:
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Prof .M.JAD
M
3
(AB)
AH AC BN BA
;
.H .
(AC)
AB HM BM BC
.
(AC)
1
[ DC ] [ AB ] . DC
2
.
IF = 3ID (BH)
ABC
[ AB ]
M
(AC) S
(KM)
(AC) (AB) (CE)
1
AM AK = AB AH AK × KS = AH × KM
IB 1 = IC 3 [ ID )
:
:
2 F 3 (
( DB ) // ( FC )
)
:
:
1
F
( M ≠ A; M ≠ B ) (AC) B
= 6cm AB = 2cm : I ( BC ) ( AD )
3
:5 K
ABCD
.
(MN)//(AH)
( H ∈ ( AC ))
:1
(BF)
F E
( :2
ABC (BC) // (EF): B .G (AC)
AF AE AE AC AB AB AC 2 = AF × AG
AC AG :
,C
.D (AB) .(BC)//(DG) :
2
[ ME ]
1
[CN ] [ BM ]
2 :3 ABC
[ NE ]
.AMN 119 117
28 27 26 14 13 9
:
AM AC www.mathchalabi.c.la
C M A N
AE AN
.(BC)
.
AN AB
(EF)
BC=5cm B ,BM=2,5cm (BC) B BA=2BN (AB)
1 2
AF AM :4 ABC N
3 M
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Prof .M.JAD