Analisis Real 1_03
This document was uploaded by user and they confirmed that they have the permission to share it. If you are author or own the copyright of this book, please report to us by using this DMCA report form. Report DMCA
Overview
Download & View Analisis Real 1_03 as PDF for free.
More details
- Words: 168
- Pages: 8
Nama : Nur Hamidah (107017002896) Ihyani Toyibah (107017000770) Siti Khodroh T (107017001101) Lema 1.2.1
1. Misal
2. Misal
3. Misal
4. Misal
5. Misal
Lema 1.2.2 jika Contoh-contoh : 1.
2.
3.
4.
5.
Lema 1.2.3
Teorema 1.4.1 (sifat Archimedes) dan 1. Misal
Terdapat
,
,
Sehingga 4.3 > 2
terdapat
, sehingga
12 > 2 (terbukti) 2. Misal
,
Terdapat
,
Sehingga 2.5 > 3 10 > 3 (terbukti) 3. Misal
,
Terdapat
,
Sehingga 7.1 > 4 7 > 4 (terbukti) 4. Misal
,
Terdapat
,
Sehingga 1.9 > 8 9 > 8 (terbukti) 5. Misal
,
Terdapat
,
Sehingga 3.3 > 7 9 > 7 (terbukti)
Teorema 1.4.2
1.
Misal
2.
Misal
3.
Misal
4.
Misal
5.
Misal
Teorema 1.4.3 1. Misal a = 2 n=3
= 1,25992105 terbukti 2. Misal a = 5 n=3
= 1,709975 terbukti 3. Misal a = 7 n=2
= 1,912931 terbukti 4. Misal a = 11 n=2
= 3,31662479 terbukti 5. Misal a = 4 n=3
= 1,587401052 terbukti
1. Misal
2. Misal
3. Misal
4. Misal
5. Misal
Lema 1.2.2 jika Contoh-contoh : 1.
2.
3.
4.
5.
Lema 1.2.3
Teorema 1.4.1 (sifat Archimedes) dan 1. Misal
Terdapat
,
,
Sehingga 4.3 > 2
terdapat
, sehingga
12 > 2 (terbukti) 2. Misal
,
Terdapat
,
Sehingga 2.5 > 3 10 > 3 (terbukti) 3. Misal
,
Terdapat
,
Sehingga 7.1 > 4 7 > 4 (terbukti) 4. Misal
,
Terdapat
,
Sehingga 1.9 > 8 9 > 8 (terbukti) 5. Misal
,
Terdapat
,
Sehingga 3.3 > 7 9 > 7 (terbukti)
Teorema 1.4.2
1.
Misal
2.
Misal
3.
Misal
4.
Misal
5.
Misal
Teorema 1.4.3 1. Misal a = 2 n=3
= 1,25992105 terbukti 2. Misal a = 5 n=3
= 1,709975 terbukti 3. Misal a = 7 n=2
= 1,912931 terbukti 4. Misal a = 11 n=2
= 3,31662479 terbukti 5. Misal a = 4 n=3
= 1,587401052 terbukti
Related Documents
Analisis Real
July 2020 6
Analisis Real Teoria
June 2020 8
Tugas Analisis Real
June 2020 4
Analisis Real 1_03
June 2020 1
Tugas 1 (analisis Real)
June 2020 9