Assignments

  • November 2019
  • PDF

This document was uploaded by user and they confirmed that they have the permission to share it. If you are author or own the copyright of this book, please report to us by using this DMCA report form. Report DMCA


Overview

Download & View Assignments as PDF for free.

More details

  • Words: 3,307
  • Pages: 36
;---------------------------------------------------------------------------; PROGRAM TO ADD N NUMBERS OF GIVEN ARRAY ; SE-I ROLL NO:-2123 Assignment no 1 ;---------------------------------------------------------------------------.model small .stack 50 .data arr db 0f0h,0f0h,0f0h,0f0h,0f0h cnt db 04 msg db 0ah,0dh,'Addition of result is $' .code mov ax,@data mov ds,ax mov cl,5 mov dx,0000h lea si,arr l1: add dl,[si] jnc l2 inc dh l2: inc si dec cl jnz l1 mov bx,dx mov cx,0404h lea dx,msg mov ah,09 int 21h l3: rol bx,cl mov dl,bl and dl,0fh cmp dl,09 jbe l4 add dl,07 l4: add dl,30h mov ah,02

int 21h dec cnt jnz l3 mov ah,4ch int 21h end ;---------------------------------------------------OUTPUT Addition of result is 04B4 ;----------------------------------------------------

;Program for Non-Overlapping and Overlapping data Transfer ;Roll No.:-2123 Assignment No.:-2 ;------------------------------------------------------------------------------.model small display1 macro msg ;Macro for Display string lea dx,msg mov ah,09 int 21h endm .stack 100 .data org 100h ;Offset arr db 10h,20h,30h,40h,50h,60h,70h,80h,90h,95h cnt db 04 cnt2 db 10 cnt1 db 02 msg1 db 10,13,'1. X+5$' msg2 db 10,13,'2. x-5$' msg3 db 10,13,'3. Non Overlapping$' msg4 db 10,13,'Enter Your Choice :$' msg5 db 10,13,'Address Value before transfer of data',10,13,'$' msg6 db 10,13,'Address Value after transfer of data',10,13,'$' msg7 db 10,13,'$' msg8 db ' $' .code mov ax,@data mov ds,ax mov es,ax display1 msg1 display1 msg2 display1 msg3 display1 msg5 lea si,arr label3: call display2 inc si display1 msg7 dec cnt2 jnz label3 display1 msg4

mov ah,01 int 21h cmp al,31h jne l2 call addfive mov cnt2,10 add si,06 display1 msg6 label32: call display2 inc si display1 msg7 dec cnt2 jnz label32 jmp l5 l2: cmp al,32h jne l4 call subfive mov cnt2,10 sub di,10 mov si,di display1 msg6 label33: call display2 inc si display1 msg7 dec cnt2 jnz label33 jmp l5 l4: lea si,arr mov di,si add di,100h mov cx,0010 l6: mov dl,[si] mov [di],dl inc si inc di loop l6 mov cnt2,10

sub di,10 mov si,di display1 msg6 label34: call display2 inc si display1 msg7 dec cnt2 jnz label34 l5: mov ah,4ch int 21h addfive proc near ;Procedure For Overlapp +5 data transfer mov cx,0010 lea si,arr mov di,si add si,09 add di,14 l1: mov dl,[si] mov [di],dl dec si dec di loop l1 retn addfive endp subfive proc near ;Procedure For Overlapp -5 data transfer lea si,arr mov di,si sub di,04 mov cx,0010 l3: mov dl,[si] mov [di],dl inc si inc di loop l3 retn subfive endp jmp l5 display2 proc near ;Procedure to display addresses and Values at that address mov ch,[si] mov bx,si mov cl,04 mov cnt,cl

mov cnt1,02 label1: rol bx,cl mov dl,bl and dl,0fh cmp dl,09 jbe label2 add dl,07 label2: add dl,30h mov ah,02 int 21h dec cnt jnz label1 display1 msg8 label31: rol ch,cl mov dl,ch and dl,0fh cmp dl,09 jbe label41 add dl,07 label41: add dl,30h mov ah,02 int 21h dec cnt1 jnz label31 retn endp end ;------------------------------------------------------------------------------OUTPUT E:\Sachin>cd tasm E:\Sachin\tasm>edit assign2.asm E:\Sachin\tasm>tasm assign2.asm Turbo Assembler Version 2.0 Copyright (c) 1988, 1990 Borland International Assembling file: assign2.asm Error messages: None Warning messages: None Passes: 1 Remaining memory: 439k

E:\Sachin\tasm>tlink assign2.obj Turbo Link Version 3.0 Copyright (c) 1987, 1990 Borland International E:\Sachin\tasm>assign2.exe 1. X+5 2. x-5 3. Non Overlapping Address Value before transfer of data 0100 10 0101 20 0102 30 0103 40 0104 50 0105 60 0106 70 0107 80 0108 90 0109 95 Enter Your Choice :1 Address Value after transfer of data 0105 10 0106 20 0107 30 0108 40 0109 50 010A 00 010B 04 010C 00 010D 90 010E 95 Enter Your Choice :2 Address Value after transfer of data 00FC 10 00FD 20 00FE 30 00FF 40 0100 50 0101 60 0102 70 0103 80 0104 90 0105 95 E:\Sachin\tasm>assign2.exe Enter Your Choice :3

Address Value after transfer of data 0200 10 0201 20 0202 30 0203 40 0204 50 0205 60 0206 70 0207 80 0208 90 0209 95 ;------------------------------------------------------------------------------

;------------------------------------------------------------------------------; Program to find Total number of positive, Negative & zeroes ; in given Array ;Roll No:-2123 Assignment no.:-3 ;------------------------------------------------------------------------------.model small .stack 100 disp macro msg5 lea dx,msg5 mov ah,09 int 21h endm .data org 100h arr db 00,08,00,-4,-7,-1,-2,03 ;Given Array cnt db 04 cntp db 00 ;Conter to Positive Numbers cntn db 00 ;Conter to Negative Numbers cntz db 00 ;Counter to Zero number msg1 db 10,13,'Number of Zeroes :$' msg2 db 10,13,'Number of Positive integers :$' msg3 db 10,13,'Number of Negative integers :$' .code mov ax,@data mov ds,ax mov cx,0008 mov bx,0000h lea si,arr l1: mov ah,[si] shl ah,01 ;Check for Carry jc l2 cmp ah,00 ;If result of compare not equal then No. is +ve je l3 jne l5 l2: inc cntn l4: inc si loop l1

;Increment Counter

jmp l7 l6: ;To teminata from DOS mov ah,4ch int 21h l3: inc cntz jmp l4 l5: inc cntp jmp l4 l7: disp msg1 mov bl,cntz call disp1 disp msg2 mov bl,cntp call disp1 disp msg3 mov bl,cntn call disp1 jmp l6 disp1 proc near ;Procedure To display Counter mov cnt,04 mov cl,04 mov dx,0000 label1: rol bx,cl mov dl,bl and dl,0fh cmp dl,09 jbe label2 add dl ,07 label2: add dl,30h mov ah,02 int 21h dec cnt jnz label1 retn endp end

------------------------------------------------------------------------------OUTPUT Microsoft Windows XP [Version 5.1.2600] (C) Copyright 1985-2001 Microsoft Corp. D:\Documents and Settings\ABC>e: E:\>cd sachin E:\Sachin>cd tasm E:\Sachin\tasm>tasm assign3.asm Turbo Assembler Version 2.0 Copyright (c) 1988, 1990 Borland International Assembling file: assign3.asm Error messages: None Warning messages: None Passes: 1 Remaining memory: 441k E:\Sachin\tasm>tlink assign3.obj Turbo Link Version 3.0 Copyright (c) 1987, 1990 Borland International E:\Sachin\tasm>assign3.exe Number of Zeroes :0002 Number of Positive integers :0002 Number of Negative integers :0004 -------------------------------------------------------------------------------

;Program to conver given HEX number into BCD form ; and BCD number into HEX Number ;assignment no:-4 ROLL NO.-2123 ;----------------------------------------------------.model small disp_str macro msg ;macro to display string lea dx,msg mov ah,09 int 21h endm disp macro l3: mov ah,01 int 21h rol bx,cl sub al,30h cmp al ,09 jbe l2 sub al,07 and al,0fh l2: add bl,al dec cnt jnz l3

;Macro to accept HEX no.

endm .stack 100 .data msg1 db 10,13,'Enter HEX Number $' msg2 db 10,13,'BCD number is $' msg3 db 10,13,'1-HEX to BCD',10,13,'2-BCD to HEX $' msg4 db 10,13,'Enter your choice :$' msg5 db 10,13,'Enter BCD Number $' msg6 db 10,13,'HEX number is $' cnt db 04 cnt1 db 00 pow dw 2710h fact dw 000Ah result dw 0000 .code mov ax,@data mov ds,ax

disp_str msg3 disp_str msg4 mov ah,01 int 21h sub al,30h cmp al,1 jne choice2 disp_str msg1 mov bx,0000h mov cx,0404 disp mov ax,bx mov cx,000ah mov cnt1,0 label1: mov dx,0000 div cx push dx inc cnt1 cmp ax,0000 jne label1

;procedure to convert HEX into BCD

;Continue untill AX containts becomes 0

mov cx,0000 mov cl,cnt1 disp_str msg2 label2: mov dx,0000 pop dx cmp dx,09 jbe label3 add dx,07 label3: add dx,30h mov ah,02h int 21h loop label2 jmp l4

;procedure to Display BCD

choice2: disp_str msg5 mov cx,0005 label4: mov ax,0000 mov ah,01 int 21h sub al,30h

;procedure to convert BCD into HEX

mov ah,00 mul pow add result,ax mov ax,pow div fact mov pow,ax loop label4 disp_str msg6 mov bx,result mov cl,04 mov cnt,04 label5: ;procedure to Display HEX rol bx,cl mov dl,bl and dl,0fh cmp dl,09 jbe label6 add dl,07 label6: add dl,30h mov ah,02 int 21h dec cnt jnz label5 l4: mov ah,4ch int 21h end -----------------------OUTPUT-----------------------E:\Sachin\tasm>sassign4 1-HEX to BCD 2-BCD to HEX Enter your choice :1 Enter HEX Number ffff BCD number is 65535 1-HEX to BCD 2-BCD to HEX Enter your choice :1 Enter HEX Number 1234 BCD number is 4660 1-HEX to BCD 2-BCD to HEX Enter your choice :2

Enter BCD Number 65535 HEX number is FFFF 1-HEX to BCD 2-BCD to HEX Enter your choice :2 Enter BCD Number 04660 HEX number is 1234 E:\Sachin\tasm> -------------------------END--------------------------------

;-----------------------------------------------------------;Program to perform various operations on string ;Roll No:-2123 Assignment no.:-5 ;-----------------------------------------------------------.model small disp_str macro msg lea dx,msg mov ah,09 int 21h endm disp_int macro mov cnt,02 mov cl,04 l1: rol bl,cl mov dl,bl and dl,0fh cmp dl,09 jbe l2 add dl,07 l2: add dl,30h mov ah,02 int 21h dec cnt jnz l1 endm

;Macro to display string

;Macro to display Length

.stack 100 .data msg db 10,13,'********MENU*********$' msg1 db 10,13,'1-Enter string $' msg2 db 10,13,'2-Lenth :$' msg3 db 10,13,'3-Reverse $' msg4 db 10,13,'4-Palindrome$' msg5 db 10,13,'Given string is Palindrome$' msg6 db 10,13,'Given string is not Palindrome$' msg7 db 10,13,'Enter your choice:$' msg8 db 10,13,'5-Exit$' msg9 db 10,13,'$' msg12 db 10,13,'Enter string :$' msg22 db 10,13,'Lenth of string is :$' msg32 db 10,13,'Reverse of string is :$' msg41 db 10,13,'Given String is not Palindrome$' msg42 db 10,13,'Given String is Palindrome$' str1 db 20 dup('$')

str2 db 20 dup('$') cnt db 04 .code mov ax,@data mov ds,ax mov es,ax begin: disp_str msg9 disp_str msg disp_str msg1 disp_str msg2 disp_str msg3 disp_str msg4 disp_str msg8 disp_str msg7 mov ah,01 int 21h

;Program starts

;Wait until key enter from keyboard

sub al,30h cmp al,1 jne next1 call accept jmp begin next1: cmp al,2 jne next2 call len jmp begin next2: cmp al,3 jne next3 call rev jmp begin next3: cmp al,4 jne next4 call palindrome jmp begin next4: cmp al,5 je EXIT EXIT: mov ah,4ch

int 21h accept proc near disp_str msg9 disp_str msg12 mov ah,0ah lea dx,str1 int 21h retn endp len proc near disp_str msg9 disp_str msg22 lea si,str1+1 mov bx,[si] and bx,00ffh disp_int retn endp

;Procedure to accept String ;interrupt 0ah to accept String

;Procedure to find length

rev proc near ;Procedure to find Reverse of string disp_str msg32 lea si,str1+1 mov cx,[si] and cx,00ffh lea si,str1 lea di,str2 add si,cx add si,01 STD ;Set Direction Flag label1: movsb ;To move string si to di add di,02 loop label1 disp_str str2 retn endp palindrome proc near ;Procedure to check Palindrome condition lea si,str1+1 mov ax,[si] and ax,00ffh add si,01 mov di,si add di,ax sub di,01

;si points to 1st character ;di points to last char

mov bl,02 div bl ;CX contains loop bound value mov cl,al mov ch,00 CLD ;Reset Direction Flag label2: cmpsb ;Compare 1st & last char jne label3 sub di,02 loop label2 disp_str msg42 retn label3: disp_str msg41 retn endp end ------------------------------------------------------------------------------OUTPUT ********MENU********* 1-Enter string 2-Lenth : 3-Reverse 4-Palindrome 5-Exit Enter your choice:1 Enter string :PICT ********MENU********* 1-Enter string 2-Lenth : 3-Reverse 4-Palindrome 5-Exit Enter your choice:2 Lenth of string is :04 ********MENU********* 1-Enter string 2-Lenth : 3-Reverse 4-Palindrome 5-Exit Enter your choice:3 Reverse of string is :TCIP ********MENU*********

1-Enter string 2-Lenth : 3-Reverse 4-Palindrome 5-Exit Enter your choice:4 Given String is not Palindrome ********MENU********* 1-Enter string 2-Lenth : 3-Reverse 4-Palindrome 5-Exit Enter your choice:1 Enter string :MADAM ********MENU********* 1-Enter string 2-Lenth : 3-Reverse 4-Palindrome 5-Exit Enter your choice:4 Given String is Palindrome ********MENU********* 1-Enter string 2-Lenth : 3-Reverse 4-Palindrome 5-Exit Enter your choice:5 E:\Sachin\tasm> -------------------------------END----------------------------

;--------------------------------------------------------------------;Program to perform various operations on string. ;Roll No:-2123 Assignment no.:-6 ;--------------------------------------------------------------------.model small .stack 100 disp_str macro msg lea dx,msg mov ah,09 int 21h endm

;Macro to display string

.data msg db 10,13,'********MENU*********$' msg1 db 10,13,'1-Concatenation $' msg2 db 10,13,'2-Compare $' msg3 db 10,13,'3-Occurance of substring $' msg4 db 10,13,'4-Exit $' msg5 db 10,13,'Enter your choice :$' newline db 10,13,'$' str1 db 20 dup('$') str2 db 20 dup('$') .code mov ax,@data mov ds,ax mov es,ax public str1,str2 begin: disp_str newline disp_str msg disp_str msg1 disp_str msg2 disp_str msg3 disp_str msg4 disp_str msg5 mov ah,01 int 21h sub al,30h cmp al,01 jne next1 extrn concat:far call concat jmp begin

;Declaration of far Procedure

next1: cmp al,2 jne next2 extrn compare:far call compare jmp begin next2: cmp al,3 jne Exit extrn substring:far call substring jmp begin EXIT: mov ah,4ch int 21h public accept accept proc far mov ah,0ah mov dx,si int 21h retf endp

;Declaration of Public procedure

end ------------------------------------------------------------------------------OUTPUT ********MENU********* 1-Concatenation 2-Compare 3-Occurance of substring 4-Exit Enter your choice: 1 Enter 1st string PICT Enter 2nd string _SCTR Result of Concatenation is: PICT_SCTR Enter your choice: 2 Enter 1st string PICT Enter 2nd string SCTR Strings are not equal Enter your choice: 2 Enter 1st string PICT Enter 2nd string PICT Strings are equal Enter your choice: 3

Enter 1st string pictsctrpict Enter substring: pict Occurrence of substring is : 02 -------------------------------END---------------------------/***************PART II OF ASSIGN6 ***************/ .model small .stack 100 disp_str macro msg lea dx,msg mov ah,09 int 21h endm

;Macro to display string

disp_concat macro msg lea dx,msg+2 mov ah,09 int 21h endm accept_str macro msg disp_str msg1 lea si,str1 extrn accept:far call accept disp_str msg lea si,str2 call accept endm

;Macro to display string

;Macro to accept String

.data msg1 db 10,13,'Enter 1st string $' msg2 db 10,13,'Enter 2nd string $' msg3 db 10,13,'Result of Concatenation is :$' msg4 db 10,13,'Strings are not equal $' msg5 db 10,13,'Strings are equal $' msg6 db 10,13,'Enter substring :$' msg7 db 10,13,'Ocuranse of substring is : $' msg8 db 10,13,'String not Found$' newline db 10,13,'$' cnt db 00 cnt1 db 00 extrn str1:byte extrn str2:byte .code mov ax,@data

mov ds,ax mov es,ax public concat proc concat far accept_str msg2 lea di,str1+1 mov cx,[di] and cx,00ffh add di,cx lea si,str2+1 inc di mov cx,[si] inc si and cx,00ffh CLD l1: movsb loop l1 disp_str msg3 disp_concat str1 retf endp public compare proc compare far accept_str msg2 lea si,str1+1 lea di,str2+1 mov ch,[si] mov cl,[di] cmp ch,cl jne l2 inc si inc di CLD mov ch,00h repe cmpsb jne l2 disp_str msg5 je l3 l2: disp_str msg4 l3: retf endp public substring proc substring far accept_str msg6 lea si,str1+1

;Far procedure for Concatenation

;Far procedure for Compare of strings

;Far procedure to find occurrences of Substring

mov al,[si] inc si jmp l4 l5: mov ah,00h lea si,str1+1 mov al,[si] sub al,cnt1 lea si,str1+2 add si,ax mov al,cnt1 l4: lea di,str2+1 mov bl,[di] lea di,str2+2 l6: mov cl,[si] cmp cl,0Dh je l10 mov dl,[di] cmp cl,dl je l7 inc si dec al jnz l6 l7: dec al mov cnt1,al dec bl l8: inc di inc si mov cl,[si] cmp cl,0Dh je l10 mov dl,[di] cmp cl,dl jne l5 dec al dec bl jnz l8 inc cnt inc si

cmp al,00h jne l4 l10: disp_str msg7 mov cx,0204h mov bl,cnt l9: rol bl,cl mov dl,bl and dl,0fh cmp dl,09 jbe ll add dl,07 ll: add dl,30h mov ah,02h int 21h dec ch jnz l9 retf endp end

;--------------------------------------------------------------------;Program Sort Array in Ascending and Descending order ;Roll No:-2123 Assignment no.:-7 ;--------------------------------------------------------------------.model small disp_str macro msg ;macro to display string lea dx,msg mov ah,09 int 21h endm .stack 100 .data msg1 db 10,13,10,13,'Which operation do want to do $' msg2 db 10,13,'1-To sort Array in Ascending order $' msg3 db 10,13,'2-To sort Array in Descending order $' msg4 db 10,13,'3-EXIT $' msg5 db 10,13,'Enter your choice :$' msg6 db 10,13,'Original Array is',10,13,'$' msg7 db 10,13,'Array in ascending order is',10,13,'$' tab db ' $' arr db 5,50h,40h,20h,10h,60h ;Array to be sort cnt db 05 ;Counter cnt1 db 06 temp db ? ;For Swap .code mov ax,@data mov ds,ax mov es,ax disp_str msg6 call disp_arr

;To display original Array

begin: disp_str msg1 disp_str msg2 disp_str msg3 disp_str msg4 disp_str msg5 mov ah,01 int 21h sub al,30h cmp al,01 jne next1

;Accept Choice

mov cnt,05 mov cnt1,06 call ascending disp_str msg7 call disp_arr jmp begin next1: cmp al,02 jne next2 mov cnt,05 mov cnt1,06 call descending disp_str msg7 call disp_arr jmp begin

;Reinitialize count

;Display Sorted Array

;Reinitialise count

;Display Sorted Array

next2: jmp EXIT ascending proc near l: mov di,0001 l1: mov dl,[arr+di] cmp dl,[arr+di+1] ;Compare jbe l2 ;if 1st no is less then skip swap call swap l2: inc di mov ah,0 mov al,cnt1 dec al cmp ax,di ;cheks n value jnz l1 dec cnt jnz l retn endp descending proc near l4: mov di,0001 l5: mov dl,[arr+di] cmp dl,[arr+di+1] jg l6 call swap l6:

inc di mov ah,0 mov al,cnt1 dec al cmp ax,di jnz l5 dec cnt jnz l4 retn endp EXIT: mov ah,4ch int 21h swap proc near ;Procedure to swap mov ah,[arr+di+1] mov [arr+di],ah mov [arr+di+1],dl retn endp disp_arr proc near lea si,arr mov cl,04 mov cnt1,05 label1: disp_str tab inc si mov bx,[si] and bx,00ffh mov cnt,02 label2: rol bl,cl mov dl,bl and dl,0fh cmp dl,09 jbe label3 add dl,07 label3: add dl,30h mov ah,02 int 21h dec cnt jnz label2 dec cnt1 jnz label1 retn endp

;Procedure to display Array

end ------------------------------ OUTPUT ------------------------------------E:\Sachin\tasm>assign7 Original Array is 50 40 20 10 60 Which operations do want to do? 1-To sort Array in ascending order 2-To sort Array in Descending order 3-EXIT Enter your choice: 1 Array in ascending order is 10 20 40 50 60 Which operations do want to do? 1-To sort Array in ascending order 2-To sort Array in Descending order 3-EXIT Enter your choice: 2 Array in ascending order is 60 50 40 20 10 Which operations do want to do? 1-To sort Array in ascending order 2-To sort Array in Descending order 3-EXIT Enter your choice: 3 -------------------------------END-----------------------

;--------------------------------------------------------------------;Program for Multiplication of two 8 bit positive Numbers ;Roll No:-2123 Assignment no.:-8 ;--------------------------------------------------------------------.model small disp_str macro msg lea dx,msg mov ah,09h int 21h endm

;Macro to display String

.stack 100 .data msg1 db 10,13,'Enter Multiplicant :$' msg2 db 10,13,'Enter Multiplier :$' msg3 db 10,13,'Result of Multipliction is :$' multr db ? mult db ? ans dw 00 .code mov ax, @data mov ds,ax disp_str msg1 call accept mov mult,dl disp_str msg2 call accept mov multr,dl call multi mov ans,bx disp_str msg3 call disp_res jmp EXIT accept proc near mov cx,0204h mov dl,00h l1: mov ah,01 int 21h sub al,30h rol dl,cl add dl,al

;Call to Multiplicand Accept proc ; Call to Multiplier Accept proc ;Call to Multiplication Proc

dec ch jnz l1 retn endp multi proc near mov bh,00h mov bl,multr mov dl,mult mov ch,08 l2: test bl,01 ;testing last digit 1 or 0 jz shiftr ;If 1 then jump on shift right add bh,dl ;Add result shiftr: rcr bx,01 ;Rotate right dec ch jnz l2 retn endp disp_res proc near mov cx,0404h mov dl,00h mov bx,ans l3: rol bx,cl mov dl,bl and dl,0fh cmp dl,09 jbe l4 add dl,07 l4: add dl,30h mov ah,02 int 21h dec ch jnz l3 retn endp EXIT: mov ah,4ch int 21h end ------------------------ OUTPUT --------------------------Enter Multiplicand: 16 Enter Multiplier: 11 Result of Multiplication is: 0176 -------------------------------END---------------------------

;----------------------------------------------------------------------; Title:-Program to handle Divide by Zero Interrupt ; Class : SE-I ROLL No : 2123 Assignment No: 16 ;-----------------------------------------------------------------------.MODEL SMALL .CODE MOV AX,@DATA MOV DS,AX MOV AX,0FFFH MOV BX,0000H DIV BX MOV AH,4CH INT 21H END ----------------------- OUTPUT -------------------------------E:\SACHIN\TASM>assgn16.exe SORRY DIVIDE BY ZERO ERROR..!!!! Divide overflow ------------------------- END -----------------------------------******************* TSR POGRAM ******************* .MODEL TINY .CODE ORG 0100 START: JMP INIT SAVEINTO DD ? MSG DB "SORRY DIVIDE BY ZERO ERROR..!!!! $" RESI: PUSH AX PUSH BX PUSH CX PUSH DX PUSH CS POP DS LEA DX,MSG MOV AH,09H INT 21H POP DX POP CX POP BX POP AX

JMP CS:SAVEINTO INIT: CLI PUSH CS POP DS MOV AH,35H MOV AL,00H INT 21H MOV WORD PTR CS:SAVEINTO,BX MOV WORD PTR CS:SAVEINTO+2,ES MOV AH,25H MOV AL,00H MOV DX,OFFSET RESI INT 21H STI MOV AH,31H MOV DX,OFFSET INIT INT 21H END START

;----------------------------------------------------------------------; Title:-Program to Display Clock ; Class : SE-I ROLL No : 2123 Assignment No: 15 ;-----------------------------------------------------------------------.MODEL TINY .stack 100 .CODE ORG 0100 START: JMP INIT SAVE DD ? HR DB 0 MIN DB 0 SEC DB 0 MSG DB ':$' RESI: PUSH AX PUSH BX PUSH CX PUSH DX PUSH SI PUSH DI PUSH CS POP DS MOV AH,02H INT 1AH MOV HR,CH MOV MIN,CL MOV SEC,DH MOV AH,09H LEA DX,MSG INT 21H POP DI POP SI POP DX POP CX POP BX POP AX JMP CS:SAVE INIT: CLI PUSH CS

POP DS MOV AH,35H MOV AL,08H INT 21H MOV WORD PTR CS:SAVE,BX MOV WORD PTR CS:SAVE+2,ES ;STORE ADDDR IN IVT TO SAVE MOV AH,25H MOV AL,08H MOV DX,OFFSET RESI ;LOAD NEW ADDR IN IVT INT 21H STI MOV AH,31H MOV DX,OFFSET INIT INT 21H END START

;STAY RESIDENT

Related Documents

Assignments
November 2019 35
Assignments
June 2020 14
Assignments
November 2019 34
Assignments
November 2019 30
Assignments
May 2020 17
Assignments 09
December 2019 15