Universidad Nacional del Callao Facultad Ingeniería Mecánica Alumno: Milton Diaz Pérez
MANUFACTURA DE BROCA COSTO DE BROCA COSTOS VARIABLES Producto Terminado
Costo Total (s/.)
Costo Unitario (s/.)
Mano de obra Broca 22φx270mm - Barra redonda lisa A36 SAE1045 1” x 6 m
Unidad
1500
50
Unidad
38.74
1.769
3
Alquiler torno 1mx30cm
Unidad
300
37.5
4 5
Afilado herramienta Taxi
Unidad Unidad
2.5 16
2.5 25
6
Rollo bolsas 35x50 700 u
Paq
3.839
0.0054
7
Caja cartón 15x15x15 12u
Paq
1
0.08
S/.1862.079
S/.116.8544
Ítem 1 2
Descripción Materiales
Costo total
Ítem 1 2 3 4 5 6 7 8 9 10 11
COSTOS FIJOS Descripción materiales
Costo Total (s/.) 5500.00 4200.00 75.00 40.00 150.00 80.00 45.00 850.00 150.00
Sueldos Arriendo de locales Luz Agua Internet y telefonía Gastos administrativos Reparación y mantenimiento Personal de vigilancia Tributos (licencias, tasas municipales) Alquiler de vehículo Transporte Total
Ganancia 30% de precio de costo PV = Precio venta Cu =Costo unitario PV
=
Cu + Cu* 0.3
80.00 35.00 S/.11205.00
PV=
116.8544+ 116.8544*0.3
PV
=
S/.151.91
PV
= $ 46.03
CT = Costo total CF = Costo Fijo CV = Costo Variable CT = CF +CV CT = 1862.079+11205.00 CT = S/.13067.079 Dimensiones en bruto 25.4 φ x 274mm para mecanizar una broca a) Refrendado: 𝑉𝐶 = 25𝑚/𝑚𝑖𝑛
𝑉𝑐 =
𝜋∗𝐷∗𝑛 1000 𝜋∗25.4∗𝑛
25 =
→
1000
25 =
𝜋∗25.4∗𝑛
→ 𝑛 = 313𝑟𝑝𝑚
1000
Tiempo mecanizado de refrentado de cada extremo:
𝑡𝑚 =
(𝐿+𝑙𝑎 )∗𝑛𝑝
→
𝑎∗𝑛
𝑡𝑚 =
(2+5)∗2
→
0.1∗313
𝑡𝑚 = 0.447𝑚𝑖𝑚
Mecanizar puntos centro con n=700rpm
𝑉𝑐 =
𝜋∗𝐷∗𝑛
𝑡𝑚 =
→
1000
(𝐿+𝑙𝑎 )∗𝑛𝑝 𝑎∗𝑛
=
(4+5)∗1 0.2∗700
𝑉𝑐 =
𝜋∗25.4∗700 1000
→
→
𝑉𝑐 = 56𝑚/𝑚𝑖𝑛
𝑡𝑚 = 0.064𝑚𝑖𝑚
b) Desbastar desde 25.4 φ x178 hasta 20.9 φ x 178mm con: 𝑉𝐶 = 30𝑚/𝑚𝑖𝑛 ,
𝑎 = 0.5𝑚𝑚/𝑟𝑒𝑣
Numero pasadas → 30 =
𝑛𝑝 =
𝜋∗25.4∗𝑛
𝑡𝑚 =
→
1000
(𝐿+𝑙𝑎 )∗𝑛𝑝 𝑎∗𝑛
→
𝐷𝑂 −𝐷𝐹 2∗𝑝
=
25.4−20.9 2∗0.5
=5
𝑛 = 376𝑟𝑝𝑚
𝑡𝑚 =
(178+5)∗5 0.5∗376
→
𝑡𝑚 = 4.87min
Mecanizar acanalado desde 25.4φx10 hasta 17.5φx10mm con: 𝑉𝐶 = 18𝑚/𝑚𝑖𝑛 ,
𝑎 = 0.2𝑚𝑚/𝑟𝑒𝑣
Numero pasadas →
18 =
𝑡𝑚 =
𝑛𝑝 =
𝜋∗25.4∗𝑛 1000 (𝐿+𝑙𝑎 )∗𝑛𝑝 𝑎∗𝑛
𝐷𝑂 −𝐷𝐹 2∗𝑝
→ →
𝑡𝑚 =
=
25.4−17.5 2∗0.2
= 20
𝑛 = 326𝑟𝑝𝑚 (10+5)∗20 0.2∗326
→
𝑡𝑚 = 4.60min
c) Mecanizar dos chaflanes en 45°con:
𝑉𝑐 =
25𝑚
,
𝑚𝑖𝑛
𝑉𝑐 =
𝑎 = 0.2𝑚𝑚/𝑟𝑒𝑣
𝜋∗𝐷∗𝑛 1000 𝜋∗20.4∗𝑛
25 =
1000
𝑡𝑚 =
(𝐿+𝑙𝑎 )∗𝑛𝑝 𝑎∗𝑛
→
→
𝑛 = 390𝑟𝑝𝑚
𝑡𝑚 =
(2+5)∗1 0.2∗390
→
𝑡𝑚 = 0.089min
→
𝑡𝑚 = 4.05min
Invertir cogida d) Desbastar desde 25.4∅x 82 hasta 19φx82mm 𝑉𝑐 = 24𝑚/𝑚𝑖𝑛,
𝑎 = 0.5𝑚𝑚/𝑟𝑒𝑣
Numero pasadas →
𝑛𝑝 =
𝑉𝑐 =
𝐷𝑂 −𝐷𝐹 2∗𝑝
=
25.4−17.5 2∗0.5
= 7
𝜋∗𝐷∗𝑛 1000 𝜋∗25.4∗𝑛
24 =
1000
𝑡𝑚 =
(𝐿+𝑙𝑎 )∗𝑛𝑝 𝑎∗𝑛
→
→
𝑛 = 301𝑝𝑚
𝑡𝑚 =
(82+5)∗7 0.5∗301
e) Desbastar cono de19φx82 hasta 14φx82 Inclinación I =
D−d 2∗l
→ I=
19−14
→
2∗82
𝑉𝑐 = 20𝑚/𝑚𝑖𝑛,
𝑎 = 0.5𝑚𝑚/𝑟𝑒𝑣
Numero pasadas →
𝑛𝑝 =
𝑉𝑐 = 20 =
𝐷𝑂 −𝐷𝐹 2∗𝑝
=
19−14 2∗0.5
𝜋∗𝐷∗𝑛 1000 𝜋∗19∗𝑛 1000
→
𝑛 = 335𝑝𝑚
I = 5/164 = 5
𝑡𝑚 =
(𝐿+𝑙𝑎 )∗𝑛𝑝 𝑎∗𝑛
→
𝑡𝑚 =
(82+5)∗5 0.5∗335
→
𝑡𝑚 = 3.59min
→
𝑡𝑚 = 0.299min
→
𝑡𝑚 = 0.01min
f) Desbastar cono 14φx14.6 hasta 19.5φx14.6mm con: 𝑉𝑐 = 30𝑚/𝑚𝑖𝑛, 𝑉𝑐 =
𝑎 = 0.1𝑚𝑚/𝑟𝑒𝑣
𝜋∗𝐷∗𝑛 1000 𝜋∗14.6∗𝑛
30 =
1000
𝑡𝑚 =
(𝐿+𝑙𝑎 )∗𝑛𝑝 𝑎∗𝑛
→
→
𝑛 = 654𝑝𝑚
𝑡𝑚 =
(14.6+5)∗1 0.1∗654
g) Chaflán con ángulo de 8°
𝑉𝑐 = 𝑉𝑐 =
25𝑚 𝑚𝑖𝑛
,
𝑎 = 0.2𝑚𝑚/𝑟𝑒𝑣
→
𝑛 = 568𝑝𝑚
𝜋∗𝐷∗𝑛 1000 𝜋∗14∗𝑛
25 =
1000
𝑡𝑚 =
(𝐿+𝑙𝑎 )∗𝑛𝑝 𝑎∗𝑛
→
𝑡𝑚 =
(0.5+5)∗1 0.1∗568
ACABADO h) Acabado desbastar cono 14φx67.4 y 19φx67.4 hasta 13.9φx67.4 y 18.3φ 67.4con:
𝑉𝑐 =
32𝑚 𝑚𝑖𝑛 𝜋∗19∗𝑛
32 =
1000
𝑡𝑚 =
(𝐿+𝑙𝑎 )∗𝑛𝑝 𝑎∗𝑛
,
𝑎 = 0.1𝑚𝑚/𝑟𝑒𝑣
→
𝑛 = 536𝑝𝑚
→
𝑡𝑚 =
(67.4+5)∗1 0.1∗536
→
𝑡𝑚 = 1.353min
→
𝑡𝑚 = 0.051min
Cilindrado Acabado desbastar 17.5φx10 hasta 17φx10mm con:
𝑉𝑐 =
32𝑚
32 =
𝑡𝑚 =
𝑚𝑖𝑛 𝜋∗17.5∗𝑛 1000 (𝐿+𝑙𝑎 )∗𝑛𝑝 𝑎∗𝑛
,
𝑎 = 0.5𝑚𝑚/𝑟𝑒𝑣
→
𝑛 = 583𝑝𝑚
→
𝑡𝑚 =
(10+5)∗1 0.5∗583
Acabado desbastar 20.9φx178 hasta 20.4 φx178mm con:
𝑉𝑐 =
30𝑚 𝑚𝑖𝑛 𝜋∗20.9∗𝑛
30 =
𝑡𝑚 =
1000 (𝐿+𝑙𝑎 )∗𝑛𝑝 𝑎∗𝑛
,
𝑎 = 0.5𝑚𝑚/𝑟𝑒𝑣
→
𝑛 = 457𝑝𝑚
𝑡𝑚 =
→
(178+5)∗1 0.5∗457
→
𝑡𝑚 = 0.80min
→
𝑡𝑚 = 0.278min
Acabado desbastar 14φx14 hasta 13.9φx14mm con:
𝑉𝑐 =
30𝑚
30 =
𝑡𝑚 =
𝑚𝑖𝑛 𝜋∗14∗𝑛 1000 (𝐿+𝑙𝑎 )∗𝑛𝑝 𝑎∗𝑛
,
𝑎 = 0.1𝑚𝑚/𝑟𝑒𝑣
→
𝑛 = 682𝑝𝑚
→
𝑡𝑚 =
(14+5)∗1 0.1∗682
Tiempo total de mecanizado: 2(0.447)+0.064+9.7+1.56+0.089+7.51+5.194+0.299+0.01+1.353+0.051+ 0.8+0.278 = 37.802min
Tiempo total = 37.802min