Andreas Pranoto 2001606415.docx

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Andreas Pranoto 2001606415 Asumsi Kolom & Balok 1. Kolom  Tributari Area: = (X) x (Y) 6

6

6

6

6

6

6

6

= (2 + 2 + 2) x (2 + 2 + 2 + 2 + 2) = 135 m2 

P kolom Jumlah lantai x Tributari Area x asumsi 5 x 135 x 1500 kg/m2 = 1.012.500 kg



Aperlu =



P kolom (kg) 0,3 x f′ c x10

1.012.500

= 0,3 x 35 x 10 = 9.642,86 cm2

b = √9.642,85 = 98,2 cm Dimensi kolom = 100 x 100 cm

2. Balok Utama L

600



Ukuran b = 12 =



Ukuran h = 2 x 50 cm = 25 cm

1

12

= 50 cm

Dimensi balok = 25 x 50 cm

ASUMSI BEBAN 1. Beban mati (0,12x2500) + (0,05x2200) + 25 = 4,35 KN/m2 2. Beban hidup 0,75 x 200 = 1,5 Kn/m2

ASUMPTION a. Membuat material 

Concrete grade f’c 30 MPa



Longitudinal reinforcement fy 400 MPa



Shear reinforcement fy = 240 MPa

b. Membuat kolom

c. Membuat balok

d. Membuat pelat

e. Pembebanan ( load pattern)

f. Pembebanan kombinasi 

Kombinasi 1 (1,4 DL)



Kombinasi 2 ( 1,2 DL + 1,4 LL)

g. Input dinding

h. Run

i. Moment

j. Shear

k. Axial

i.

Hasil akhir

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