Assignment+2 C++

NUST School of Civil and Environmental Engineering

ASSIGNMENT #2

Lecturer Asad Ali Shah

NUST SCEE Course: Fundamentals of Programming Name: Syed Ali Hamza Naqvi Reg#: 2008-NUST-BE-CE-135 Section: B Class: CE- 2 Solve all questions; output should be clear and understandable. Cheating is not allowed if any cheating is found both get zero marks. (20 Marks) Q 1. Write a program that takes input from user in array of size 10. Sort this array in ascending order once the user has finished entering the numbers. (5 Marks) Note: Use only single 1D array and minimum size of array is 10. Sample Output Enter 10 integers for the Array: 5 4 1 0 8 13 11 2 7 9 Sorted Array: 0 1 2 4 5 7

8

9

11

13

Sol# #include #include void main() { int num[10],i,c,j,k,l; cout<<"Enter 10 integers for the array:\n"; for(i=0;i<=9;i++) cin>>num[i]; cout<<endl; for(j=0;j<=9;j++) { for(i=0;i<=9-j;i++) { if(num[i]>num[i+1]) { c=num[i]; num[i]=num[i+1]; num[i+1]=c; } //For checking purposes, I put these 2 loops to see how the program was working// for(k=0;k<=9;k++)

cout<
values for Matrix A for Matrix A [0][0]

Enter Value 5 Value 6 Value 7 Value 8

values for Matrix B for Matrix B [0][0]

for Matrix A [0][1] for Matrix A [1][0] for Matrix A [1][1]

for Matrix B [0][1] for Matrix B [1][0] for Matrix B [1][1]

The Resultant Matrix C is 19 22 43 50

Sol# #include #include void main() { int matA[2][2], matB[2][2],i,j,matC[2][2]; cout<<"Enter Matrix A \n"; for(i=0;i<=1;i++) for(j=0;j<=1;j++) cin>>matA[i][j]; cout<<"\n";

cout<<"Enter Matrix B\n"; for(i=0;i<=1;i++) for(j=0;j<=1;j++) cin>>matB[i][j]; cout<<"\n"; matC[0][0]=matA[0][0]*matB[0][0]+matA[0][1]*matB[1][0]; matC[0][1]=matA[0][0]*matB[0][1]+matA[0][1]*matB[1][1]; matC[1][0]=matA[1][0]*matB[0][0]+matA[1][1]*matB[1][0]; matC[1][1]=matA[1][0]*matB[0][1]+matA[1][1]*matB[1][1]; cout<<"Matric C is \n"; for(i=0;i<=1;i++) { for(j=0;j<=1;j++) cout<<matC[i][j]<<"\t"; cout<<endl; } getch(); }

Q 3. Write program that rotates the matrix 180 degrees. The values for the matrix should be acquired from the user first. Print matrix before and after rotation. (7 Marks) e.g. Matrix is: 1 2 3 4 5 6 7 8 9 Output is after rotation of 180 degree: 9 8 7 6 5 4 3 2 1 Hint: Try revolving the matrix 90 degrees first and then repeat the process once more. Sol# #include #include void main() { int mat[3][3],i,j; cout<<"Enter the numbers \n"; for(i=0;i<=2;i++) for(j=0;j<=2;j++) cin>>mat[i][j]; for(i=0;i<=2;i++) { for(j=0;j<=2;j++) cout<<mat[i][j]<<"\t"; cout<<"\n"; }

//The matrix was possible to be rotated directly 180 degrees, this step is just additional as required...// cout<<"\n Matrix after 90 degrees rotation..\n"; for(i=0;i<=2;i++) { for(j=2;j>=0;j--) cout<<mat[j][i]<<"\t"; cout<<"\n"; } cout<<"\n Matrix after 180 degrees rotation..\n"; for(i=2;i>=0;i--) { for(j=2;j>=0;j--) cout<<mat[i][j]<<"\t"; cout<<"\n"; } getch(); } Q 4. Get input in char array (minimum size is 10). write a program that will search total no. of occurrence of char in array that user enter. The program should not be case sensitive i.e. ‘A’ and ‘a’ are both considered equal. (3 Marks) Sample Output: Enter a String: AsadAli Character to search for: A The no. of occurrence of ‘A’ in the array is:

3

Sol# #include #include void main() { char name[10],a; int i,count; for(i=0;i<=9;i++) name[i]='\0'; cout<<"Enter the string:\n"; cin>>name; cout<<"Enter the character to be searched...\n"; cin>>a; count=0; for(i=0;i<=9;i++) { if(a==name[i]||a-32==name[i]||a+32==name[i]) count++; } cout<<"The occurance of '"<