Answer Scheme Quiz 1
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SCHEME QUIZ 1
1.Assuming total weight 100g, therefore weight NaOH is 52g. no of moles NaOH = 52/40 = 1.3 mol Volume of NaOH = 100g/1.48g/mL = 67.57mL Molarity = 1.3/ ( 67.57/1000 ) = 19.24M @ in 1L solution, concentration of NaOH is (52/100) X 1.48g/mL x 1000mL 40g/mol
=
19.24M
To prepare 0.1M solution : M1V1 = M2V2 V2 = ( 50 x 19.24 ) / 0.1 = 9620mL therefore amount of water required : 9620 – 50 = 9570mL @ 9.57 L
1.Assuming total weight 100g, therefore weight NaOH is 52g. no of moles NaOH = 52/40 = 1.3 mol Volume of NaOH = 100g/1.48g/mL = 67.57mL Molarity = 1.3/ ( 67.57/1000 ) = 19.24M @ in 1L solution, concentration of NaOH is (52/100) X 1.48g/mL x 1000mL 40g/mol
=
19.24M
To prepare 0.1M solution : M1V1 = M2V2 V2 = ( 50 x 19.24 ) / 0.1 = 9620mL therefore amount of water required : 9620 – 50 = 9570mL @ 9.57 L
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