Algebra Test No. 1

1.

Solve any three of the following: i. Find the binary equivalent of 2410. ii. Find the decimal equivalent of 10101012. iii. What is the greatest and smallest 3 – bit binary numbers? iv. Subtract: 10012 – 1012. 2. Solve any four of the following: i. Find the difference between the greatest and the smallest 5 – bit binary numbers. ii. Find the sum of the greatest 4 – bit and 3 – bit binary numbers. iii. Add and verify your answer in the decimal number system: 10012 + 101012. iv. Solve and verify your answer in the decimal number system: 1010102 – 101012. v. Solve: 1012 – 10012 + 10102. 3. Solve any four of the following: i. Solve and answer the following: a. ii. iii. iv. v.

1010012 =

10

b. 10510 = 2 Add the following numbers: 101012 + 10012. Solve: 11100112 + 1010 2 – 11011012. Solve: 101012 – 10012. Solve by converting the following numbers to binary number system. 25110 – 13510 + 21210.

1.

Solve any three of the following: v. Find the binary equivalent of 2410. vi. Find the decimal equivalent of 10101012. vii. What is the greatest and smallest 3 – bit binary numbers? viii. Subtract: 10012 – 1012. 2. Solve any four of the following: i. Find the difference between the greatest and the smallest 5 – bit binary numbers. ii. Find the sum of the greatest 4 – bit and 3 – bit binary numbers. iii. Add and verify your answer in the decimal number system: 10012 + 101012. iv. Solve and verify your answer in the decimal number system: 1010102 – 101012. v. Solve: 1012 – 10012 + 10102. 3. Solve any four of the following: i. Solve and answer the following: a. ii. iii. iv. v.

1010012 =

10

b. 10510 = 2 Add the following numbers: 101012 + 10012. Solve: 11100112 + 1010 2 – 11011012. Solve: 101012 – 10012. Solve by converting the following numbers to binary number system. 25110 – 13510 + 21210.