Ans_maths-2008
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SOALAN ULANGKAJI SPM 2008
SPM 2008
Jawap
[ 1449/1 ] [ 1449/2 ]
Mathematics
Soalan
Kertas 1 1. B 2. C 3. D 4. C 5. C 6. B 7. B 8. A 9. A 10. A 11. D 12. B 13. B 14. C 15. A 16. D 17. C 18. A 19. B 20. C
21. B 22. B 23. A 24. D 25. C 26. B 27. C 28. D 29. D 30. C 31. D 32. B 33. C 34. A 35. B 36. A 37. A 38. C 39. D 40. A
an
Ulang
kaji
SOALAN ULANGKAJI SPM 2008
SPM 2008
Jawap
[ 1449/1 ] [ 1449/2 ]
Mathematics
an
Soalan
Ulang
kaji
Kertas 2 Soalan
Jawapan 1 , x=1 3
1
x= -
2
p=1, q=-2 P
Q
3
Soalan
4
11 (a)
58 cm
11 (b)
56 cm²
4 Q
R
P
R
3
i ) true ii) false
4 (b)
Implication 1 : If 3k 2 – 5 > 7 then k > 1 Implication 2 : If k > 1 then 3k 2 – 5 > 7
4 (c)
Conclusion : n² + 3, n = 1,2 ,3,4,…….
12 (a)
5
5
18 cm
4
6
UW = 10 cm
()
6 6 , 0 = tan 1 8 8
4
7 (b)
8 x 7 = 4 14 13 13
k=3
8 (b)
x = 1, y = -1
9 (a)
1 4
9 (b)
y = 3 x-12, x-intercept = 8 2
10 (a)
25 - 15 = 10 s
10 (b)
10 - 0 = -2 ms 1 25 - 30 d = 2 , d = 60 30
10 (c)
x y
-3 8
i) (0,1) ii) (3,-1) iii) (-2,-2)
13 (b)
i) (a) A or (-3,1) i) (b) k = 3
14 (a)
6
5
6
12
2 18
i) 24.5 ii) - 2.3, 2.4
13 (a)
4 7 7 4 28 x + x = 11 10 11 10 55
8 (a)
6
12
Frequency ii)Age 64 unit²
5
Markah
x³ - 15x + 10 = 0 x³ - 15x + 10 + 10x 10 = 0 + 10x + 10 x³ - 5x + 20 = 10x + 10 y = 10x + 10 Draw a graph y = 10x + 10 x = 0.7 , 3.5
= 36.87º or 36º52’ 7 (a)
Jawapan
Section B
12 (c)
4 (a)
tan 0 =
Markah
upper cummulative boundary frequency
5-9
0
9.5
0
10-14
6
14.5
6
15-19
8
19.5
14
20-24
14
24.5
28
25-29
12
29.5
40
30-34
5
34.5
45
35-39
3
39.5
48
14 (b)
Draw a graph 7 plotted points, joining points, A curve line from point (9.5,0) to point (39.5,48)
14 (c)
i) The third quartile = 27.5 ii) 36 participants are 27.5 years old or less.
12
SOALAN ULANGKAJI SPM 2008
SPM
Jawap
[ 1449/1 ] [ 1449/2 ]
Mathematics
2008
Soalan
an
Ulang
kaji
Kertas 2 Soalan 15 (a)
Jawapan B
A/Q
Markah 2 cm U/R
Soalan 16 (a)
HL is the diameter of the parallel of latitude 60º S H ( 60º S, 40º E), L ( 60º S, 140º W) , Longitude of L = 140º W
16 (b)
Shortest distance = ( 180 – 60 – 60 ) x 60 = 3600 n.m
16 (c)
H ( 60º S, 40º E), K ( 60º S, 30º W) Distance = ( 40 + 30 ) x 60 x Cos 60 = 2100 n.m
16 (d)
Average speed = distance/time ,
3 cm D/P
15 (b)
i)
8 cm
T/S
C
W/T
V/U
12 4 cm 7 cm C/D
B/A
3 cm
480 = Distance 5
K/S/P 3 cm L/R/Q
ii)
Distance = 480 x 5 = 2400 n.m T
D
6 cm
C
W
8 cm
Distance = 40 0 = 5 Latitude of M = 60-40 = 20º S
7 cm
3 cm P
Jawapan
S 2 cm K
Markah
12
SPM 2008
Jawap
[ 1449/1 ] [ 1449/2 ]
Mathematics
Soalan
Kertas 1 1. B 2. C 3. D 4. C 5. C 6. B 7. B 8. A 9. A 10. A 11. D 12. B 13. B 14. C 15. A 16. D 17. C 18. A 19. B 20. C
21. B 22. B 23. A 24. D 25. C 26. B 27. C 28. D 29. D 30. C 31. D 32. B 33. C 34. A 35. B 36. A 37. A 38. C 39. D 40. A
an
Ulang
kaji
SOALAN ULANGKAJI SPM 2008
SPM 2008
Jawap
[ 1449/1 ] [ 1449/2 ]
Mathematics
an
Soalan
Ulang
kaji
Kertas 2 Soalan
Jawapan 1 , x=1 3
1
x= -
2
p=1, q=-2 P
Q
3
Soalan
4
11 (a)
58 cm
11 (b)
56 cm²
4 Q
R
P
R
3
i ) true ii) false
4 (b)
Implication 1 : If 3k 2 – 5 > 7 then k > 1 Implication 2 : If k > 1 then 3k 2 – 5 > 7
4 (c)
Conclusion : n² + 3, n = 1,2 ,3,4,…….
12 (a)
5
5
18 cm
4
6
UW = 10 cm
()
6 6 , 0 = tan 1 8 8
4
7 (b)
8 x 7 = 4 14 13 13
k=3
8 (b)
x = 1, y = -1
9 (a)
1 4
9 (b)
y = 3 x-12, x-intercept = 8 2
10 (a)
25 - 15 = 10 s
10 (b)
10 - 0 = -2 ms 1 25 - 30 d = 2 , d = 60 30
10 (c)
x y
-3 8
i) (0,1) ii) (3,-1) iii) (-2,-2)
13 (b)
i) (a) A or (-3,1) i) (b) k = 3
14 (a)
6
5
6
12
2 18
i) 24.5 ii) - 2.3, 2.4
13 (a)
4 7 7 4 28 x + x = 11 10 11 10 55
8 (a)
6
12
Frequency ii)Age 64 unit²
5
Markah
x³ - 15x + 10 = 0 x³ - 15x + 10 + 10x 10 = 0 + 10x + 10 x³ - 5x + 20 = 10x + 10 y = 10x + 10 Draw a graph y = 10x + 10 x = 0.7 , 3.5
= 36.87º or 36º52’ 7 (a)
Jawapan
Section B
12 (c)
4 (a)
tan 0 =
Markah
upper cummulative boundary frequency
5-9
0
9.5
0
10-14
6
14.5
6
15-19
8
19.5
14
20-24
14
24.5
28
25-29
12
29.5
40
30-34
5
34.5
45
35-39
3
39.5
48
14 (b)
Draw a graph 7 plotted points, joining points, A curve line from point (9.5,0) to point (39.5,48)
14 (c)
i) The third quartile = 27.5 ii) 36 participants are 27.5 years old or less.
12
SOALAN ULANGKAJI SPM 2008
SPM
Jawap
[ 1449/1 ] [ 1449/2 ]
Mathematics
2008
Soalan
an
Ulang
kaji
Kertas 2 Soalan 15 (a)
Jawapan B
A/Q
Markah 2 cm U/R
Soalan 16 (a)
HL is the diameter of the parallel of latitude 60º S H ( 60º S, 40º E), L ( 60º S, 140º W) , Longitude of L = 140º W
16 (b)
Shortest distance = ( 180 – 60 – 60 ) x 60 = 3600 n.m
16 (c)
H ( 60º S, 40º E), K ( 60º S, 30º W) Distance = ( 40 + 30 ) x 60 x Cos 60 = 2100 n.m
16 (d)
Average speed = distance/time ,
3 cm D/P
15 (b)
i)
8 cm
T/S
C
W/T
V/U
12 4 cm 7 cm C/D
B/A
3 cm
480 = Distance 5
K/S/P 3 cm L/R/Q
ii)
Distance = 480 x 5 = 2400 n.m T
D
6 cm
C
W
8 cm
Distance = 40 0 = 5 Latitude of M = 60-40 = 20º S
7 cm
3 cm P
Jawapan
S 2 cm K
Markah
12
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