๐‘…๐‘’ =

15,467 โˆ— ๐‘‰๐‘Ž โˆ— (๐ท2 โˆ’ ๐ท1 ) โˆ— ๐œŒ ๐œ‡๐‘’๐‘Ž

15,467 โˆ— 12,704 โˆ— (8,835 โˆ’ 4,5) โˆ— 9,49 3877,020

๐‘๐‘…๐‘’ = 2,085

Flujo laminar ๐‘“๐‘Ž =

24 ๐‘๐‘…๐‘’

๐‘“๐‘Ž =

24 2,085

๐‘“๐‘Ž = 11,511 Para la caรญa de presiรณn ๐‘ƒ๐‘Ž = ๐‘ƒ๐‘Ž =

๐‘“๐‘Ž โˆ— ๐‘‰๐‘Ž2 โˆ— ๐œŒ โˆ— ๐ฟ๐‘š 92916(๐ท2 โˆ’ ๐ท1 )

11,511 โˆ— 12,7042 โˆ— 9,49 โˆ— 10786 92916(8,835 โˆ’ 4,5)

๐‘ท๐’‚ = ๐Ÿ’๐Ÿ•๐Ÿ, ๐Ÿ๐ŸŽ๐Ÿ– ๐’‘๐’”๐’Š

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