2.3 Perhitungan Tulangan Pelat Lantai Diameter Tulangan
= 10 mm
Jarak antar tulangan sumbu x = 200 mm Jarak antar tulangan sumbu y = 200 mm Jumlah tulangan sumbu x area 1 = 98 tulangan x 2 tulangan = 196 Jumlah tulangan sumbu x area 2 = 36 tulangan x 2 tulangan = 72 Jumlah tulangan sumbu y area 1 = 21 tulangan x 4 tulangan = 84 Jumlah tulangan sumbu y area 2 = 21 tulangan x 2 tulangan = 42 Jumlah tulangan sumbu y area 3 = 71 tulangan x 6 tulangan = 246
2.4.1 Arah Memendek (y) 1. Tulangan Atas Lapis 1 ( Area 1 )
d sengkang = 10 mm
= Jarak as ke as – Lebar balok + 2(selimut beton + dsengkang + rtulangan balok) + 1
(2(6𝐷 + 4 𝜋(𝐷𝑝𝑒𝑛 + 2𝑑𝑠𝑒𝑛𝑔𝑘𝑎𝑛𝑔) + (80 − 𝐷𝑝𝑒𝑛 − 2𝑑𝑠𝑒𝑛𝑘𝑎𝑛𝑔) + 3 8
𝜋(𝐷𝑝𝑒𝑛 + 2𝑑𝑠𝑒𝑛𝑔𝑘𝑎𝑛𝑔)) 1
= 4000 − 350 + 2(40 + 10 + 11) + (2(60 + 4 𝜋(38,1 + 20) + 3
(80 − 38,1 − 20) + 𝜋(38,1 + 20)) 8 = 3650 + 122 + 391,8425 = 4163,8425 mm ≈ 4164 mm = 4,164 m
2. Tulangan Atas Lapis 1 ( Area 1 )
d sengkang = 10 mm
= Jarak as ke as – Lebar balok + 2(selimut beton + dsengkang + 3
rtulangan balok) + (2(6𝐷 + 8 𝜋(𝐷𝑝𝑒𝑛 + 2𝑑𝑠𝑒𝑛𝑔𝑘𝑎𝑛𝑔)) = 4000 − 350 + 2(40 + 10 + 11) + 2(60 + 68,4) = 4028,8 𝑚𝑚 ≈ 4028 𝑚𝑚 = 4,028 𝑚
3. Tulangan Atas Lapis 1 ( Area 1 )
diameter tulangan = 10 mm
diameter tulangan = 10 mm
= Jarak as ke as – Lebar balok + 2(selimut beton + dsengkang + 3
rtulangan balok) + (2(6𝐷 + 8 𝜋(𝐷𝑝𝑒𝑛 + 2𝑑𝑠𝑒𝑛𝑔𝑘𝑎𝑛𝑔)) + 40D = 8000 − 350 + 2(40 + 10 + 11) + 2(60 + 68,4) + 400 = 15428.8 𝑚𝑚 ≈ 15429 𝑚𝑚 = 15,429 𝑚 a. Tulangan a = 12 𝑚𝑒𝑡𝑒𝑟 b. Tulangan b = 3,429 𝑚𝑒𝑡𝑒𝑟 4. Tulangan Bawah Lapis 1 ( Area 1 )
diameter tulangan = 10 mm diameter tulangan = 10 mm
= Jarak as ke as – Lebar balok + 2(selimut beton + dsengkang + rtulangan balok) + 1
(2(6𝐷 + 4 𝜋(𝐷𝑝𝑒𝑛 + 2𝑑𝑠𝑒𝑛𝑔𝑘𝑎𝑛𝑔) + (110 − 𝐷𝑝𝑒𝑛 − 2𝑑𝑠𝑒𝑛𝑘𝑎𝑛𝑔) + 3 8
𝜋(𝐷𝑝𝑒𝑛 + 2𝑑𝑠𝑒𝑛𝑔𝑘𝑎𝑛𝑔)) + 40D 1
= 15000 − 350 + 2(40 + 10 + 11) + (2(60 + 4 𝜋(38,1 + 20) + 3
(110 − 38,1 − 20) + 𝜋(38,1 + 20)) + 400 8
= 14772 + 2(60 + 45,6 + 51,9 + 68,4) + 400 = 15623,8 mm ≈ 15624 mm = 15,624 m a. Tulangan a = 11 𝑚𝑒𝑡𝑒𝑟 b. Tulangan b = 4,624 𝑚𝑒𝑡𝑒𝑟 5. Tulangan Atas Lapis 1 ( Area 3 )
diameter tulangan = 10 mm
diameter tulangan = 10 mm
diameter tulangan = 10 mm
= Jarak as ke as – Lebar balok + 2(selimut beton + dsengkang + 3
rtulangan balok) + (2(6𝐷 + 8 𝜋(𝐷𝑝𝑒𝑛 + 2𝑑𝑠𝑒𝑛𝑔𝑘𝑎𝑛𝑔)) + ( 2 x 40D ) = 30000 − 350 + 2(40 + 10 + 11) + 2(60 + 68,4) + 800 = 30828,8 𝑚𝑚 ≈ 30829 𝑚𝑚 = 30,829 𝑚 a. Tulangan a = 12 𝑚𝑒𝑡𝑒𝑟 b. Tulangan b = 12 𝑚𝑒𝑡𝑒𝑟 c. Tulangan c = 6,829 𝑚𝑒𝑡𝑒𝑟
6. Tulangan Bawah Lapis 1 ( Area 3 )
diameter tulangan = 10 mm diameter tulangan = 10 mm diameter tulangan = 10 mm
= Jarak as ke as – Lebar balok + 2(selimut beton + dsengkang + rtulangan balok) + 1
(2(6𝐷 + 𝜋(𝐷𝑝𝑒𝑛 + 2𝑑𝑠𝑒𝑛𝑔𝑘𝑎𝑛𝑔) + (110 − 𝐷𝑝𝑒𝑛 − 2𝑑𝑠𝑒𝑛𝑘𝑎𝑛𝑔) + 4
3 8
𝜋(𝐷𝑝𝑒𝑛 + 2𝑑𝑠𝑒𝑛𝑔𝑘𝑎𝑛𝑔)) + ( 2 x 40D ) 1
= 30000 − 350 + 2(40 + 10 + 11) + (2(60 + 4 𝜋(38,1 + 20) + 3
(110 − 38,1 − 20) + 𝜋(38,1 + 20)) + 800 8 = 29772 + 2(60 + 45,6 + 51,9 + 68,4) + 800 = 31023,8 mm ≈ 31024 mm = 31,024 m a. Tulangan a = 11 𝑚𝑒𝑡𝑒𝑟 b. Tulangan b = 12 𝑚𝑒𝑡𝑒𝑟 c. Tulangan c = 8,024 𝑚𝑒𝑡𝑒𝑟
2.4.2 Arah Memanjang (x) 1. Tulangan Bawah Lapis 2 ( Area 1 )
d sengkang = 10 mm
b
a
d sengkang = 10 mm
a. Tulangan a = 11 𝑚𝑒𝑡𝑒𝑟 b. Tulangan b = 12 meter
2. Tulangan Atas Lapis 2 ( Area 1 )
b
d sengkang = 10 mm a
d sengkang = 10 mm
a. Tulangan a = 12 meter b. Tulangan b = 12 meter
3.
Tulangan Bawah Lapis 2 ( Area 2 )
b
d sengkang = 10 mm a
d sengkang = 10 mm
a. Tulangan a = 11 𝑚𝑒𝑡𝑒𝑟 b. Tulangan b = 12 meter
4. Tulangan Atas Lapis 2 ( Area 2 )
b
d sengkang = 10 mm a
d sengkang = 10 mm
a. Tulangan a = 12 meter b. Tulangan b = 12 meter
Tabel Bar Bending Scheduler Tulangan Pelat Lantai
No. Kode
Tipe
PELAT LANTAI Diameter Total Panjang Total Panjang Jumlah (mm) Teoritis (m) (m)
1
016
aba
8
6,533
166
1084,478
2
017
a
8
6,467
166
1073,522
ab
8
7,584
510
3867,84
c
8
11,69
510
5961,9
3
ba
8
7,584
510
3867,84
4
ab
8
7,538
510
3844,38
c
8
11,69
510
5961,9
ba
8
7,583
510
3867,33
3 018
019 4
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