Aplicacion De Metodos.docx

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PLANTEAMIENTO DEL PROBLEMA Para la siguiente viga calcular a que distancia “x” del primer apoyo se encuentra el momento máximo y calcular el momento en ese punto.

∑ fy=0 Ay + By = 150

∑ MA=0 −10 ( 6 )( 3 )−

30 ( 6 )( 4 ) +6 By=0 2

By=90 Ay =60

CORTE ¿ 10 ≤ X ≤ 6

∑ M =0 M ( X )+ 10 X

( X2 )+5 X ( X )( X3 )−60 X =0 2

3

−5 X M ( X )= −5 X 2+60 X ; 0 ≤ X ≤ 0 6 dM −5 x 2 =0= −10 x+60 dx 2

X = 3.291502622 M(max) = M(3.291502622) = 113.6Nm

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